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\(\Leftrightarrow x-15=132:11\Leftrightarrow x-15=12\Leftrightarrow x=12+15=27\)
\(\Leftrightarrow x=15-20\Leftrightarrow x=-5\)
\(11\left(x-15\right)=132\\ \Rightarrow x-15=132:11\\ \Rightarrow x-15=12\\ \Rightarrow x=12+15\\ \Rightarrow x=27\)
b) 11.(x – 15) = 132
x - 15 = 132 : 11
x - 15 = 12
x = 12 + 15
x = 27
Vậy x = 27
(x-7).(2x-8)=0
suy ra :(x-7)=0 suy ra x=7
2x-8=0 suy ra x=4
Câu b:
( x-40) .15 =15.3
(x-40) .15=45
(x-40) = 45:15
x-40 = 3
x=43
Bài 1: Tìm x biết:
a ) (x-7).(2x-8)=0
=>x-7=0 hoặc 2x-8=0
=>x=7 hoặc x=4
b) (x-40).15=15.3
=>(x-40).15=45
=>x-40=45:15
=>x-40=3
=>x=3+40
=>x=43
\(\frac{-15}{4}\times\frac{9}{11}+\frac{15}{4}\times\frac{15}{11}-\frac{15}{4}\times\frac{6}{11}\)
\(=\frac{15}{4}\times\left(\frac{-9}{11}+\frac{15}{11}-\frac{6}{11}\right)\)
\(=\frac{15}{4}\times0\)
\(=0\)
\(=\frac{15}{4}\times\left(-\frac{9}{11}\right)+\frac{15}{4}\times\frac{15}{11}+\frac{15}{4}\times\left(-\frac{6}{11}\right)\)
\(=\frac{15}{4}\times\left(-\frac{9}{11}+\frac{15}{11}+\left(-\frac{6}{11}\right)\right)\)
\(=\frac{15}{4}\times0\)
\(=0\)
A = 1 - \(\dfrac{5}{6}\)+\(\dfrac{7}{12}\)-\(\dfrac{9}{20}\)+\(\dfrac{11}{30}\)-\(\dfrac{13}{42}\)+\(\dfrac{15}{56}\) - \(\dfrac{17}{72}\)+\(\dfrac{19}{90}\)+\(\dfrac{23}{132}\)-\(\dfrac{25}{156}\)
A = 1 - \(\dfrac{5}{2.3}\)+\(\dfrac{7}{3.4}\)-\(\dfrac{9}{4.5}\)+\(\dfrac{11}{5.6}\)-\(\dfrac{13}{6.7}\)+\(\dfrac{15}{7.8}\)-\(\dfrac{17}{8.9}\)+\(\dfrac{19}{9.10}\)+\(\dfrac{23}{11.12}\)-\(\dfrac{25}{12.13}\)
A = 1 - \(\dfrac{1}{2}-\dfrac{1}{3}\)+\(\dfrac{1}{3}+\dfrac{1}{4}\)-\(\dfrac{1}{4}-\dfrac{1}{5}\)+...+\(\dfrac{1}{11}+\dfrac{1}{12}\)- \(\dfrac{1}{12}-\dfrac{1}{13}\)
A = 1 - \(\dfrac{1}{2}\) - \(\dfrac{1}{13}\)
A = \(\dfrac{1}{2}\) - \(\dfrac{1}{13}\)
A = \(\dfrac{11}{26}\)
\(a.13.\left(78+22\right)=13.100=1300\)
\(b.25.70+28.25+25.2=25.\left(70+28+2\right)=25.100=2500\)
\(c.\dfrac{15.3.14.2.19}{19.14.15}=6\)
\(d.\dfrac{132.70.60}{12.35.20}=\dfrac{11.12.35.2.20.3}{12.35.20}=66\)
(57869-297:1x108)x(180:15-132:11)
= 25793 x 0
= 0
=(57869-297:11.108).0
=0