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\(\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}{\dfrac{19}{1}+\dfrac{18}{2}+\dfrac{17}{3}+....+\dfrac{1}{19}}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}{1+\left(\dfrac{18}{2}+1\right)+\left(\dfrac{17}{3}+1\right)+\left(\dfrac{1}{19}+1\right)}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{20}}{1+\dfrac{20}{2}+\dfrac{20}{3}+...+\dfrac{20}{19}}\)
\(=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{20}}{20.\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}\right)}\)
\(=\dfrac{1}{20}\)
ta có : (ghi lại đề)
=6+12+18+24+30/3+6+9+12+15
=2*(3/3+6/6+9/9+12/12+15/15)
=2*(1+1+1+1+1)
=2*5=10
chúc main học tốt nhé
=43/306:599/105x1473/1820
=1505/61098x1473/1820
=0.01993613035
Đặt \(A=1.2.3+2.3.4+3.4.5+...+17.18.19\)
\(\Rightarrow3A=1.2.3.3+2.3.4.3+3.4.5.3+...+17.18.19.3\)
\(\Rightarrow3A=1.2.3.\left(4-1\right)+2.3.4.\left(5-2\right)+3.4.5.\left(6-3\right)\)
\(+17.18.19\left(20-16\right)\)
\(=17.18.19.20\)
\(\Rightarrow A=38760\)
Vậy \(1.2.3+2.3.4+3.4.5+...+17.18.19=38760\)
\(x+\frac{1}{19}+x+\frac{2}{18}+x+\frac{3}{17}+x+\frac{4}{16}=4\)
\(4x+\left(\frac{1}{19}+\frac{2}{18}+\frac{3}{17}+\frac{4}{16}\right)=4\)
\(4x+\frac{6863}{11628}=4\)
\(4x=4-\frac{6863}{11628}=\frac{39649}{11628}\)
\(\Rightarrow x=\frac{39649}{11628\cdot4}=\frac{39649}{46512}\)
N = (202 - 192) + (182 - 172) + ...+ (42 - 32) + (22 - 12)
= (20 - 19).(20 + 19) + (18 - 17)(18 + 17) +...+ (4 -3).(4 +3) + (2-1)(2+1)
= 39 + 35 + ...+ 7 + 3
Số số hạng: (39 - 3): 4 + 1 = 10
=> N = (39 + 3).10 : 2 = 210
+) Ở đây: sd công thức: (a-b).(a+b) = a2 - b2
ta có
\(4A=1.2.3.4+2.3.4.4+..+17.18.19.4\)hay \(4A=1.2.3.4+2.3.4\left(5-1\right)+..+17.18.19.\left(20-16\right)\)
\(4A=1.2.3.4+2.3.4.5-1.2.3.4+..+17.18.19.20-16.17.18.19=17.18.19.20\)
hay \(A=5.17.18.19\)