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5x - 3x - 13 = 25
5x - 3x = 25+ 13
5x - 3x = 38
(5 - 3) x = 38
2 x = 38
x = 38:2
x = 19
Vậy x = 19
ai thấy đúng thì nhấn vào chữ "đúng"cho mik nha thank you
5x - 3x + 13 = 25
( 5 - 3 ) x - 13 = 25
2x - 13 = 25
2x = 25 + 13
2x = 38
x = 38 : 2
x = 19
Vậy x = 19
a,x-25=-43 b,35-5(x+13)=-15 c,5x+6=-19 d,51-(-12+3x)=27 e,3x+4=-23
x=(-43)+25 5(x+13)=35-(-15) 5x=-19-6 -12+3x=51-27 3x=(-23)-4
x=-18 5(x+13)=35+15 5x=(-19)+(-6) -12+3x=24 3x=(-23)+(-4)
5(x+13)=50 5x=-25 3x=24-(-12) 3x=-27
x+13=50:5 x=(-25):5=-5 3x=24+12 x=-27:3=-9
x+13=10 3x=36
x=13-10 x=36:3=12
x=3
NHỚ K CHO MÌNH NHA!!!!!!!
a.x - 25 = -43
x = -43 + 25
x = -18
b.35 - 5(x + 13) = -15
5(x + 13) = 35 - (-15)
5(x + 13) = 50
x + 13 = 50 : 5
x + 13 = 10
x = 10 - 13
x = -3
c. 5x + 6 = -19
5x = -19 - 6
5x = -25
x = -25 : 5
x = -5
d.51 - (-12 + 3x) = 27
-12 + 3x = 51 - 27
-12 + 3x = 24
3x = 24 - (-12)
3x = 36
x = 36 :3
x = 12
e. 3x +4 = -23
3x = -23 - 4
3x = -27
x = -27 : 3
x = -9
5x - 3x - 13 = 25
5x - 3x = 25 + 13
5x - 3x = 38
(5 - 3)x = 38
2x = 38
x = 38 : 2
x = 19
Ta có :
\(\frac{3x-1}{40-5x}=\frac{25-3x}{5x-34}\)
\(=>\left(3x-1\right)\left(5x-34\right)=\left(40-5x\right)\left(25-3x\right)\)
\(=>15x^2-102x-5x+34=1000-120x-125x+15x^2\)
\(=>15x^2-107x+34=1000-245x+15x^2\)
\(=>34-107x=1000-245x\)
\(=>1000-245x+107x=34\)
\(=>1000-138x=34\)
\(=>138x=1000-34=966\)
\(=>x=\frac{966}{138}=7\)
\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)
\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)
17x + 3. ( -16x – 37) = 2x + 43 - 4x
<=>17x-48x-111=-2x+43
<=>-29x=154
<=> \(x=-\frac{154}{29}\)
-3. (2x + 5) -16 < -4. (3 – 2x)
\(\Leftrightarrow-6x-31< -12+8x.\)
\(\Leftrightarrow-14x< 19\Rightarrow x< -\frac{19}{14}\)
a) 3x – 15 = 25 – 5x
=> 3x + 5x = 25 + 15
=> 8x = 40
=> x = 5
b) 3x - 17 = 2x – 7
=> 3x - 2x = -7 + 17
=> x = 10
c) 2x – 17 = – (3x – 18)
=> 2x - 17 = -3x + 18
=> 2x + 3x = 18 + 17
=> 5x = 35
=> x = 7
d) 3x – 14 = 2(x – 9) + 1
=> 3x - 14 = 2x - 18 + 1
=> 3x - 2x = -18 + 1 + 14
=> x = -3
f) (x – 5)2 = 9
\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
a) Ta có: \(3x-15=25-5x\)
\(\Leftrightarrow3x-15-25+5x=0\)
\(\Leftrightarrow8x-40=0\)
\(\Leftrightarrow8x=40\)
hay x=5
Vậy: x=5
b) Ta có: \(3x-17=2x-7\)
\(\Leftrightarrow3x-17-2x+7=0\)
\(\Leftrightarrow x-10=0\)
hay x=10
Vậy: x=10
c) Ta có: \(2x-17=-\left(3x-18\right)\)
\(\Leftrightarrow2x-17=-3x+18\)
\(\Leftrightarrow2x-17+3x-18=0\)
\(\Leftrightarrow5x-35=0\)
\(\Leftrightarrow5x=35\)
hay x=7
Vậy: x=7
d) Ta có: \(3x-14=2\left(x-9\right)+1\)
\(\Leftrightarrow3x-14=2x-18+1\)
\(\Leftrightarrow3x-14-2x+18-1=0\)
\(\Leftrightarrow x+3=0\)
\(\Leftrightarrow x=-3\)
Vậy: x=-3
f) Ta có: \(\left(x-5\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{2;8\right\}\)
\(\text{Tìm }x\text{ : }\)
\(5x-3x-13=25\)
\(2x-13=25\)
\(2x=25+13\)
\(2x=38\)
\(x=38:2\)
\(x=19\)
5x-3x-13=25
x × (5-3)=25+13
x × 2 =38
x=38:2
x=19
Vậy x=19