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5 tháng 7 2023
1: =1/8*9/4=9/32
2: =8/27*243/32=9/4
3: =(5/4*4/5)^5*(4/5)^2=16/25
4: \(=\left(-\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^2\cdot\left(\dfrac{6}{5}\right)^2=\dfrac{36}{25}\)
5: \(=\left(-\dfrac{4}{3}\right)^3\cdot\left(\dfrac{3}{4}\right)^{10}=\left(-1\right)\left(\dfrac{3}{4}\right)^7=-\left(\dfrac{3}{4}\right)^7\)
6: \(=\left(\dfrac{1}{3}\cdot\dfrac{-9}{2}\right)^4\left(-\dfrac{9}{2}\right)^2=\left(-\dfrac{3}{2}\right)^4\cdot\dfrac{81}{4}=\dfrac{9}{4}\cdot\dfrac{81}{4}=\dfrac{729}{16}\)
8: =(0,2*5)^4*5^2=25
10: =-0,5^5*2^10
=-0,5^5*2^5*2^5
=-32
13: =(0,5*2)^2*2^2=4
S
4
MP
28 tháng 6 2023
\(\dfrac{11}{2}.\dfrac{21}{3}+\dfrac{11}{3}.\dfrac{1}{2}\)
\(=\dfrac{77}{2}+\dfrac{11}{6}=\dfrac{121}{3}\)
14 tháng 7 2023
1: =1-1+5-5+7-7+8-8=0
2: =14-23+5+14-5+23+17
=28+17=45
3: =12-12+9-9+14-44-3=-33
4: =22-8-8-12+4
=22-16-8
=-2
15 tháng 7 2023
Bài \(1\)
\(1)\) \(1-5+7-8+4-1+5-7+8\)
\(=(1-1)+(5-5)+(7-7)+(8-8)\)
\(=0+0+0+0\)
\(=0\)
\(2)\) \(14-23+(5+14)-(5-23)+17\)
\(=14-23+5+14-5+23+17\)
\(=(14+14)+(23-23)+(5-5)+17\)
\(=28+17\)
\(=45\)
\(3)\) \(12-44+9-3+14-19-9-12\)
\(=(12-12)+(9-9)+(14-44)+3\)
\(=-30+3\)
\(=-33\)
\(4)\) \(22-(4-8+12)+(-8-12+4)\)
\(=22-4+8-12-8-12+4\)
\(=22+(4+4)+(8-8)+(-12-12)\)
\(=22-24\)
\(=-2\)
H
1
MA
6 tháng 10 2023
\(a.\dfrac{-3}{8}-\dfrac{13}{65}+\dfrac{3}{8}=\left(\dfrac{3}{8}-\dfrac{3}{8}\right)-\dfrac{13}{65}=-\dfrac{13}{65}\)
\(b.\left(\dfrac{-13}{7}-\dfrac{4}{9}\right)-\left(-\dfrac{10}{7}-\dfrac{4}{9}\right)=\dfrac{-13}{7}-\dfrac{4}{9}+\dfrac{10}{7}+\dfrac{4}{9}\\ =\left(\dfrac{-13}{7}+\dfrac{10}{7}\right)+\left(\dfrac{4}{9}-\dfrac{4}{9}\right)=-\dfrac{3}{7}\)
\(c.17\dfrac{1}{3}\cdot\left(\dfrac{-3}{7}\right)+3\dfrac{2}{3}\cdot\left(\dfrac{-3}{7}\right)=\dfrac{-3}{7}\cdot\left(17\dfrac{1}{3}+3\dfrac{2}{3}\right)\\ =\dfrac{-3}{7}\cdot\left(\dfrac{52}{3}+\dfrac{11}{3}\right)=\dfrac{-3}{7}\cdot21=-9\)
AH
19 tháng 8 2016
a ) \(\frac{15}{2}-\left(-\frac{7}{3}\right)-\frac{7}{3}-10\)
= \(\frac{15}{2}+\frac{7}{3}-\frac{7}{3}-10\)
=\(\frac{15}{2}-10\)
= \(\frac{-5}{2}\)
b ) \(\frac{65}{2}+\left(-\frac{65}{3}\right)-\frac{130}{3}\)
= \(\frac{65}{6}-\frac{130}{3}\)
=\(\frac{-65}{2}\)
c ) \(\left(\frac{-16}{3}\right)+\left(\frac{-2}{3}\right)\)
= -6
d ) \(\frac{1}{7}+\frac{9}{-8}+\left(-\frac{3}{14}\right)\)
= \(\frac{-55}{56}+\left(-\frac{3}{14}\right)\)
= \(\frac{-67}{56}\)
e ) - 1,8 +\(\frac{5}{-6}\)
= \(\frac{-79}{30}\)
PH
1
NV
Nguyễn Việt Lâm
Giáo viên
16 tháng 1
\(A< \dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}+...+\dfrac{1}{2003.2004}\)
\(\Rightarrow A< \dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{2003}-\dfrac{1}{2004}\)
\(\Rightarrow A< \dfrac{1}{4}-\dfrac{1}{2004}< \dfrac{1}{4}\)
Đồng thời:
\(A>\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+...+\dfrac{1}{2004.2005}\)
\(A>\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+...+\dfrac{1}{2004}-\dfrac{1}{2005}\)
\(A>\dfrac{1}{5}-\dfrac{1}{2005}=\dfrac{80}{401}>\dfrac{50}{500}>\dfrac{1}{10}>\dfrac{1}{65}\)
Vậy \(\dfrac{1}{65}< A< \dfrac{1}{4}\)
a) \(1+1=2\)
b) \(2+2+2=6\)
c) \(7+3+65=75\)
Học tốt!