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a) 285 + 470 + 115 + 230
= (285 + 115) + (470 + 230)
= 400 + 700
= 1 100
b) 571 +216 + 129 + 124
= (571 + 129) + (216 + 124)
= 700 + 340
= 1 040.
35.48 + 65.68 + 20.35
= 35.(48 + 20) + 65.68
= 35.68 + 65.68
= (35 + 65).68
= 100 . 68
= 6800
35.48+65.68+20.35
=35.48+20.35+65.68
=35.(48+20)+65.68
=35.68+65.68
=68.(35+65)
=68.100=6800
=115 + 85 +35 - 46 - 35
=200-46+35-35
= 200-46
=154
hok tốt
\(\frac{3}{5}.\frac{13}{46}-\frac{1}{10}.\frac{16}{23}\)
\(=\frac{3}{5}.\left(\frac{1}{46}.13\right)-\frac{1}{10}.\frac{32}{46}\)
\(=\left(\frac{3}{5}.13\right).\frac{1}{46}-\left(\frac{1}{10}.32\right).\frac{1}{46}\)
\(=\frac{39}{5}.\frac{1}{46}-\frac{32}{10}.\frac{1}{46}\)
\(=\frac{78}{10}.\frac{1}{46}-\frac{32}{10}.\frac{1}{46}\)
\(=\left(\frac{78}{10}-\frac{32}{10}\right).\frac{1}{46}\)
\(=\frac{46}{10}.\frac{1}{46}\)
\(=\frac{1}{10}\)
\(\text{Phần a nên sửa đề thế này :}\) \(\frac{1}{7}.\frac{-3}{8}+\frac{1}{7}.\frac{-13}{8}\)
\(\text{Giải :}\)
\(\frac{1}{7}.\frac{-3}{8}+\frac{1}{7}.\frac{-13}{8}\)
\(=\frac{1}{7}\left(\frac{-3}{8}+\frac{-13}{8}\right)\)
\(=\frac{1}{7}.\left(-2\right)\)
\(=\frac{-2}{7}\)
\(\frac{3}{5}.\frac{13}{46}-\frac{1}{10}.\frac{16}{23}\)
\(=\frac{3}{5}.\left(\frac{1}{46}.13\right)-\frac{1}{10}.\frac{32}{46}\)
\(=\left(\frac{3}{5}.13\right).\frac{1}{46}-\left(\frac{1}{10}.32\right).\frac{1}{46}\)
\(=\frac{39}{5}.\frac{1}{46}-\frac{32}{10}.\frac{1}{46}\)
\(=\frac{78}{10}.\frac{1}{46}-\frac{32}{10}.\frac{1}{46}\)
\(=\left(\frac{78}{10}-\frac{32}{10}\right).\frac{1}{46}\)
\(=\frac{46}{10}.\frac{1}{46}\)
\(=\frac{1}{10}\)
a) ( 367 + 133 ) - ( 24 + 76 ) , b) ( 338 -162 ) - ( 635 - 165 ) còn câu c thì mik ko bt , bn cs thể tham khảo hai câu mà mik đã đưa ra :3
a) \(\left(367-24\right)+\left(133-76\right)\)
\(=\left(367-133\right)+\left(24+76\right)\)
\(=434+100\)
\(=534\)
b) \(\left(338-635\right)-\left(165-162\right)\)
\(=\left(635-165\right)-\left(338+162\right)\)
\(=470+570\)
\(=970\)
c) \(-418-\left\{-346-218\right\}\left[-146-\left(-285\right)+215\right]\)
285+470+115+230=(285+115)+(470+230)=400+700=1100
\(285+470+115+230\)
\(=\left(285+115\right)+\left(470+230\right)\)
\(=400+700\)
\(=1100\)