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a) \(1010+1111+1212+.....+9898+9999\)\(=\frac{\left(1010+9999\right)\cdot\left(\frac{9999-1010}{1111-1010}+1\right)}{2}\)\(=\frac{11009\cdot\left(\frac{8989}{101}+1\right)}{2}\)\(=\frac{11009\cdot\left(89+1\right)}{2}\)\(=\frac{11009\cdot90}{2}\)\(=\frac{990810}{2}\)\(=495405\)
a) Khoảng cách của dãy số là:
1111-1010=101;1212-1111=101;...
Số số hạng của dãy số là:
(9999-1010):101+1=90(số)
Tổng:
(1010+9999)*90:2=495405
Đ/s:495405
Nhớ k mk nha!
a) \(\dfrac{23}{24}< 1\)
\(\dfrac{24}{23}>1\)
\(\Rightarrow\dfrac{23}{24}< \dfrac{24}{23}\)
b) \(\dfrac{4}{21}< \dfrac{4}{20}=\dfrac{1}{5}=\dfrac{6}{30}< \dfrac{6}{29}\)
c) \(\dfrac{6}{7}=1-\dfrac{1}{7}< \dfrac{8}{9}=1-\dfrac{1}{9}\)
d) \(\dfrac{1212}{1313}=\dfrac{12\times101}{13\times101}=\dfrac{12}{13}\)
\(A=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{9.11}-\frac{1}{11.13}\)
\(\Leftrightarrow A=\frac{1}{1.3}-\frac{1}{11.13}=\frac{1}{3}-\frac{1}{143}=\frac{140}{429}\)
\(A=\frac{4}{1.3.5}+\frac{4}{3.5.7}+\frac{4}{5.7.9}+\frac{4}{7.9.11}+\frac{4}{9.11.13}\)
\(\Rightarrow A=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{9.11}-\frac{1}{11.13}\)
\(\Rightarrow A=\frac{1}{1.3}-\frac{1}{11.13}=\frac{1}{3}-\frac{1}{143}=\frac{140}{429}\)
a)Vì \(7>5\)nên\(\frac{7}{12}>\frac{5}{12}\)
b)\(\frac{2}{5}=\frac{2\times5}{5\times5}=\frac{10}{25}\)
Vì \(\frac{10}{25}>\frac{7}{25}\)nên \(\frac{2}{5}>\frac{7}{25}\)
c) Vì \(11< 24\)nên \(\frac{9}{11}>\frac{9}{24}\)
d)\(\frac{12}{13}=\frac{12\times101}{13\times101}=\frac{1212}{1313}\)
\(\Rightarrow\frac{12}{13}=\frac{1212}{1313}\)
e) mình làm hai cách:
Cách 1:\(\frac{4}{5}=\frac{4\times9}{5\times9}=\frac{36}{45};\frac{10}{9}=\frac{10\times5}{9\times5}=\frac{50}{45}\)
Vì \(36>50\)nên \(\frac{36}{45}>\frac{50}{45}\)hay\(\frac{4}{5}>\frac{10}{9}\)
Cách 2: Vì \(\frac{4}{5}< 1;\frac{10}{9}>1\)
\(\Rightarrow\frac{4}{5}< 1< \frac{10}{9}\)
Vậy \(\frac{4}{5}< \frac{10}{9}\)
g)\(\frac{17}{15}=\frac{17\times29}{15\times29}=\frac{493}{435};\frac{31}{29}=\frac{31\times15}{29\times15}=\frac{465}{435}\)
Vì \(493>465\)nên \(\frac{493}{435}>\frac{465}{435}\)hay \(\frac{17}{15}>\frac{31}{29}\)
7/12>5/12
2/5>7/25
9/11>9/24
12/13=1212/1313
4/5<10/9
17/15>31/29
\(a,=\frac{7-1}{1.3.7}+\frac{9-3}{3.7.9}+\frac{13-7}{7.9.13}+\frac{15-9}{9.13.15}\)\(+\frac{19-13}{13.15.19}\)
\(=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}\)
\(=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}\)
\(b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)\)
làm giống như trên
\(c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)\)
\(=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}\)
\(d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)\)
\(=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}\)
P/S: . là nhân nha
Ta có 1212/1313= 12/13
=> 1212/1313 =12/13
a/\(\frac{1212}{1313}=\frac{12x101}{13x101}=\frac{12}{13}\)
Vậy \(\frac{12}{13}=\frac{1212}{1313}\)
b/Ta có:
\(\frac{4}{5}< 1\)
\(\frac{10}{9}>1\)
=>\(\frac{4}{5}< 1< \frac{10}{9}\Rightarrow\frac{4}{5}< \frac{10}{9}\)
c/\(\frac{17}{15}=1+\frac{2}{15}\)
\(\frac{31}{29}=1+\frac{2}{29}\)
Vì \(\frac{2}{15}>\frac{2}{29}\) nên \(\frac{17}{15}>\frac{31}{29}\)
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chú ý: dấu "=>" có nghĩa là "suy ra"
a) 1+2+3+...+2018
=[(2018-1):1+1].(2018+1):2
=2018.2019:2
=2037171
b) 4+7+10+13+...+2017
=[(2017-4):3+1].(2017+4):2
=672.2021:2
=679056
c) 1+2-3-4+5+6-7-8+9+10-11-12+13+14
=(1+2-3-4)+(5+6-7-8)+(9+10-11-12)+13+14
=-4+(-4)+(-4)+13+14
=-12+27
=15
d) 23 x 75 + 25 x 23 + 180
=23 x (75+25) +180
=23 x 100 +180
=2300+180
2480
chúc ban hoc tốt nha
a) Số số hạng: ( 2018 - 1 ) : 1 + 1 = 2018
Tổng: 2018 x ( 2018 + 1 ) : 2 = 2 037 171