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a) \(\dfrac{-7}{20}=\dfrac{1}{5}.\dfrac{-7}{4}\) b) \(\dfrac{-7}{20}=\dfrac{-7}{40}:\dfrac{1}{2}\) c) \(\dfrac{-7}{20}=\dfrac{2}{5}+\dfrac{-3}{4}\) d) \(\dfrac{-7}{20}=\dfrac{-1}{5}+\dfrac{-3}{20}\)
a)\(\dfrac{-7}{20}=\dfrac{-7}{10}\times\dfrac{1}{2}\)
b)\(\dfrac{-7}{20}=\dfrac{-7}{40}\times\dfrac{1}{2}\)
c)\(\dfrac{-7}{20}=\dfrac{7}{20}+\dfrac{-7}{10}\)
d)\(\dfrac{-7}{20}=\dfrac{-1}{5}+\dfrac{-3}{20}\)
A)\(-\frac{7}{20}=\frac{1}{10}.\left(-\frac{7}{2}\right)\)
B)
a) \(\frac{7}{2}.\frac{-1}{10}\)
b)\(7:\left(-20\right)\)
c)\(\frac{7}{20}+\frac{-7}{10}\)
d)\(\frac{-1}{5}+\frac{-3}{20}\)
Câu 1.
$\frac{1}{15}-\frac{9}{15}=\frac{-8}{15}$
$\frac{2}{15}-\frac{10}{15}=\frac{-8}{15}$
$\frac{3}{15}-\frac{11}{15}=\frac{-8}{15}$
Câu 2:
$\frac{-9}{15}+\frac{1}{15}=\frac{-8}{15}$
$\frac{-10}{15}+\frac{2}{15}=\frac{-8}{15}$
$\frac{-11}{15}+\frac{3}{15}=\frac{-8}{15}$
a, \(\dfrac{7}{20}\) = \(\dfrac{8}{20}\) + (\(\dfrac{-1}{20}\))
b, \(\dfrac{7}{20}\) = \(\dfrac{1}{4}\) + \(\dfrac{1}{10}\)