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A = 10 + 11 - 12 - 13 + 14 + 15 - 16 - 17 + ........ + 2011 - 2012 - 2013 + 2014
A = 10 + (11 - 12 -13 + 14) + (15 - 16 - 17 + 18) +...... + (2011 - 2012 - 2013 + 2014)
A = 10 + 0 + 0 + ... + 0
A = 10
Vì \(B=\frac{2014^{11}+2}{2014^{12}+2}<1\)
\(\Rightarrow B=\frac{2014^{11}+2}{2014^{12}+2}<\frac{2014^{11}+2+4026}{2014^{12}+2+4026}=\frac{2014^{11}+4028}{2014^{12}+4028}=\frac{2014.\left(2014^{10}+2\right)}{2014\left(2014^{11}+2\right)}=\frac{2014^{10}+2}{2014^{11}+2}=A\)
Vậy B<A hay A<B
ta chứng minh bài toán phụ:
nếu ta có b<d \(\frac{a}{b}\)>\(\frac{c}{d}\) thì ad>bc
dễ thây \(\frac{ad}{bd}>\frac{cb}{bd}\)
=> ad>bd
áp dụng:
dat 2014=a ta co
\(A=\frac{a^{10}+2}{a^{11+2}}\)
\(B=\frac{a^{11}+2}{a^{12}+2}\)
ta có
\(A=\frac{a^{10}+2.a^{12}+2}{a^{11}+2.a^{12}+2}\)
\(B=\frac{a^{11}+2.a^{11}+2}{a^{12}+2.a^{11}+2}\)=\(\frac{a^{10}+2a^{12}+2}{a^{12}+2a^{11}+2}\)
=> A=B
mk hok chắc đâu nha
1) Ta có : 1/2x+150%x=2014 suy ra (1/2+150/100)*x=2014 =(0,5+1,5)*x=2014=2*x=2014
Suy ra x=2014/2=1007
2)
1/2x+1/8x=3/4
=(1/2+1/8)x=3/4
=(0,5+0,125)x=0,75
=0,625x=0,75 suy ra x=1,2
Nho k nha
a)\(\frac{1}{2}x+150\text{%}.x=2014\)
\(\frac{1}{2}x+\frac{3}{2}x=2014\)
\(x.\left(\frac{1}{2}+\frac{3}{2}\right)=2014\)
\(x.2=2014\)
\(x=2014:2=1007\)
b) \(\frac{1}{2}x+\frac{1}{8}x=\frac{3}{4}\)
\(x.\left(\frac{1}{2}+\frac{1}{8}\right)=\frac{3}{4}\)
\(x.\frac{5}{8}=\frac{3}{4}\)
\(x=\frac{3}{4}:\frac{5}{8}=\frac{6}{5}\)
Ta có: \(\frac{x+1}{2014}+\frac{x+2}{2013}+\frac{x+3}{2012}=\frac{x+4}{2011}+\frac{x+5}{2010}+\frac{x+6}{2009}\)
\(\Rightarrow\frac{x+1}{2014}+1+\frac{x+2}{2013}+1+\frac{x+3}{2012}+1=\frac{x+4}{2011}+1+\frac{x+5}{2010}+1+\frac{x+6}{2009}+1\)
\(\Rightarrow\frac{2015+x}{2014}+\frac{2015+x}{2013}+\frac{2015+x}{2012}=\frac{2015+x}{2011}+\frac{2015+x}{2010}+\frac{2015+x}{2009}\)
\(\Rightarrow\left(2015+x\right)\left(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}-\frac{1}{2011}-\frac{1}{2010}-\frac{1}{2009}\right)=0\)
=> 2015 + x = 0
=> x = -2015
2x + 7=0-135
2x + 7=-135
2x=-135-7
2x=-142
x=-142:2
x=-71
1/2x + 3/2x=2014
x(1/2+3/2)=2014
2x=2014
x=2014:2
x=1007
150%=\(\frac{150}{100}=\frac{3}{2}\)
\(\frac{1}{2}x+\frac{3}{2}x=2014\)
\(=>x.\left(\frac{1}{2}+\frac{3}{2}\right)=2014\)
\(=>x.2=2014\)
\(x=2014:2\)
vậy x= 1007
CHÚC BẠN HỌC GIỎI
\(\frac{1}{2}x+150\%x=2014\)
\(\frac{1}{2}x+\frac{3}{2}x=2014\)
\(\left(\frac{1}{2}+\frac{3}{2}\right).x=2014\)
\(2.x=2014\)
\(\Rightarrow x=1007\)
\(\frac{1}{2}x+150\%x=2014\)
=>\(\frac{1}{2}x+\frac{3}{2}x=2014\)
=>x(\(\frac{1}{2}+\frac{3}{2}\))=2014
=>x.2=2014
=>x=1007
vậy x=1007