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\(\dfrac{3}{5}\times\dfrac{2}{7}-\dfrac{3}{5}\times\dfrac{4}{7} +\dfrac{3}{5}\)
\(=\dfrac{3}{5}\times\left(1+\dfrac{2}{7}-\dfrac{4}{7}\right)\)
\(=\dfrac{3}{5}\times\left(\dfrac{7}{7}+\dfrac{2}{7}-\dfrac{4}{7}\right)\)
\(=\dfrac{3}{5}\times\left(\dfrac{7+2-4}{7}\right)\)
\(=\dfrac{3}{5}\times\dfrac{5}{7}\)
\(=\dfrac{3}{7}\)
= 3/5 x 2/7 - 3/5 x 4/7 + 3/5 x 1
= 3/5 x ( 2/7 + 4/7 + 1 )
= 3/5 x 1
= 3/5
3 \(\times\) \(\dfrac{4}{15}\) + 2 \(\times\) \(\dfrac{4}{15}\) - 5 \(\times\) \(\dfrac{4}{15}\)
= \(\dfrac{4}{15}\) \(\times\) ( 3 + 2 - 5)
= \(\dfrac{4}{15}\) \(\times\) 0
= 0
(Dấu . là dấu nhân)
a/\(\dfrac{2}{5}\cdot\dfrac{4}{3}-\dfrac{2}{5}:3\)
\(=\dfrac{2}{5}\cdot\dfrac{4}{3}-\dfrac{2}{5}\cdot\dfrac{1}{3}\)
\(=\dfrac{2}{5}\cdot\left(\dfrac{4}{3}-\dfrac{1}{3}\right)\)
\(=\dfrac{2}{5}\cdot1\)
\(=\dfrac{2}{5}\)
b/\(\dfrac{2010}{2018}:\dfrac{1}{2}+\dfrac{7}{2018}:\dfrac{1}{2}\)
\(=\left(\dfrac{2010}{2018}+\dfrac{7}{2018}\right):\dfrac{1}{2}\)
\(=\dfrac{2017}{2018}:\dfrac{1}{2}\)
\(=\dfrac{2017}{2018}\cdot2\)
\(=\dfrac{2017}{1009}\)
a, \(\dfrac{2}{5}\) \(\times\) \(\dfrac{4}{3}\) - \(\dfrac{2}{5}\) : 3
= \(\dfrac{2}{5}\) \(\times\) \(\dfrac{4}{3}\) - \(\dfrac{2}{5}\) \(\times\) \(\dfrac{1}{3}\)
= \(\dfrac{2}{5}\) \(\times\) ( \(\dfrac{4}{3}\) - \(\dfrac{1}{3}\))
= \(\dfrac{2}{5}\) \(\times\) 1
= \(\dfrac{2}{5}\)
b, \(\dfrac{2010}{2018}\) : \(\dfrac{1}{2}\) + \(\dfrac{7}{2018}\) : \(\dfrac{1}{2}\) + \(\dfrac{1}{2018}\) : \(\dfrac{1}{2}\)
= \(\dfrac{2010}{2018}\) \(\times\) \(\dfrac{2}{1}\) + \(\dfrac{7}{2018}\) \(\times\) \(\dfrac{2}{1}\) + \(\dfrac{1}{2018}\) \(\times\) \(\dfrac{2}{1}\)
= \(\dfrac{2}{1}\) \(\times\) ( \(\dfrac{2010}{2018}\) + \(\dfrac{7}{2018}\) + \(\dfrac{1}{2018}\))
= 2 \(\times\) \(\dfrac{2018}{2018}\)
= 2 \(\times\) 1
= 2
1, \(\dfrac{16\times25-22\times16}{7\times3+5\times7}=\dfrac{16\times\left(25-22\right)}{7\times\left(5+3\right)}=\dfrac{16\times3}{7\times8}\)
\(=\dfrac{6}{7}\)
2,\(\dfrac{2001\times2003+2003\times2005}{2003\times4006}=\dfrac{2003\times\left(2001+2005\right)}{2003\times4006}=\dfrac{2003\times4006}{2003\times4006}=1\)
\(108\times5+108\times96-108=108\times\left(5+96-1\right)\)
\(=108\times100=10800\)
`4/7xx3/7+4/5xx6/7-4/5xx7/14`
`=4/7xx3/7+4/5xx(6/7-7/14)`
`=4/7xx3/7+4/5xx5/14`
`=12/49+2/7`
`=26/49`
=4/7x3/7+4/5x(6/7-7/14)
=4/7x3/7+4/5x5/14
=12/49+2/7
=26/49
= 5 x 7 + 5 x 4 + 5 x 8 + 5 x 1
= 5 x ( 7 + 4 + 8 + 1 )
= 5 x 20
= 100
5x(7+4+8+1)
=5x20
=100