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ta có
A = \(1+\frac{1+2}{2}+\frac{1+2+3}{3}+\frac{1+2+3+4}{4}+......+\frac{1+2+3+\text{4 +....+16}}{16}\)
xét tổng S = 1+2+3+4+5+......+n = \(\frac{\left(n+1\right)n}{2}\) lấy \(\frac{S}{n}=\frac{\frac{\left(n+1\right)n}{2}}{n}=\frac{n+1}{2}\)
ta có
A=\(1+\frac{\frac{2\left(2+1\right)}{2}}{2}+\frac{\frac{3\left(3+1\right)}{2}}{3}+\frac{\frac{4\left(4+1\right)}{2}}{4}+\frac{\frac{5\left(5+1\right)}{2}}{5}+......+\frac{\frac{16\left(16+1\right)}{2}}{16}\)
A = \(1+\frac{1+2}{2}+\frac{1+3}{2}+\frac{1+4}{2}+\frac{1+5}{2}+......+\frac{1+16}{2}\)
A = \(1+\frac{1+2+1+3+1+\text{4+1+5+1+6+.....+1+16}}{2}\)
A = \(1+\frac{151}{2}\)
A = \(\frac{153}{2}\)
A=1+1/2x3+1/3X6+1/4X10+...+1/16X136
A=1+3/2+2+5/2+3+...+17/2
A=2/2+3/2+4/2+5/2+6/2+...+17/2
A=2+3+4+5+...+16+17/2
A=(2+17)x16:2/2
A=19x16:2/2
A=304:2/2
A=152/2
A=76
****
`(5^(16) +16^5)(3^(17)-3^(10))(2^4-4^2)`
`=(5^(16)+16^5)(3^(17)-3^(10))(16-16)`
`=(5^(16)+16^5)(3^(17)-3^(10))0`
`=0`
Ta có :
\(1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+\frac{1}{4}\left(1+2+3+4\right)+...+\frac{1}{16}\left(1+2+3+4+...+16\right)\)
\(=\)\(1+\frac{1}{2}.\frac{2\left(2+1\right)}{2}+\frac{1}{3}.\frac{3\left(3+1\right)}{2}+\frac{1}{4}.\frac{4\left(4+1\right)}{2}+...+\frac{1}{16}.\frac{16\left(16+1\right)}{2}\)
\(=\)\(1+\frac{2+1}{2}+\frac{3+1}{2}+\frac{4+1}{2}+...+\frac{16+1}{2}\)
\(=\)\(\frac{2}{2}+\frac{3}{2}+\frac{4}{2}+\frac{5}{2}+...+\frac{17}{2}\)
\(=\)\(\frac{2+3+4+5+...+17}{2}\)
\(=\)\(\frac{\frac{16\left(17+2\right)}{2}}{2}\)
\(=\)\(\frac{152}{2}\)
\(=\)\(76\)
Bài này áp dụng công thức \(1+2+3+...+n=\frac{n\left(n+1\right)}{2}\) nhé
Chúc bạn học tốt ~
ta có
\(3^2\cdot2^3-\left(-4^2-3^2\right)-16=3^2\cdot2^3+3^2+4^2-16\)
\(=3^2\left(2^3+1\right)+\left(4^2-16\right)=3^2.9=81\)
32*23-(-42-32)+(-16)
=32*23+42+32-42
=(32+32)*23+(42-42)
=34*23+0
Phần sau bạn tự làm nha