Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a,\left(\frac{1}{16}\right)^3:\left(\frac{1}{8}\right)^2=\frac{1}{16^3}.8^2=\frac{\left(2^3\right)^2}{\left(2^4\right)^3}=\frac{2^{3.2}}{2^{4.3}}=\frac{2^6}{2^{12}}=\frac{1}{2^6}\)
\(b,\left(\frac{1}{9}\right)^{25}:\left(\frac{1}{3}\right)^{30}=\frac{1}{9^{25}}.3^{30}=\frac{3^{30}}{\left(3^2\right)^{25}}=\frac{3^{30}}{3^{50}}=\frac{1}{3^{20}}\)
\(\frac{9^5.16^4}{27^3.^{ }8^4}=\frac{\left(3^2\right)^5.\left(2^4\right)^4}{\left(3^3\right)^3.\left(2^3\right)^4}=\frac{3^{10}.2^{16}}{3^9.2^{12}}=3.2^4=3.16=48\)
\(\frac{8^{15}.3^{16}}{4^{22}.9^8}=\frac{\left(2^3\right)^{15}.3^{16}}{\left(2^2\right)^{22}.\left(3^2\right)^8}=\frac{2^{45}.3^{16}}{2^{44}.3^{16}}=2\)
\(\frac{8^{15}.3^{16}}{4^{22}.9^8}=\frac{\left(2^3\right)^{15}.3^{16}}{\left(2^2\right)^{22}.\left(3^2\right)^8}=\frac{2^{45}.3^{16}}{2^{44}.3^{16}}=2\)
\(=\frac{3^{30}.2^{24}}{2^{21}.3^{32}}=\frac{2^2}{3^2}=\frac{4}{9}\)