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TH
4
DN
2 tháng 10 2021
M=256
N=15^15/3^15
Thông cảm vì mình ko giải ra chi tiết vì nó lâuuuu
2 tháng 10 2021
N = \(\dfrac{3^{30}.5^{30}}{3^{30}.5^{15}}=\dfrac{5^{30}}{5^{15}}=5^{15}\)
HH
22 tháng 6 2018
Giải:
\(M=\dfrac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(\Leftrightarrow M=\dfrac{2^{10}.4^{10}+4^{10}}{2^4.4^4+4^{11}}\)
\(\Leftrightarrow M=\dfrac{4^{10}\left(2^{10}+1\right)}{4^4.2^4\left(2^{10}+1\right)}\)
\(\Leftrightarrow M=\dfrac{4^6}{2^4}\)
\(\Leftrightarrow M=\dfrac{2^{12}}{2^4}\)
\(\Leftrightarrow M=2^8=256\)
Vậy ...
4 tháng 12 2018
\(A=\dfrac{8^{10}+4^{10}}{8^4+4^{11}}=\dfrac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\dfrac{2^{30}+2^{20}}{2^{12}+2^{22}}=\dfrac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}=2^8\)
Vậy...
22 tháng 10 2017
\(M=\dfrac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(M=\dfrac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)
\(M=\dfrac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(M=\dfrac{4^{15}+4^{10}}{4^6+4^{11}}\)
\(M=\dfrac{4^{10}\left(4^5+1\right)}{4^6\left(4^5+1\right)}\)
\(M=\dfrac{4^{10}}{4^6}\)
\(M=4^4=256\)
2 tháng 5 2017
\(\dfrac{\text{45^{10^{ }}}.5^{10}}{75^{10}}=\dfrac{9^{10}.5^{10}.5^{10}}{5^{10}.5^{10}.3^{10}}=\dfrac{9^{10}}{3^{10}}=3^{10}\)
2 tháng 5 2017
\(\dfrac{\left(0,8\right)^5}{\left(0,4\right)^6}=\dfrac{2^5.\left(0,4\right)^5}{\left(0,4\right)^6}=\dfrac{2^5}{0,4}=\dfrac{32}{0,4}=80\)
NN
1
QT
Quoc Tran Anh Le
Giáo viên
15 tháng 12 2017
\(\dfrac{8^{10}+4^{10}}{8^4+4^{11}}=\dfrac{8^4.4^{10}\left(8^6+1\right)}{8^4.4^{10}\left(1+4\right)}=\dfrac{8^6+1}{1+4}=52429\)
15 tháng 12 2017
a) \(\dfrac{15}{12}+\dfrac{5}{13}-\dfrac{3}{12}-\dfrac{18}{13}\)
\(=\left(\dfrac{15}{12}-\dfrac{3}{12}\right)+\left(\dfrac{5}{13}-\dfrac{18}{13}\right)\)
\(=\dfrac{12}{12}+\dfrac{-13}{13}\)
\(=1-1\)
\(=0\)
b) \(\dfrac{5^4\cdot20^4}{25^5\cdot4^5}\)
\(=\dfrac{100^4}{100^5}\)
\(=\dfrac{1}{100}\)
15 tháng 12 2017
a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}\)
\(=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
b) \(\frac{5^4.20^4}{25^5.4^5}=\frac{\left(20.5\right)^4}{\left(25.4\right)^5}=\frac{100^4}{100^5}=\frac{1}{100}\)
c) \(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.\left(2^{18}+2^8\right)}{2^{12}.\left(1+2^{10}\right)}=\frac{2^{18}+2^8}{1+2^{10}}=256\)
B
4
24 tháng 9 2021
\(\dfrac{x+4}{8}+\dfrac{x+3}{9}=\dfrac{x+2}{10}+\dfrac{x+1}{11}\)
\(\Leftrightarrow\left(\dfrac{x+4}{8}+1\right)+\left(\dfrac{x+3}{9}+1\right)=\left(\dfrac{x+2}{10}+1\right)+\left(\dfrac{x+1}{11}+1\right)\)
\(\Leftrightarrow\dfrac{x+12}{8}+\dfrac{x+12}{9}-\dfrac{x+12}{10}-\dfrac{x+12}{11}=0\)
\(\Leftrightarrow\left(x+12\right)\left(\dfrac{1}{8}+\dfrac{1}{9}-\dfrac{1}{10}-\dfrac{1}{11}\right)=0\)
\(\Leftrightarrow x=-12\)( do \(\dfrac{1}{8}+\dfrac{1}{9}-\dfrac{1}{10}-\dfrac{1}{11}\ne0\))
OY
24 tháng 9 2021
\(\dfrac{x+4}{8}+\dfrac{x+3}{9}=\dfrac{x+2}{10}+\dfrac{x+1}{11}\)
\(\dfrac{x+4}{8}+1+\dfrac{x+3}{9}+1=\dfrac{x+2}{10}+1+\dfrac{x+1}{11}+1\)
\(\dfrac{x+12}{8}+\dfrac{x+12}{9}=\dfrac{x+12}{10}+\dfrac{x+12}{11}\)
\(\dfrac{x+12}{8}+\dfrac{x+12}{9}-\dfrac{x+12}{10}-\dfrac{x+12}{11}=0\)
\(\Rightarrow\left(x+12\right).\left(\dfrac{1}{8}+\dfrac{1}{9}+\dfrac{1}{10}+\dfrac{1}{11}\right)=0\)
Vì \(\dfrac{1}{8}+\dfrac{1}{9}+\dfrac{1}{10}+\dfrac{1}{11}\ne0\) nên \(x+12=0\)
\(\Rightarrow x=-12\)
20 tháng 12 2022
a: \(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
b: \(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)
\(\dfrac{8^{10}+4^{10}}{8^4+4^{11}}\\ =\dfrac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\\ =\dfrac{2^{3\cdot10}+2^{2\cdot10}}{2^{3\cdot4}+2^{2\cdot11}}\\ =\dfrac{2^{30}+2^{20}}{2^{12}+2^{22}}\\ =\dfrac{2^{20}\cdot\left(2^{10}+1\right)}{2^{12}\cdot\left(2^{10}+1\right)}\\ =\dfrac{2^{20}}{2^{12}}\\ =2^{20-12}\\ =2^8\\ =256\)
hình như là gạch 8 và 4 rồi cộng số mũ