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A) 195 x 63 + 37 x195
195 x ( 63 + 37 ) = 195 x 100
= 19500
B) 7^12 : 7^10 - 36 : 3^2
= 7^12-10 - 36 : 9
= 7^2 - 4 = 49 - 4 = 45
C) 180 - [130-(12-10)^3] + 2023^0
= 180 -(130-2^3)+1
= 180-130+8+1
= 50 + 8+1 = 59
\(a,195.63+37.195\)
\(=195\left(63+37\right)\)
\(=195.100\)
\(=19500\)
\(b,7^{12}:7^{10}-36:3^2\)
\(=7^2-2^2.3^2:3^2\)
\(=7^2-2^2\)
\(=49-4=44\)
\(c,180-\left[130-\left(12-10\right)^3\right]+2023^0\)
\(=180-\left[130-2^3\right]+1\)
\(=180-\left(130-8\right)+1\)
\(=180-122+1\)
\(=59\)
Có gì k hiểu thì ib nhá
Thực hiện các phép tính(tính nhanh nếu có thể)
a)135-12.(3+6)
b)36+4.(7-15)
c) (-3)2 .23
d)(-6-14):(-5)
a, 135 - 12 . 9
= 135 - 108
= 27
b, 36 + 4 . -8
= 36 + (-32)
= 36 - 32
= 4
c, (-3)2 . 23
= 9 . 8
= 72
d, ( -6 - 14 ) : (-5) = (-21) : (-5) = 4,2
a 135-12*(3+6)
= 135 - 12*9
= 135 - 12*(10-1)
=135- (12*10-12*1
)=135-(120-12)
=135-108
=27
b= 35+4*-8
=35+ 4*(-10+2)
=35+(4*-10+4*2)
=35+(-40+8)
=35+-32
=3
`a,5 xx (-7)+(-2) xx (-5)`
`=5 xx (-7)+5 xx 2`
`= 5 xx (2-7)`
`=5 xx (-5)`
`=-25`
`b,5 xx (-9)+(-2) xx 3`
`=3 xx (-15)+3 xx (-2)`
`=3 xx (-15-2)`
`=3 xx (-17)`
`=-51`
`c,6 xx (-5)^2+3 xx (-15)`
`=2 xx 3 xx 25+3 xx (-15)`
`=3 xx 75-3 xx 15`
`=3 xx (75-15)`
`=3 xx 60`
`=180`
Câu 1:
a: =126+5=131
b: =-564-724+564+224=-500
c: =3x25+2-8
=75+2-8
=77-8
=69
d: =1024:32+140:70-49
=32-49+2
=-15
\(a.36+15+64\\ =\left(36+64\right)+15\\ =100+15\\ =115\\ b.12\cdot36+12\cdot64\\ =12\cdot\left(36+64\right)\\ =12\cdot100\\ =1200\\ c.\left(3^2+2^3\cdot5\right):7\\ =\left(9+8\cdot5\right):7\\ =\left(9+40\right):7\\ =49:7\\ =7\)\(\)
a)
\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)
\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
b)
\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
\(B=7^5:7^3-6^2\cdot2+2^3\cdot2^2\)
\(B=7^2-36\cdot2+2^5\)
\(B=49-36\cdot2+32\)
\(B=49-72+32\)
\(B=9\)
\(a,\dfrac{2}{5}-\dfrac{3}{8}+\dfrac{7}{6}=\dfrac{16}{40}-\dfrac{15}{40}+\dfrac{7}{6}=\dfrac{1}{40}+\dfrac{7}{6}=\dfrac{3}{120}+\dfrac{140}{120}=\dfrac{143}{120}\)
\(b,\dfrac{2}{3}+\left[\dfrac{5}{7}+\left(-\dfrac{2}{3}\right)\right]=\dfrac{2}{3}+\dfrac{5}{7}+\left(-\dfrac{2}{3}\right)=\left[\dfrac{2}{3}+\left(-\dfrac{2}{3}\right)\right]+\dfrac{5}{7}=0+\dfrac{5}{7}=\dfrac{5}{7}\)
\(c,\dfrac{5}{13}+\left(-\dfrac{5}{7}\right)+\left(-\dfrac{20}{41}\right)+\dfrac{8}{13}+\left(-\dfrac{21}{41}\right)\)
\(=\left(\dfrac{5}{13}+\dfrac{8}{13}\right)-\dfrac{5}{7}-\dfrac{20}{41}-\dfrac{21}{41}=-\dfrac{5}{7}\)
a: =48/120-45/120+140/120
=143/120
b: =2/3-2/3+5/7=5/7
c: =5/13+8/13-5/7-20/41-21/41
=-5/7
a; 135 + 60 + 365 + 240
= (135 + 365) + (60+ 240)
= 500 + 300
= 800
b; 37.28+ 37.72
= 37.(28 + 72)
= 37.100
= 3700
1290 - 20.(75:73 + 20230)
= 1290 - 20.(72 + 1)
= 1290 - 20.(49 + 1)
= 1290 - 20.50
= 1290 - 1000
= 290