Question

[Công chúa thế giới đêm]

Tìm x

\(a,x+\frac{15}{7}=\frac{9}{2}\)

\(b,x-\frac{3}{4}=\frac{7}{2}\)

\(c,x\times\frac{7}{8}=\frac{12}{5}\)

\(d,\frac{5}{6}:x=\frac{4}{3}\)

Answer 1

[Phương Thảo Linh 0o0]

\(x+\frac{15}{7}=\frac{9}{2}\)

\(x=\frac{9}{2}-\frac{15}{7}=\frac{33}{14}\)

\(x-\frac{3}{4}=\frac{7}{2}\)

\(x=\frac{7}{2}+\frac{3}{4}=\frac{17}{4}\)

\(x.\frac{7}{8}=\frac{12}{5}\)

\(x=\frac{12}{5}:\frac{7}{8}=\frac{96}{35}\)

\(\frac{5}{6}:x=\frac{4}{3}\)

\(x=\frac{5}{6}:\frac{4}{3}=\frac{5}{8}\)

Answer 2

[Thiên Thần Công Chúa]

• a) x=9/2-15/7=33/14
• b) x=7/2+3/4=17/4
• c) x=12/5:7/8=61/35
• d) x=5/6:4/3=5/8
• k nha