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1+2-3-4+5+6-7-8+9+................+33
=1+(2-3-4+5)+(6-7-8+9)+............+(30-31-32+33)
=1+0+0+..............+0
=1
`-3/7xx15/13-3/7xx11/13-3/7`
`=-3/7xx(15/13+11/13+1)`
`=-3/7xx3`
`=-9/7`
a) \(\dfrac{7}{30}+\dfrac{\left(-12\right)}{37}+\dfrac{23}{30}+\dfrac{\left(-25\right)}{37}=\left(\dfrac{7}{30}+\dfrac{23}{30}\right)+\left(\dfrac{-12}{37}+\dfrac{-25}{37}\right)=1+\left(-1\right)=0\)
b) \(\dfrac{5}{7}\cdot\dfrac{5}{11}+\dfrac{5}{7}\cdot\dfrac{2}{11}-\dfrac{5}{7}\cdot\dfrac{14}{11}=\dfrac{5}{7}\cdot\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\left(-\dfrac{7}{11}\right)=-\dfrac{5}{11}\)
c) \(\dfrac{\left(-5\right)}{7}\cdot\dfrac{3}{13}-\dfrac{5}{7}\cdot\dfrac{10}{13}+1\dfrac{5}{7}=\dfrac{5}{7}\cdot\dfrac{-3}{13}-\dfrac{5}{7}\cdot\dfrac{10}{13}+\dfrac{12}{7}=\dfrac{5}{7}\cdot\left(\dfrac{-3}{13}-\dfrac{10}{13}\right)+\dfrac{12}{7}=\dfrac{5}{7}\cdot\left(-1\right)+\dfrac{12}{7}=\left(-\dfrac{5}{7}\right)+\dfrac{12}{7}=\dfrac{7}{7}=1\)
a)\(315-64:2^3\)
\(=315-2^6:2^3\)
\(=315-8=307\)
b)\(7^2.33+7^2.67\)
\(=7^2\left(33+67\right)\)
\(=7^2.100=4900\)
a) \(315-64\div2^3=315-2^6\div2^3=315-2^{6-3}=315-2^3=315-8=307\)
b) \(7^2.33+7^2.67=7^2.\left(33+67\right)=7^2.100=49.100=4900\)
(7/111 - 4/33 + 9/37).(1/2 - 1/3 -1/6)
= (7/111 - 4/33 + 9/37).0
= 0
(7/111 - 4/33 + 9/37).(1/2 - 1/3 - 1/6)
= (7/111 - 4/33 + 9/37).0
= 0
Ta có:\(77.\left(-7\right)-33.7-10.\left(-7\right)=\left(-7\right).\left(77+33-10\right)\)
\(=\left(-7\right).\left(110-10\right)\)
\(=\left(-7\right).100\)
\(=-700\)
\(77.\left(-7\right)-33.7-10.\left(-7\right)\)
\(=-7.\left(77+33-10\right)\)
\(=-7.100\)
\(=-700\)
@@ Học tốt