Câu hỏi của Nguyễn Thanh Trúc

Question

tính nhanh:$\dfrac{2003x1999-2003x999}{2004x999+1004}$

✫¸.•°*”˜˜”*°•✫ Ṱђầภ Ḉђết ✫•°*”˜˜”*°... · Accepted Answer

$\dfrac{2003\times1999-2003\times999}{2004\times999+1004}=$ $\dfrac{2003\times\left(1999-999\right)}{\left(1000+1004\right)\times999+1004}$

$=\dfrac{2003\times1000}{1000\times999+1004\times999+1004}$

$=\dfrac{2003\times1000}{1000\times999+1004\times\left(999+1\right)}$

$=\dfrac{2003\times1000}{1000\times999+1004\times1000}$

$=\dfrac{2003\times1000}{1000\times\left(999+1004\right)}$

$=\dfrac{2003}{2003}=1$

Câu trả lời:

$\dfrac{2003\times1999-2003\times999}{2004\times999+1004}=$ $\dfrac{2003\times\left(1999-999\right)}{\left(1000+1004\right)\times999+1004}$

$=\dfrac{2003\times1000}{1000\times999+1004\times999+1004}$

$=\dfrac{2003\times1000}{1000\times999+1004\times\left(999+1\right)}$

$=\dfrac{2003\times1000}{1000\times999+1004\times1000}$

$=\dfrac{2003\times1000}{1000\times\left(999+1004\right)}$

$=\dfrac{2003}{2003}=1$