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\(\frac{9}{16}:\frac{27}{8}=\frac{3^2:3^3}{2^4:2^3}=\frac{\frac{1}{3}}{2}=\frac{1}{6}\)
b tương tự nha
\(\frac{9}{16}:\frac{27}{8}=\frac{9}{16}\cdot\frac{8}{21}=\frac{3\cdot3\cdot4\cdot2}{8\cdot2\cdot7\cdot3}=\frac{14}{3}\)
\(\frac{40}{7}:\frac{5}{14}=\frac{40}{7}\cdot\frac{14}{5}=\frac{4\cdot5\cdot2\cdot7\cdot2}{7\cdot5}=\frac{16}{1}=16\)
Chúc bạn học tốt
Ta có \(\frac{8}{9}+\frac{14}{27}+\frac{1}{9}=\left(\frac{8}{9}+\frac{1}{9}\right)+\frac{14}{27}=1+\frac{14}{27}=\frac{41}{27}\)
Ta có \(\frac{1}{2}+\frac{3}{4}+\frac{1}{2}=\left(\frac{1}{2}+\frac{1}{2}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)
\(\frac{8}{9}+\frac{14}{27}+\frac{1}{9}=\left(\frac{8}{9}+\frac{1}{9}\right)+\frac{14}{27}=1+\frac{14}{27}=\frac{41}{27}\)
\(\frac{1}{2}+\frac{3}{4}+\frac{1}{2}=\left(\frac{1}{2}+\frac{1}{2}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)
\(\frac{3}{2}+\frac{3}{8}+\frac{3}{32}+\frac{3}{128}+\frac{3}{512}\)
=\(\frac{3}{1.2}+\frac{3}{2.4}+\frac{3}{4.8}+\frac{3}{8.16}+\frac{3}{16.32}\)
=\(\frac{3}{1}-\frac{3}{2}+\frac{3}{2}-\frac{3}{4}+\frac{3}{4}-\frac{3}{8}+\frac{3}{8}-\frac{3}{16}+\frac{3}{16}-\frac{3}{36}\)
=\(\frac{3}{1}-\frac{3}{36}\)=\(\frac{35}{12}\)
c. 1/6+7/2=11/3
Chúc bạn học tốt nếu đúng thì giúp mình nhé.
8/9:6/27-3=4-3=1
Bài làm :
\(c,\frac{1}{6}+\frac{5}{2}\times\frac{7}{5}\)
\(=\frac{1}{6}+\frac{7}{2}\)
\(=\frac{11}{3}\)
\(\frac{8}{9}:\frac{6}{27}-3\)
\(=\frac{8}{9}\times\frac{9}{2}-3\)
\(=4-3\)
\(=1\)
Học tốt
\(\frac{4}{27}\cdot\frac{9}{2}+\frac{7}{15}=\frac{2}{3}+\frac{7}{15}=\frac{17}{15}\)
( \(\cdot\)là dấu nhân đó)
Đặt \(A=\frac{1}{3}+\frac{1}{9}+.......+\frac{1}{59049}\)
\(3A=3.\left(\frac{1}{3}+\frac{1}{9}+......+\frac{1}{59049}\right)\)
\(3A=1+\frac{1}{3}+........+\frac{1}{19683}\)
\(3A-A=\left(1+\frac{1}{3}+......+\frac{1}{19683}\right)-\left(\frac{1}{3}+\frac{1}{9}+........+\frac{1}{59049}\right)\)
\(2A=1-\frac{1}{59049}\)
\(2A=\frac{59048}{59049}\)
\(A=\frac{59048}{59049}:2\)
\(A=\frac{59048}{118098}\)
