Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(N=\frac{6^6+6^3\cdot3^3+3^6}{-73}=\frac{\left(2\cdot3\right)^6+\left(2\cdot3\right)^3\cdot3^3+3^6}{-73}\)
\(=\frac{2^6\cdot3^6+2^3\cdot3^3\cdot3^3+3^6}{-73}=\frac{2^6\cdot3^6+2^3\cdot3^6+3^6}{-73}\)
\(=\frac{3^6\left(2^6+2^3+1\right)}{-73}=\frac{3^6\cdot73}{-73}=-3^6=-729\)
\(N=\dfrac{6^6+6^3.3^3+3^6}{-73}\)
\(\Rightarrow N=\dfrac{\left(2.3\right)^6+\left(2.3\right)^3.3^3+3^6}{-73}\)
\(\Rightarrow N=\dfrac{2^6.3^6+2^3.3^6+3^6}{-73}\)
\(\Rightarrow N=\dfrac{3^6\left(2^6+2^3-1\right)}{-73}\)
\(\Rightarrow N=3^6.\left(-1\right)=-729\)
\(A=\frac{2^{12}.27^3}{6^7.16^2}=\frac{2^{12}.3^9}{3^7.2^{15}}=\frac{3^2}{2^3}=\frac{9}{8}\)
a)
\(\begin{array}{l}\left( {0,25 - \frac{5}{6}} \right).1,6 + \frac{{ - 1}}{3}\\ =(\frac{25}{100}-\frac{5}{6}).\frac{16}{10}+\frac{-1}{3}\\= \left( {\frac{1}{4} - \frac{5}{6}} \right).\frac{8}{5} + \frac{{ - 1}}{3}\\ = \left( {\frac{6}{{24}} - \frac{{20}}{{24}}} \right).\frac{8}{5} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{24}}.\frac{8}{5} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{15}} + \frac{{ - 1}}{3}\\ = \frac{{ - 14}}{{15}} + \frac{{ - 5}}{{15}}\\ = \frac{{ - 19}}{{15}}\end{array}\)
b)
\(\begin{array}{l}3 - 2.\left[ {0,5 + \left( {0,25 - \frac{1}{6}} \right)} \right]\\ = 3 - 2.\left[ {\frac{1}{2} + \left( {\frac{1}{4} - \frac{1}{6}} \right)} \right]\\ = 3 - 2.\left( {\frac{1}{2} + \frac{1}{{12}}} \right)\\ =3-2.(\frac{6}{12}+\frac{1}{12})\\= 3 - 2.\frac{7}{{12}}\\ = 3 - \frac{7}{6}\\=\frac{18}{6}-\frac{7}{6}\\ = \frac{{11}}{6}\end{array}\)
a)y2 = 7 => y = \(\sqrt{7}hoặc-\sqrt{7}\)
Nếu y = \(\sqrt{7}\) thì :
x2y3 = 5 . y2 .y
x2y3 = 5.7.\(\sqrt{7}\) = 35\(\sqrt{7}\)
Nếu y = -\(\sqrt{7}\) thì :
x2y3 = 5.7. (-\(\sqrt{7}\)) = -35\(\sqrt{7}\)
b) x2y2 = 5.7 = 35
x6y6 = (x2y2)3 = 353 = 42875
c) làm tương tự câu (a). Chia x làm 2 trường hợp bằng căng 5 hoặc cặng 5 rồi thế vô tính nhé bạn!