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a)
b) \(\dfrac{x^2}{6}=\dfrac{24}{25}\)
\(\Leftrightarrow\left(5x\right)^2=144\)
\(\Leftrightarrow\left(5x\right)^2=12^2\)
\(\Leftrightarrow\left[{}\begin{matrix}5x=12\\5x=-12\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)
c) \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
\(\Leftrightarrow\left(x-2\right)\left(x+7\right)=\left(x-1\right)\left(x+4\right)\)
\(\Leftrightarrow x^2+5x-14=x^2+3x-4\)
\(\Leftrightarrow2x=10\)
\(\Leftrightarrow x=5\)
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a) Trong ba số 6,8,24 có ba cach chọn ra tích của hai trong ba số ấy.Với mỗi tích,có một cách lập đẳng thức với tích của số còn lại và số x. Ta có :
6.8 = 24.x. <=> x = 2
6.24 = 8.x. <=> x = 18
8.24 = 6.x. <=> x = 32
b) Bạn tự lập tỉ lệ thức :))
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1/ \(\frac{1}{3x}:\frac{2}{3}=1\)
<=> \(\frac{3}{3×2×x}=\:1\)
<=> \(\frac{1}{2x}=1\)<=> x = \(\frac{1}{2}\)
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a) \(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{7}{4}:\frac{2}{5}\)
\(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{35}{8}\)
\(\Rightarrow\frac{1}{3}.x=\frac{35}{8}.\frac{2}{3}\)
\(\Rightarrow\frac{1}{3}.x=\frac{35}{12}\)
\(\Rightarrow x=\frac{35}{12}:\frac{1}{3}\)
\(\Rightarrow x=\frac{35}{4}\)
Vậy \(x=\frac{35}{4}\)
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a, \(\frac{x-6}{x+4}=\frac{2}{7}\Rightarrow7x-42=2x+8\)ĐK : \(x\ne-4\)
\(\Leftrightarrow5x=50\Leftrightarrow x=10\)(tm)
b, \(\left(x+5\right):2\frac{1}{2}=\frac{40}{x+5}\)ĐK : \(x\ne-5\)
\(\Leftrightarrow\frac{5\left(x+5\right)}{2}=\frac{40}{x+5}\Rightarrow5\left(x+5\right)^2=80\Leftrightarrow\left(x+5\right)^2=16\)
TH1 : \(x+5=4\Leftrightarrow x=-1\)
TH2 : \(x+5=-4\Leftrightarrow x=-9\)
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a) Đề có bị thiếu không bạn?
b) \(\frac{7}{x-1}=\frac{x+1}{9}\)
\(\Rightarrow7.9=\left(x-1\right).\left(x+1\right)\)
\(\Rightarrow63=x^2+x-x-1\)
\(\Rightarrow63=x^2-1\)
\(\Rightarrow x^2=63+1\)
\(\Rightarrow x^2=64\)
\(\Rightarrow\left[{}\begin{matrix}x=8\\x=-8\end{matrix}\right.\)
Vậy \(x\in\left\{8;-8\right\}.\)
d) \(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\Rightarrow\left(x-1\right).\left(x+3\right)=\left(x-2\right).\left(x+2\right)\)
\(\Rightarrow x^2+3x-x-3=x^2+2x-2x-4\)
\(\Rightarrow x^2+2x-3=x^2-4\)
\(\Rightarrow x^2+2x-3-x^2+4=0\)
\(\Rightarrow2x+1=0\)
\(\Rightarrow2x=0-1\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=\left(-1\right):2\)
\(\Rightarrow x=-\frac{1}{2}\)
Vậy \(x=-\frac{1}{2}.\)
Chúc bạn học tốt!
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a, Ta có: x = 2,5 . 3/5 : 7,5 = 1/5
b, Ta có: x = 3 . 5 : 7 = 15/7
c, Ta có: x = -2 . 37 : 3,6 = -185/9
a) \(2.5\div7.5=x\div\frac{3}{5}\)
\(x\div\frac{3}{5}=\frac{1}{3}\)
\(x=\frac{1}{3}×\frac{3}{5}\)
\(x=\frac{3}{15}=\frac{1}{5}\)
Vậy, \(x=\frac{1}{5}\)
b) \(x\div5=3\div7\)
\(x\div5=\frac{3}{7}\)
\(x=\frac{3}{7}×5\)
\(x=\frac{15}{7}\)
Vậy, \(x=\frac{15}{7}\)
c) \(x\div37=\frac{-2}{3×6}\)
\(x\div37=\frac{-5}{9}\)
\(x=\frac{-5}{9}×37\)
\(x=\frac{-185}{9}\)
Vậy, \(x=\frac{-185}{9}\)
Cbht
\(a,\frac{x-3}{5-x}=\frac{5}{7}\)
\(\Rightarrow\left(x-3\right).7=5\left(5-x\right)\)
\(\Rightarrow7x-21=25-5x\)
\(\Rightarrow12x=46\)
\(\Rightarrow x=\frac{23}{6}\)
\(b,\frac{x-2}{x-1}=\frac{x+4}{x+7}\)
\(\Rightarrow\left(x-2\right)\left(x+7\right)=\left(x+4\right)\left(x-1\right)\)
\(\Rightarrow x^2+7x-2x-14=x^2-x+4x-4\)
\(\Rightarrow x^2+5x-14=x^2+3x-4\)
\(\Rightarrow x^2+5x-x^2-3x=14-4\)
\(\Rightarrow2x=10\)
\(\Rightarrow x=5\)