Question

[Miki Thảo]

Tìm x.y , biết

a )\(\left(x-1\right)^2+\left(y-3\right)^2=0\)

b) \(\left(2x-\frac{1}{2}\right)^4+\left(y+\frac{3}{2}\right)^8=0\)

c) \(\left(\frac{1}{2}x-5\right)^{20}+\left(y^2-\frac{1}{4}\right)^{10}\le0\)

Answer 1

[Trần Tuyết Như]

 \(\left(x-1\right)^2+\left(y-3\right)^2=0\)

mà  \(\left(x-1\right)^2\ge0;\left(y-3\right)^2\ge0\)

nên để: \(\left(x-1\right)^2+\left(y-3\right)^2=0\) thì:

  \(x-1=y-3=0\Rightarrow x=1;y=3\)

Answer 2

[Trần Thị Diễm Quỳnh]

a)x-1=y-3=0

x=1 va y=3

b)2x-1/2=y+3/2=0

x=1/4 va y=-3/2

c)1/2x-5=y²-1/4=0

1/2.x=5 va y²=1/4

x=10 va y=1/2 hoac x=10 va y=-1/2