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#include <bits/stdc++.h>
using namespace std;
long long a,b;
int main()
{
cin>>a>>b;
cout<<a*b<<endl;
cout<<fixed<<setprecision(2)<<(a*1.0)/(b*1.0);
return 0;
}

Câu 1:
uses crt;
var a,b:integer;
begin
clrscr;
readln(a,b);
write(a+b);
readln;
end.
Câu 2:
uses crt;
var a,b,c:integer;
begin
clrscr;
readln(a,b,c);
writeln(a+b-c);
readln;
end.
Câu 3:
uses crt;
var a,b:integer;
begin
clrscr;
readln(a,b);
writeln(a-b);
readln;
end.
Câu 4:
uses crt;
var x,y,z:integer;
begin
clrscr;
readln(x,y,z);
writeln((x+y)*z);
readln;
end.

1:
#include <bits/stdc++.h>
using namespace std;
double a;
int main()
{
cin>>a;
cout<<a*a;
return 0;
}

Vd:
#include <bits/stdc++.h>
using namespace std;
long double x,y;
int main()
{
cin>>x>>y;
cout<<fixed<<setprecision(2)<<x+y;
return 0;
}

program TongN;
var
n, i, tong: integer;
begin
tong := 0;
writeln('Nhap so nguyen duong N: ');
readln(n);
i := 0;
while i < n do
begin
i := i + 1;
tong := tong + i;
end;
writeln('Tong cac so tu 1 den ', n, ' la ', tong);
readln;
end.

1:
uses crt;
var n,i,t:integer;
begin
clrscr;
readln(n);
t:=0;
for i:=1 to n do
t:=t+i*i;
write(t);
readln;
end.
2
program bt2;
var i,n,t:integer;
begin
readln(n);
s:=0;
for i:=1 to n do
if i mod 2 = 1 then s:=s+i;
readln;
end.

Câu 1:
program Tinhtong:
var
n, i, sum: integer;
begin
write('Nhap n: ');
readln(n);
sum := 0;
for i := 2 to n do
begin
if i mod 2 = 0 then
begin
sum := sum + i;
end;
end;
writeln('Tong cac so chan tu 2 toi ', n, ' la ', sum);
readln;
end.
Câu 2:
program Tinhtong:
var
n, i, sum: integer;
begin
write('Nhap n: ');
readln(n);
sum := 0;
for i := 1 to n do
begin
if i mod 2 = 1 then
begin
sum := sum + i;
end;
end;
writeln('Tong cac so le tu 1 toi ', n, ' la ', sum);
readln;
end.

Câu 6:
uses crt;
var n,i:integer;
begin
clrscr;
readln(n);
for i:=1 to n do
if n mod i=0 then write(i:4);
readln;
end.
5:
uses crt;
var n,i,dem:integer;
begin
clrscr;
readln(n);
dem:=0;
for i:=0 to n do
if i mod 2=1 then
begin
write(i:4);
dem:=dem+1;
end;
writeln;
writeln(dem);
readln;
end.
Program tinhtong;
uses crt;
var a,b: real;
begin
clrscr;
write('nhap so a ='); readln(a);
write('nhap so b ='); readln(b);
writeln('tong cua hai so a va b = ',a+b :4:2);
readln;
end.