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a) 3/7 + 4/9 + 4/7 + 5/9
= ( 3/7 + 4/7 ) + ( 4/9 + 5/9 )
= 7/7 + 9/9
= 1 + 1
= 2
b)1/5 + 4/10 + 9/15 + 16/20 + 25/25 + 36/30 + 49/35 + 64/40 + 81/45
= 1/5 + 2/5 + 3/5 + 4/5 + 5/5 + 6/5 + 7/5 + 8/5 + 9/5
= ( 1/5 + 9/5 ) + ( 2/5 + 8/5 ) + (7/5 + 3/5 ) + ( 4/5 + 6/5 ) + 5/5
= 2 + 2 + 2 + 2 + 1
= 2 x 4 + 1
= 8 +1
= 9
c) 1/8 + 1/12 + 3/8 + 5/12
= ( 1/8 + 3/8 ) + ( 1/12 + 5/12)
= 4/8 + 6/12
= 1/2 + 1/2
= 2/4 = 1/2
mỏi tay rồi
d; (1 - \(\dfrac{1}{2}\)) x (1 - \(\dfrac{1}{3}\)) x (1 - \(\dfrac{1}{4}\)) x ... x ( 1 - \(\dfrac{1}{100}\))
= \(\dfrac{1}{2}\) x \(\dfrac{2}{3}\) x \(\dfrac{3}{4}\) x \(\dfrac{3}{4}\) x ... x \(\dfrac{99}{100}\)
= \(\dfrac{1}{100}\)
a) 67.(-18) + (-33).18
= 67.(-18) + 33.(-18)
= (-18).(67 + 33)
= (-18).100
= (-1800)
b) 34.(-53) - (-66).53 - 68.(-53)
= (-34).53 + 66.53 - (-68).53
= (-34).53 + 66.53 + 68.53
= 53. (-34 + 66 + 68)
= 53.100
= 5300
a) 67.(-18) + (-33).18
= 67.(-18) + 33.(-18)
= (-18).(67 + 33)
= (-18).100
= (-1800)
b) 34.(-53) - (-66).53 - 68.(-53)
= (-34).53 + 66.53 - (-68).53
= (-34).53 + 66.53 + 68.53
= 53. (-34 + 66 + 68)
= 53.100
= 5300
chúc bạn học tốt nhé
Bài 1:
Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)
Vậy: \(x=\dfrac{4}{65}\)
Bài 2:
a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)
\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)
\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)
\(=\dfrac{5366}{527}\)
a/ 259 . 13 + 259 . 86 + 259
= 259 . 13 + 259 . 86 + 259 . 1
= 259 . ( 13 + 86 + 1 )
= 259 . 100
= 25 900
1) = 2750 - 1229 + 2570 + 438 + 29 + 438
= (2750 + 2750) - (1229 - 29) + (438 + 438)
= 5500 - 1200 + 876
= 5176
2) = 38.9 + 17.9 - 35.9 - 11.35
= (38+17-35).9 - 11.35
= 20.9 - 11.35
= 180 - 385
= -205
3) = 500 - \(\left\{5.\left[409-\left(24-21\right)^2\right]+1000\right\}\) : 15
= 500 - \(\left\{5.\left[409-9\right]+1000\right\}:15\)
= 500 - \(\left\{5.400+1000\right\}:15\)
= 500 - (2000 + 1000) : 15
= 500 - 200
= 300
a: \(\left(\dfrac{1}{17}-\dfrac{1}{57}+\dfrac{1}{23}\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)
\(=\left(\dfrac{1}{17}-\dfrac{1}{57}+\dfrac{1}{23}\right)\cdot\dfrac{3-2-1}{6}\)
=0
b: \(\left(\dfrac{17}{3}-\dfrac{29}{6}\right)+\dfrac{7}{6}=\dfrac{17}{3}-\dfrac{29}{6}+\dfrac{7}{6}\)
\(=\dfrac{17}{3}-\dfrac{22}{6}=\dfrac{17}{3}-\dfrac{11}{3}=\dfrac{6}{3}=2\)