Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
A = \(\dfrac{47\times48-47\times47-24-23+2046}{2+4+8+..+512+1024}\)
Đặt tử số là B, mẫu số là C thì
B = 47\(\times\)48 - 47 \(\times\) 47 - 24 -23+2046vàC = 2 + 4 + 8 +....+ 512 + 1024
B = 47 \(\times\) 48 - 47 \(\times\) 47 - 24 - 23 + 2046
B= 47 \(\times\) 48 - 47 \(\times\) 47 - ( 24 + 23) + 2046
B = 47 \(\times\) 48 - 47 \(\times\) 47 - 47 + 2046
B = 47 \(\times\) 48 - 47 \(\times\) 47 - 47 \(\times\) 1 + 2046
B = 47 \(\times\) ( 48 - 47 - 1) + 2046
B = 47 \(\times\) 0 + 2046
B = 2046
C = 2 + 4 + 8+ ....+ 512 +1024
C \(\times\) 2 = 4 + 8 +.....+ 512 + 1024 + 2048
C \(\times\) 2 - C = 2048 - 2
C \(\times\) ( 2 - 1) = 2046
C = 2046
A = \(\dfrac{B}{C}\) = \(\dfrac{2046}{2046}\) = 1
a) ( 735 - 135 ) + ( 243 - 143 ) = 600 + 100
= 700
b) 31 x ( 118 - 48 ) = 31 x 70
= 2170
c) ( 25 x 32 ) x7 = 800 x 7
= 2400
d ) 47 x ( 63 + 47 ) - 38
= 47 x 100 - 38
= 4700 - 38
=4662
h ) ( 53 + 47 ) x ( 39 + 21 ) = 100 x 60
= 6000
\(\dfrac{19}{28}+\dfrac{23}{47}-\dfrac{15}{8}+\dfrac{9}{28}+\dfrac{24}{47}\)
\(=\left(\dfrac{19}{28}+\dfrac{9}{28}\right)+\left(\dfrac{23}{47}+\dfrac{24}{47}\right)-\dfrac{15}{8}\)
\(=\dfrac{28}{28}+\dfrac{47}{47}-\dfrac{15}{8}\)
\(=1+1-\dfrac{15}{8}\)
\(=\dfrac{1}{8}\)
____________________
\(\dfrac{30}{11}+\dfrac{12}{35}-\dfrac{19}{11}-\dfrac{2}{35}-\dfrac{2}{7}\)
\(=\left(\dfrac{30}{11}-\dfrac{19}{11}\right)+\left(\dfrac{12}{35}-\dfrac{2}{35}\right)-\dfrac{2}{7}\)
\(=\dfrac{11}{11}+\dfrac{10}{35}-\dfrac{2}{7}\)
\(=1+\dfrac{2}{7}-\dfrac{2}{7}\)
\(=1\)
\(A=\frac{2}{2\cdot3\cdot4}+\frac{2}{3\cdot4\cdot5}+...+\frac{2}{47\cdot48\cdot49}+\frac{2}{48\cdot49\cdot50}\)
\(A=\frac{1}{2\cdot3}-\frac{1}{3\cdot4}+\frac{1}{3\cdot4}-\frac{1}{4\cdot5}+...+\frac{1}{47\cdot48}-\frac{1}{48\cdot49}+\frac{1}{48\cdot49}-\frac{1}{49\cdot50}\)
\(A=\frac{1}{2\cdot3}-\frac{1}{49\cdot50}\)
\(A=\frac{1}{6}-\frac{1}{2450}\)
\(A=\frac{611}{3675}\)
mong giúp đc bn.thk cho mk
giúp mình với bạn nào giúp mình mình sé cho bạn ấy like