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Ta có
\(A=\left(-40\right):\left(-5\right)-39=8-39=-31\)
\(B=7-2^4+\left(-36\right):\left(-9\right)+5^3\)
\(=7-16+4+125=120\)
2) \(B=\left(1-2-3+4\right)+\left(5-6-7+8\right)+...+\left(1989-1990-1991+1992\right)+1993-1994\)
\(=0+0+...+0+1993-1994=0+1993-1994=-1\)
a. 1/4 + 1/5 + 3/4 + 2/5
=(1/4 + 3/4) + (1/5 + 2/5)
=1 + 3/5
=8/5
b. 2/7 + 5/14 + 1/7 + 3/14
=(2/7 + 1/7) + (5/14 + 3/14)
=3/7 + 4/7
=1
\(7\frac{5}{9}-\left(3\frac{5}{9}-2\frac{3}{4}\right)=7\frac{5}{9}-3\frac{5}{9}+2\frac{3}{4}=4+2\frac{3}{4}=6\frac{3}{4}\)
\(7\frac{5}{9}-\left(3\frac{5}{9}-2\frac{3}{4}\right)=7\frac{5}{9}-3\frac{5}{9}+2\frac{3}{4}=4+2\frac{3}{4}=6\frac{3}{4}\)
a/ A= 1-3+5-7+9-11+......+97-99
= -2+(-2)+(-2)+......+(-2)
= (-2).25=-50
b/B=-1-2-3-4-...-100
=-(1+2+3+4+...+100)
=-5050
c/C=1-2+3-4+5-6+......+99-100
= -1+(-1)+(-1)+.............+(-1)
=(-1).50=-50
d/D=1-2-3+4+5-6-7+8+9-....+94-95
= (1-2-3+4)+(5-6-7+8)+.......+(92-93-94+95)
= 0+0+0+...+0=0
\(a)\left(-\dfrac{3}{4}\div\dfrac{2}{-3}\right)\times\dfrac{-5}{7}\)
\(=\dfrac{9}{8}\times\dfrac{-5}{7}\)
\(=\dfrac{-45}{56}\)
\(b)\dfrac{-2}{-5}\div\left(\dfrac{7}{-5}\div\dfrac{-3}{2}\right)\)
\(=\dfrac{2}{5}\div\left(\dfrac{7}{-5}\div\dfrac{-3}{2}\right)\)
\(=\dfrac{2}{5}\div\dfrac{14}{15}\)
\(=\dfrac{3}{7}\)