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NT
1
D
17 tháng 3 2018
\(A=\frac{1}{2}+\frac{4}{7}-\frac{-3}{70}+\frac{-1}{4}\)
\(A=\frac{15}{14}-\frac{-3}{70}+\frac{-1}{4}\)
\(A=\frac{39}{35}+\frac{-1}{4}\)
\(A=\frac{121}{40}\)
\(B=\frac{3}{4}-\frac{3}{-16}+\frac{5}{12}\)
\(B=\frac{15}{16}+\frac{5}{12}\)
\(B=\frac{65}{48}\)
\(C=\frac{9}{27}+\frac{2}{14}+\frac{4}{-12}-\frac{1}{-6}\)
\(C=\frac{10}{21}+\frac{4}{-12}-\frac{1}{-6}\)
\(C=\frac{1}{7}-\frac{1}{-6}\)
\(C=\frac{13}{42}\)
DT
3
15 tháng 4 2018
a) \(\frac{7}{3}+\frac{1}{2}--\frac{3}{7}\)
\(=\frac{7}{3}+\frac{1}{2}+\frac{3}{7}\)
\(=\frac{137}{42}\)
b) \(\frac{5}{12}-\frac{3}{-16}+\frac{3}{4}\)
\(=\frac{5}{12}+\frac{3}{16}+\frac{3}{4}\)
\(=\frac{65}{48}\)
Chúc bn học tốt !
AK
15 tháng 4 2018
\(a)\frac{7}{3}+\frac{1}{2}--\frac{3}{7}\)
\(=\frac{7}{3}+\frac{1}{2}+\frac{3}{7}\)
\(=\frac{98}{42}+\frac{21}{42}+\frac{18}{42}\)
\(=\frac{137}{42}\)
\(b)\frac{5}{12}-\frac{3}{-16}+\frac{3}{4}\)
\(=\frac{5}{12}--\frac{3}{16}+\frac{3}{4}\)
\(=\frac{5}{12}+\frac{3}{16}+\frac{3}{4}\)
\(=\frac{20}{48}+\frac{9}{48}+\frac{36}{48}\)
\(=\frac{65}{48}\)
Chúc bạn học tốt !!!
C
13 tháng 3 2017
a,3/7 +1/2-[-3]/70
=13/14 -[-3]/70
=65/70 -[-3]/70
=34/35
b,3/5+-1/25 -35/100
=14/25 - 35/100
=56 /100 -35/100
= 21/100
c ,5/12 -3/-16+3/4
=29/48 +3/4
= 29/48 +36/48
=65/48
d, 5/15 +4/-12 +1/7 -1/-6
= 1/3 +1/-3 +1/7-1/-6
=0+1/7-1/-6
= 13/42
13 tháng 3 2017
A.\(\dfrac{3}{7}+\dfrac{1}{2}+\dfrac{\left(-3\right)}{70}\)
=\([\dfrac{30}{70}+\dfrac{\left(-3\right)}{70}]\)+\(\dfrac{1}{2}\)
= \(\dfrac{27}{70}+\dfrac{35}{70}\)
=\(\dfrac{62}{70}=\dfrac{31}{35}\)
B.\(\dfrac{3}{5}+\dfrac{-1}{25}-\dfrac{35}{100}\)
=\(\dfrac{60}{100}+\dfrac{-4}{100}-\dfrac{35}{100}\)
=\(\dfrac{60+\left(-4\right)-35}{100}\)
=\(\dfrac{21}{100}\)
C.\(\dfrac{5}{12}-\dfrac{3}{-16}+\dfrac{3}{4}\)
=\(\left(\dfrac{5}{12}+\dfrac{9}{12}\right)-\dfrac{-3}{16}\)
=\(\dfrac{7}{6}-\dfrac{-3}{16}\)
=\(\dfrac{56}{48}-\dfrac{-9}{48}\)=\(\dfrac{65}{48}\)
D.\(\dfrac{5}{15}+\dfrac{4}{-12}+\dfrac{1}{7}-\dfrac{1}{-6}\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+(\dfrac{-2}{6}-\dfrac{-1}{6})\)
=\(\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{-1}{6}\)
=\((\dfrac{1}{3}+\dfrac{-1}{6})+\dfrac{1}{7}\)
=\(\dfrac{1}{6}+\dfrac{1}{7}\)=\(\dfrac{13}{42}\)
NK
12 tháng 2 2023
\(a,\dfrac{4}{5}+\dfrac{2}{3}+\dfrac{1}{9}=\dfrac{12}{15}+\dfrac{10}{15}+\dfrac{1}{9}=\dfrac{22}{15}+\dfrac{1}{9}=\dfrac{66}{45}+\dfrac{5}{45}=\dfrac{71}{45}\)
\(b,\dfrac{3}{7}+\dfrac{11}{14}+\dfrac{19}{28}=\dfrac{12}{28}+\dfrac{22}{28}+\dfrac{19}{28}=\dfrac{53}{28}\)
\(c,\dfrac{1}{2}+\dfrac{1}{7}+\dfrac{-1}{5}=\dfrac{7}{14}+\dfrac{2}{14}+\dfrac{-1}{5}=\dfrac{9}{14}+\dfrac{-1}{5}=\dfrac{45}{70}+\dfrac{-14}{70}=\dfrac{31}{70}\)
\(d,\dfrac{7}{8}+\dfrac{5}{16}+\dfrac{-3}{4}=\dfrac{14}{16}+\dfrac{5}{16}+\dfrac{-12}{16}=\dfrac{7}{16}\)
\(e,\dfrac{1}{4}+\dfrac{5}{12}+\dfrac{-1}{13}=\dfrac{3}{12}+\dfrac{5}{12}+\dfrac{-1}{13}=\dfrac{8}{12}+\dfrac{-1}{13}=\dfrac{2}{3}+\dfrac{-1}{13}=\dfrac{26}{39}+\dfrac{-3}{39}=\dfrac{23}{39}\)
\(g,\dfrac{2}{3}+\dfrac{3}{8}+\dfrac{-5}{12}=\dfrac{16}{24}+\dfrac{9}{24}+\dfrac{-5}{12}=\dfrac{25}{24}+\dfrac{-5}{12}=\dfrac{25}{24}+\dfrac{-10}{24}=\dfrac{15}{24}\)
LT
1
7 tháng 5 2020
1) \(\frac{7}{3}+\frac{1}{2}-\left(-\frac{3}{70}\right)=\frac{7}{3}+\frac{1}{2}+\frac{3}{70}=\frac{490}{210}+\frac{105}{210}+\frac{9}{210}=\frac{604}{210}=\frac{302}{105}\)
2) \(\frac{5}{12}-\left(\frac{3}{-16}\right)+\frac{3}{4}=\frac{5}{12}+\frac{3}{16}+\frac{3}{4}=\frac{20}{48}+\frac{9}{48}+\frac{36}{48}=\frac{65}{48}\)
18 tháng 2 2022
3/7+1/2- -3/70 =34/35
3/5 + -1/25 -35/100 =21/100
5/12-3/-16 + 3/4 =65/48
YY
20 tháng 7 2015
a/ \(\frac{7}{3}+\frac{1}{2}-\frac{-3}{70}=\frac{17}{6}-\frac{-3}{70}=\frac{302}{105}\)
b/ \(\frac{5}{12}-\frac{3}{-16}+\frac{3}{4}=\frac{29}{48}+\frac{3}{4}=\frac{65}{48}\)
c/ \(\frac{2}{3}+5\frac{3}{7}:2+9\frac{4}{9}.\left(-7\right)+\frac{1}{12}.\left(-2\right)^4=\frac{2}{3}+\frac{38}{7}:2+\frac{85}{9}.\left(-7\right)+\frac{1}{12}.\left(-2\right)^4=\frac{2}{3}+\frac{19}{7}+-\frac{595}{9}+\frac{4}{3}=\frac{71}{21}+-\frac{583}{9}=-\frac{3868}{63}\)
a)\(\frac{7}{3}\)+\(\frac{1}{2}\)-\(\frac{-3}{70}\)= \(\frac{490}{210}\)+ \(\frac{105}{210}\)- \(\frac{-9}{210}\)
=\(\frac{490+105-\left(-9\right)}{210}\)
= \(\frac{604}{210}\)=\(\frac{302}{105}\)
b)\(\frac{5}{12}\)-\(\frac{3}{-16}\)+\(\frac{3}{4}\)= \(\frac{5}{12}\)-\(\frac{-3}{16}\)+\(\frac{3}{4}\)
=\(\frac{100}{240}\)-\(\frac{-45}{240}\)+\(\frac{180}{240}\)
=\(\frac{100-\left(-45\right)+180}{240}\)
= \(\frac{325}{240}\)=\(\frac{65}{48}\)
\(a,\frac{7}{3}+\frac{1}{2}--\frac{3}{70}\)
\(=\frac{17}{6}+\frac{3}{70}\)
\(=\frac{302}{105}\)
\(b,\frac{5}{12}-\frac{3}{-16}+\frac{3}{4}\)
\(=\frac{29}{48}+\frac{3}{4}\)
\(=\frac{65}{48}\)
chúc bạn học tốt