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a.
-2 (x+6)+6 (x-10)=8
-2x -12 +6x -60 =8
4x -72 =8
4x = -64
x= -16
b.
7x (2+x) -7x (x+3) =14
7x [ (2+x)-(x+3) ] =14
7x (2+x-x-3) =14
-7x =14
x= -2
ĐKXĐ: \(x\ne0\)
\(\frac{7x}{10}=\frac{14}{x}\Rightarrow7x^2=140\Rightarrow x^2=20\Rightarrow\orbr{\begin{cases}x=2\sqrt{5}\\x=-2\sqrt{5}\end{cases}}\)
Vậy ............................... chúc bn hok tốt
\(\frac{7x}{5}+\frac{14}{x}\)
=>\(7x.x=5.14\)
=>\(7x^2=70\)
=>\(x^2=70:7=10\)
=>\(x=\sqrt{x}\)
https://olm.vn/hoi-dap/tim-kiem?q=%7C2x-9%7C+%7C3x-13%7C-%7C14-5x%7C+%7C19-(4x+12)%7C=56t%C3%ACm+x&id=191953
\(\Leftrightarrow\left[{}\begin{matrix}14-19x=7x-15\\19x-14=7x-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}26x=29\\12x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{29}{26}\\x=-\dfrac{1}{12}\end{matrix}\right.\)
\(\frac{3}{7}\left(7x+\frac{2}{3}\right)-2\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)
\(\Leftrightarrow3x+\frac{2}{7}-\frac{5}{7}+6x=3\)
\(\Leftrightarrow9x=\frac{24}{7}\)
\(\Leftrightarrow x=\frac{8}{21}\)
\(\frac{3}{7}.\left(7x+\frac{2}{3}\right)-2.\left(\frac{5}{14}-3x\right)=\frac{15}{5}\)
\(\Leftrightarrow3x+\frac{2}{7}.x-\frac{5}{7}+6x=3\)
\(\Leftrightarrow\frac{65}{7}.x-\frac{5}{7}=3\)
\(\Leftrightarrow\frac{65}{7}.x=3+\frac{5}{7}\)
\(\Leftrightarrow\frac{65}{7}.x=\frac{26}{7}\)
\(\Leftrightarrow x=\frac{26}{7}:\frac{65}{7}\)
\(\Leftrightarrow x=\frac{2}{5}\)
\(7x\left(2+x\right)-7x\left(x+3\right)=14\)
\(\Rightarrow7x\left[\left(2+x\right)-\left(x+3\right)\right]=14\)
\(\Rightarrow7x\left[2+x-x-3\right]=14\)
\(\Rightarrow7x.\left(-1\right)=14\)
\(\Rightarrow-7x=14\)
\(\Rightarrow x=14:-7\)
\(\Rightarrow x=-2\)
Vậy x = -2
_Chúc bạn học tốt_
a) Ta có :\(\frac{x}{2}=\frac{y}{5}\Rightarrow x=2k\) ; \(y=5k\)
\(x+y=-21\Rightarrow2k+5k=-21\)
\(\Leftrightarrow7k=-21\Rightarrow k=-3\)
Với \(k=-3\Rightarrow\hept{\begin{cases}\frac{x}{2}=-3\\\frac{y}{5}=-3\end{cases}\Rightarrow}\hept{\begin{cases}x--3.2=-6\\y=-3.5=-15\end{cases}}\)
Vậy ........
c) \(7x=3y\Rightarrow\frac{x}{3}=\frac{y}{7}\left(1\right)\)
\(12y=7z\Rightarrow\frac{y}{7}=\frac{z}{12}\left(2\right)\)
Từ (1) và (2) \(\Rightarrow\frac{x}{3}=\frac{y}{7}=\frac{z}{12}=\frac{3x}{9}=\frac{2y}{14}=\frac{z}{12}=\frac{3x+2y+z}{9+14+12}=\frac{14}{35}=\frac{2}{5}\)
\(\Leftrightarrow\hept{\begin{cases}\frac{x}{3}=\frac{2}{5}\\\frac{y}{7}=\frac{2}{5}\\\frac{z}{12}=\frac{2}{5}\end{cases}\Rightarrow}\hept{\begin{cases}x=\frac{6}{5}\\y=\frac{14}{5}\\z=\frac{24}{5}\end{cases}}\)
a: =>10|x-2|=50
=>|x-2|=5
=>x-2=5 hoặc x-2=-5
=>x=7 hoặc x=-3
b: =>|3x-12|+|5x-20|=56
=>8|x-4|=56
=>|x-4|=7
=>x-4=7 hoặc x-4=-7
=>x=11 hoặc x=-3
→ 7x = 14x.x
→ x = \(\frac{7x}{14x}\)
→ x = \(\frac{1}{2}\)