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\(x.\frac{1}{2}=\frac{1}{2}+\frac{2}{4}\)
\(x.\frac{1}{2}=\frac{3}{4}\)
\(x=\frac{3}{4}:\frac{1}{2}\)
\(x=\frac{3}{2}\)
\(x-\frac{1}{2}=\frac{2}{4}+\frac{1}{2}\)
\(x-\frac{1}{2}=1\)
\(x=1+\frac{1}{2}\)
\(x=\frac{3}{2}\)
Mình làm cách lớp 6 nha bạn, cách lớp 4 mình không biết.
\(\frac{1}{2}.x+\frac{1}{5}.x=\frac{2}{5}\)
\(\Rightarrow x.\left(\frac{1}{2}+\frac{1}{5}\right)=\frac{2}{5}\)
\(\Rightarrow x.\frac{7}{10}=\frac{2}{5}\)
Giờ thành tìm x rồi!
\(x=\frac{7.5}{2.10}\)
\(x=1\frac{3}{4}\)
Xong!
\(\frac{1}{2}\times x+\frac{1}{5}\times x=\frac{2}{5}\)
\(x\times\left(\frac{1}{2}+\frac{1}{5}\right)=\frac{2}{5}\)
\(x\times\frac{7}{10}=\frac{2}{5}\)
\(x=\frac{2}{5}:\frac{7}{10}\)
\(x=\frac{4}{7}\)
\(2\frac{1}{2}-x=1\frac{2}{3}\)
\(x=2\frac{1}{2}-1\frac{2}{3}\)
\(x=\frac{5}{6}\)
1-(1-(1/2 × 3/5 + 1/5 × 1/2 + 2/10 × 1/2 +1/2)
=1-(1-(3/10 + 1/10 + 1/10 + 5/10)
=1-(1-(3+1+1+5/10)
=1-(1- 10/10)
=1-(1-1)
=1-0
=1
\(1-\left[1-\left(\frac{1}{2}\times\frac{3}{5}+\frac{1}{5}\times\frac{1}{2}+\frac{2}{10}\times\frac{1}{2}+\frac{1}{2}\right)\right]\)
\(=1-\left[1-\left\{\frac{1}{2}\times\left(\frac{3}{5}+\frac{1}{5}+\frac{2}{10}+\frac{1}{2}\right)\right\}\right]\)
\(=1-\left[1-\left\{\frac{1}{2}\times\left(\frac{6}{10}+\frac{2}{10}+\frac{2}{10}+\frac{5}{10}\right)\right\}\right]\)
\(=1-\left[1-\left\{\frac{1}{2}\times\left(\frac{6+2+2+5}{10}\right)\right\}\right]\)
\(=1-\left[1-\left\{\frac{1}{2}\times\frac{3}{2}\right\}\right]\)
\(=1-\left[1-\frac{3}{4}\right]\)
\(=1-\frac{1}{4}\)
\(=\frac{3}{4}\)
\(x-\frac{1}{2}=1+\frac{2}{1}\)
\(x-\frac{1}{2}=3\)
\(x=3+\frac{1}{2}\)
\(x=\frac{7}{2}\)
x- 1/2= 1+2/1
=>x-1/2=1+2
=>x-1/2=3
=>x=3+1/2
=>x=6/2+1/2
=>x=7/2
\(x+3\frac{1}{2}=\frac{1}{2}\)
\(x=\frac{1}{2}-3\frac{1}{2}\)
\(x=-3\)
\(x.\frac{1}{2}=2\) ; \(x+2=\frac{1}{2}+\frac{1}{2}\)
\(x=2:\frac{1}{2}\) \(x+2=\frac{2}{4}\)
\(x=4\) \(x=\frac{2}{4}-2\)
\(x=\frac{-6}{4}\)
\(x.\frac{1}{2}=2\)
\(x=2:\frac{1}{2}\)
\(x=4\)
\(x+2=\frac{1}{2}+\frac{1}{2}\)
\(x+2=1\)
\(x=1-2\)
\(khong\)\(co\)\(so\)\(tu\)\(nhien\)\(thoa\)\(man\)
\(k\) \(mk\)