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a) (x+1/7):1/3=3/4
=> x+1/7=3/4.1/3
=> x+1/7=1/4
=> x=1/4-1/7
=> x=3/28
b)(1/4+x) :5/7=4/9
(1/4+x) =4/9.5/7
(1/4+x)=20/63
x=20/63-1/4
x=17/252
các phần còn lại cậu tự làm nha giống nhau mà
Câu trả lời của bạn Thủy Thủ Mặt Trăng là đúng hay sai ạ
mn cho mik bt vs
mik cũng đang ko bt bài này
\(a,\)\(\left(5x-15\right)\div5=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
\(b,\)\(84-4\left(2x+1\right)=48\)
\(\Rightarrow84-8x-4=48\)
\(\Rightarrow8x=32\)
\(\Rightarrow x=4\)
\(\frac{2}{5}×\frac{3}{4}+\frac{6}{15}:\frac{4}{9}×5\)
\(=\frac{3}{10}+\frac{6}{15}×\frac{9}{4}×5\)
\(=\frac{3}{10}+\frac{9}{10}×5\)
\(=\frac{3}{10}+\frac{9}{2}\)
\(=\frac{3}{10}+\frac{45}{10}\)
\(=\frac{3+45}{10}\)
\(=\frac{48}{10}=\frac{24}{5}=4,8\)
\(\frac{3}{10}+\frac{9}{10}\cdot5=\frac{3}{10}+\frac{45}{10}=\frac{48}{10}=\frac{24}{5}\)
khong can ghi de bai nha
a) x + 2/3=9/11
<=> x=9/11-2/3= 5/33
b) x - 3/10=4/15
<=> x=4/15+3/10=17/30
c) X x 1/7=5/6
<=> x=5/6:1/7=35/6
d) x : 3/5=1/6
<=> x=1/6x3/5=1/10
\(a,x+\frac{2}{3}=\frac{9}{11}\)
\(x=\frac{9}{11}-\frac{2}{3}\)
\(x=\frac{5}{33}\)
\(b,x-\frac{3}{10}=\frac{4}{15}\)
\(x=\frac{4}{15}+\frac{3}{10}\)
\(x=\frac{17}{30}\)
\(c,x\cdot\frac{1}{7}=\frac{5}{6}\)
\(x=\frac{5}{6}:\frac{1}{7}\)
\(x=\frac{35}{6}\)
\(d,x:\frac{3}{5}=\frac{1}{6}\)
\(x=\frac{1}{6}\cdot\frac{3}{5}\)
\(x=\frac{1}{10}\)
. là nhân nha
b) X x 3,7 + X x 6,3 = 120 |
X x ( 3,7 + 6,3 ) = 120
X x 10 = 120
X = 120 : 10
X = 12
Vậy X = 12
1a)\(\dfrac{14}{3}-\dfrac{11}{4}+\dfrac{80}{11}\)
= \(\dfrac{23}{12}\) + \(\dfrac{80}{11}\)
= \(\dfrac{1213}{132}\)
b \(\dfrac{4}{5}\times\dfrac{15}{16}+\dfrac{5}{2}:\dfrac{20}{9}\)
= \(\dfrac{3}{4}+\dfrac{5}{2}\times\dfrac{9}{20}\)
= \(\dfrac{3}{4}+\dfrac{9}{8}\)
= \(\dfrac{15}{8}\)
b 204 x 307 - 148004 : 209
= 62628 - 708,15311
=61919,846889
\(\frac{5}{3}-\frac{1}{3}:\left(1-x\cdot\frac{1}{3}\right)=\frac{7}{6}\)
=> \(\frac{1}{3}:\left(1-x\cdot\frac{1}{3}\right)=\frac{5}{3}-\frac{7}{6}\)
=> \(\frac{1}{3}:\left(1-x\cdot\frac{1}{3}\right)=\frac{1}{2}\)
=> \(\left(1-x\cdot\frac{1}{3}\right)=\frac{1}{3}:\frac{1}{2}=\frac{1}{3}\cdot2=\frac{2}{3}\)
=> \(1-\frac{x}{3}=\frac{2}{3}\)
=> \(\frac{x}{3}=1-\frac{2}{3}=\frac{1}{3}\)
=> x = 1
\(3-\left(x:\frac{1}{2}+\frac{3}{2}\right)-\frac{1}{4}=\frac{1}{2}\)
=> \(3-\left(x:\frac{1}{2}+\frac{3}{2}\right)=\frac{1}{2}+\frac{1}{4}=\frac{3}{4}\)
=> \(x:\frac{1}{2}+\frac{3}{2}=3-\frac{3}{4}=\frac{9}{4}\)
=> \(x:\frac{1}{2}=\frac{9}{4}-\frac{3}{2}\)
=> \(x:\frac{1}{2}=\frac{3}{4}\)
=> \(x=\frac{3}{4}\cdot\frac{1}{2}=\frac{3}{8}\)
\(\frac{5}{3}-\frac{1}{3}:\left(1-x\times\frac{1}{3}\right)=\frac{7}{6}\)
\(\frac{1}{3}:\left(1-x\times\frac{1}{3}\right)=\frac{5}{3}-\frac{7}{6}\)
\(\frac{1}{3}:\left(1-x\times\frac{1}{3}\right)=\frac{1}{2}\)
\(1-x\times\frac{1}{3}=\frac{1}{3}:\frac{1}{2}\)
\(1-x\times\frac{1}{3}=\frac{2}{3}\)
\(x\times\frac{1}{3}=1-\frac{2}{3}\)
\(x\times\frac{1}{3}=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{1}{3}\)
\(x=1\)
\(3-\left(x:\frac{1}{2}+\frac{3}{2}\right)-\frac{1}{4}=\frac{1}{2}\)
\(3-\left(x:\frac{1}{2}+\frac{3}{2}\right)=\frac{1}{2}+\frac{1}{4}\)
\(3-\left(x:\frac{1}{2}+\frac{3}{2}\right)=\frac{3}{4}\)
\(x:\frac{1}{2}+\frac{3}{2}=3-\frac{3}{4}\)
\(x:\frac{1}{2}+\frac{3}{2}=\frac{9}{4}\)
\(x:\frac{1}{2}=\frac{9}{4}-\frac{3}{2}\)
\(x:\frac{1}{2}=\frac{3}{4}\)
\(x=\frac{3}{4}\times\frac{1}{2}\)
\(x=\frac{3}{8}\)
/x+4/=15-(-4)+(-5)
/x+4/=14
TH1 x+4=14 ->x=10
TH2 x+4=-14->x=-18
|x + 4| - (-5) + (-4) = 15
|x + 4| = 24
x + 4 = 24 => x = 20
x + 4 = -24 => x= -28