Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Sửa đề: 113^2-26*113+13^2
=113^2-2*113*13+13^2
=(113-13)^2
=100^2=10000
dúng hằng đẳng thức thứ 2 dễ mà bạn
=(113-13)2=1002=10 000
111-98+113-96+115-94+...+207-2
=(111+113+115+...+207)-(2+4+...+96+98)
=\(\dfrac{\left(207-11\right):2+1\cdot\left(11+207\right)}{2}\)-\(\dfrac{\left(98-2\right):2+1\cdot\left(2+98\right)}{2}\)
=10791-2450=8341.
\(1^2-2^2+3^2-4^2+...-2004^2+2005^2\)
\(=1^2-2^2+3^2-4^2+...+2003^2-2004^2+2005^2\)
\(=-\left(2^2-1^2\right)-\left(4^2-3^2\right)-...-\left(2004^2-2003^2\right)+2005^2\)
\(=-\left[\left(2^2-1^2\right)+\left(4^2-3^2\right)+...+\left(2004^2-2003^2\right)\right]+2005^2\)
\(=-\left[\left(2-1\right)\left(2+1\right)+\left(4-3\right)\left(4+3\right)+...+\left(2004-2003\right)\left(2004+2003\right)\right]+2005^2\)
\(=-\left[1+2+3+4+...+2003+2004\right]+2005^2\)
\(=-\dfrac{2004.2005}{2}+2005^2\)
\(=2011015\)
:D
\(84^2-44\cdot84+22^2-38^2\)
\(=\left(84-22\right)^2-38^2\)
\(=\left(62+38\right)\left(62-38\right)\)
\(=100\cdot24=2400\)
\(C=a^3+b^3=\left(a+b\right)\left(a^2-ab+b^2\right)=a^2-ab+b^2=13-ab\)
Có : \(a^2+2ab+b^2=\left(a+b\right)^2\)
\(\Leftrightarrow13+2ab=1^2\)
\(\Leftrightarrow2ab=-12\)
\(\Leftrightarrow ab=-6\)
\(\Leftrightarrow C=16-\left(-6\right)=13+6=19\)
\(a+b=1\Rightarrow\left(a+b\right)^2=1\)\(\Rightarrow a^2+b^2+2ab=1\)
Mà \(a^2+b^2=13\Rightarrow ab=-6\)
\(\Rightarrow a^3+b^3=\left(a+b\right)\left(a^2+b^2-ab\right)=1.\left[13-\left(-6\right)\right]=19\)
\(113^2-26.113+13^2\)
\(=\left(113-13\right)^2\)
\(=100^2\)
\(=10000\)