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a) x = 4
b) x = -8
c) | x | - 9 = -2 + 17
| x | = 15 + 9
| x | = 24
x = 24 hoặc x = -24
d) |x – 9| = -2 + 17
|x – 9| = 15
x – 9 = 15 hoặc x – 9 = -15
x = 24 hoặc x = -6
\(a,2-x=17-\left(-5\right)\)
\(\Rightarrow2-x=17+5\)
\(\Rightarrow2-x=22\)
\(\Rightarrow x=2-22\)
\(\Rightarrow x=-20\)
Vay...
\(b,11-\left(15+11\right)=x-\left(25-9\right)\)
\(\Rightarrow11-26=x-16\)
\(\Rightarrow-15=x-16\)
\(\Rightarrow-15+16=x\)
\(\Rightarrow x=1\)
a) 3x – 15 = 25 – 5x
=> 3x + 5x = 25 + 15
=> 8x = 40
=> x = 5
b) 3x - 17 = 2x – 7
=> 3x - 2x = -7 + 17
=> x = 10
c) 2x – 17 = – (3x – 18)
=> 2x - 17 = -3x + 18
=> 2x + 3x = 18 + 17
=> 5x = 35
=> x = 7
d) 3x – 14 = 2(x – 9) + 1
=> 3x - 14 = 2x - 18 + 1
=> 3x - 2x = -18 + 1 + 14
=> x = -3
f) (x – 5)2 = 9
\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
a) Ta có: \(3x-15=25-5x\)
\(\Leftrightarrow3x-15-25+5x=0\)
\(\Leftrightarrow8x-40=0\)
\(\Leftrightarrow8x=40\)
hay x=5
Vậy: x=5
b) Ta có: \(3x-17=2x-7\)
\(\Leftrightarrow3x-17-2x+7=0\)
\(\Leftrightarrow x-10=0\)
hay x=10
Vậy: x=10
c) Ta có: \(2x-17=-\left(3x-18\right)\)
\(\Leftrightarrow2x-17=-3x+18\)
\(\Leftrightarrow2x-17+3x-18=0\)
\(\Leftrightarrow5x-35=0\)
\(\Leftrightarrow5x=35\)
hay x=7
Vậy: x=7
d) Ta có: \(3x-14=2\left(x-9\right)+1\)
\(\Leftrightarrow3x-14=2x-18+1\)
\(\Leftrightarrow3x-14-2x+18-1=0\)
\(\Leftrightarrow x+3=0\)
\(\Leftrightarrow x=-3\)
Vậy: x=-3
f) Ta có: \(\left(x-5\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{2;8\right\}\)
a) x + 2 = - 9 - 11
x + 2 = - 20
x = - 20 - 2
x = - 22
Vậy x = - 22
b) x - 2 = - 6 + 17
x - 2 = 11
x = 11 + 2
x = 13
Vậy x = 13
a)11-(15+11)=x-(25-9)
11-26=x-16
-15=x-16
x=-15+16
x=1
vậy x=1
b)2-x=17-(-5)
2-x=22
x=2-22
x=-24
vậy x=-24
c)lxl-7=9
lxl=9+7
lxl=16
=>x=+-16
vậy x=+-16
d)3x-40=5x+32
3x-5x=40+32
(3-5)x=72
-2x=72
x=72:(-2)
x=-36
vậy x=-36
a)-7129+1478+7129+(-1429)
=(-7129+7129)+(1478-1429)
=0+(-1)
=-1
b)\(|-5|.\left(-7\right)+4.\left(-9\right)
\)
=5.(-7)+(-36)
=-35+(-36)
=-71
c)\(|-15+21|-|4-11|\)
=\(|6|-|-7|\)
=\(6-7\)
=-1
d)1-2+3-4+5-6+...+2009-2010+2011
xét dãy số có:
số số hạng là: (2011-1):1+1=2011(số hạng)
vì 2011:2=1005(dư 1) nên ta nhóm như sau:
=(1-2)+(3-4)+(5-6)+...+(2009-2010)+2011
=-1.1005+2011
=-1005+2011
=1006
e)5+(-8).3
=5+(-24)
=-19
f)4+(-5).2
=4+(-10)
=-6
h)40-(-7).2
=40-(-14)
=40+14
=54
k)1-2-3+4+5-6-7+8+...+801-802-803+804
Xét dãy số có:
số số hạng là: (804-1):1+1=804(số hạng)
vì 804:4=201 nên ta nhóm như sau:
=(1-2-3+4)+(5-6-7+8)+...(801-802-803+804)
=0+0+...+0
=0
bài 2:
a)x+5=-2+11
x+5=9
x=9-5
x=4
vậy...
b)-3x=-5+29
-3x=24
x=24:(-3)
x=-8
vậy...
c)\(|x|-9=-2+17\)
\(|x|-9=15
\)
\(|x|=15+9\)
\(|x|=24\)
\(\Rightarrow\left\{{}\begin{matrix}x=24\\x=-24\end{matrix}\right.\)
Vậy x\(\in\)\(\left\{24;-24\right\}\)
d)\(|x-9|=-2+17\)
\(|x-9|=15\)
\(\Rightarrow\left\{{}\begin{matrix}x-9=15\\x-9=-15\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=15+9\\x=-15+9\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=24\\x=-6\end{matrix}\right.\)
Vậy x\(\in\left\{24;-6\right\}\)
e)x-2=-6+17
x-2=11
x=11+2
x=13
vậy...
f)x+2=-9-11
x+2=-20
x=-20-2
x=-24
vậy...
g)2x+5=x-1
2x-x=-1-5
x=-6
vậy...
h)\(|x-4|=|-81|\)
\(|x-4|=81\)
\(\Rightarrow\left\{{}\begin{matrix}x-4=81\\x-4=-81\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=81+4\\x=-81+4\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=85\\x=-77\end{matrix}\right.\)
vậy \(x\in\left\{85;-77\right\}\)
k)x+9=2-17
x+9=-15
x=-15-9
x=-24
vậy...
m)x-17=(-11).(-5)
x-17=55
x=55-17
x=38
vậy...
n)\(|x-5|=\left(-4\right).2
\)
\(|x-5|=-8\) (loại)
vậy \(x\in\left\{\varnothing\right\}\)
Bài 1. Tính:
a) -7129 + 1478 + 7129 + (-1479)
= -7129 + 7129 + 1478 + ( -1479 )
= 0 + (-1) = -1
b) | -5 | . (-7) + 4 . (-9)
= 5 . (-7) + (-36)
= (-35) + (-36) = -71
c) | -15 + 21| – | 4 – 11|
= | 6 | - | -7| = 6 - 7 = -1
e) 5 + (-8).3
= 5 + (-24) = -19
f) 4 + (-5)2
= 4 + (-10) = -6
g) 49 + (11 – 25)
= 49 + (-14) = 35
h) 40 – (-7)2
= 40 - (-14) = 54
Bài 2. Tìm x ∈ Z, biết:
a) x + 5 = -2 + 11
x + 5 = 9
x = 9 - 5
x = 4
Vậy x = 4
b) -3x = -5 + 29
-3x = 24
x = 24 : (-3)
x = -8
Vậy x = -8
c) | x | - 9 = -2 + 17
| x | - 9 = 15
| x | = 15 + 9
| x | = 24
=> [\(\begin{matrix} x=24 \\ x=-24 \end{matrix}\)
Vậy..
d) | x – 9 | = -2 + 17
| x - 9 | = 15
=>[ \(\begin{matrix} x-9=15<=>x=24\\ x-9=-15<=>x=-6 \end{matrix}\)
Vậy..
e) x – 2 = -6 + 17
x - 2 = 11
x = 11 + 2
x = 13
Vậy x =13
f) x + 2 = -9 – 11
x + 2 = -20
x = -20-2
x = -22
Vậy x =-22
g) 2x + 5 = x – 1
2x - x = -1 -5
x = -6
Vậy x = -6
h) |x – 4| = | -81 |
| x - 4 | = 81
=>[\(\begin{matrix} x-4=81<=>x=85\\ x-4=-81<=>x =-85 \end{matrix}\)
Vậy..
k) x + 9 = 2 – 17
x + 9 = -15
x = -15 - 9
x = -24
Vậy x = -24
m) x - 17 = (-11) . (-5)
x - 17 = 55
x = 55 + 17
x = 72
Vậy x = 72
Bài 1:
a)=(-7129+7129)+(1478-1479)
=0+(-1)
=-1
b)=5.(-7)+(-36)
=-35-36
=-71
c)=\(|6|-|-3|\)
=6-3
=3
d)Xét dãy số có:
Số số hạng là: (2011-1):1+1=2011(số hạng)
Vì 2011:2=1005(dư 1) nên ta nhóm như sau:
=(1-2)+(3-4)+(5-6)+...+(2007-2008)+(2009-2010)+2011
=-1+(-1)+(-1)+...+(-1)+(-1)+2011
=-1.1005+2011
=-1005+2011
=1006
e)=5+(-24)
=5-24
=-19
f)=4+(-10)
=4-10
=-6
g)=49+(-14)
=49-14
=35
k)Xét dãy số có:
Số số hạng là: (804-1):1+1=804(số hạng)
Vì 804:4=201 nên ta nhóm như sau:
=(1-2-3+4)+(5-6-7+8)+...+(801-802-803+804)
=0+0+...+0
=0
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
a, x+5=-2+11
=> x + 5 = 9
=> x = 4
b, -3x=-5+29
=> -3x = 24
=> x = -8
c,|x-9|=-2+17
=> |x-9| = 15
=> x - 9 = 15 hoặc x - 9 = -15
=> x = 24 hoặc x = -6
d, |x|-9=-2+17
=> |x| - 9 = 15
=> |x| = 24
=> x = 24 hoặc x = -24
e,|x+19|+|x+5|+|x+2011|=4x
|x + 19| > 0 ; |X + 5| > 0 ; |x + 2011| > 0
=> |x + 19| + |X + 5| + | x + 2011| > 0
=> 4x > 0
=> x > 0
=> x + 19 + x + 5 + x + 2011 = 4x
=> 3x + 2035 = 4x
=> x = 2035
dễ mà bro
?