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a)2,5:7,5=x:3/5
0,(3)=x:3/5
\(\Rightarrow\)x= 1/5
b)x:2,5=0,003;0,75
x:2,5=1/250
\(\Rightarrow\)x=1/100
a) \(\left(\dfrac{1}{4}x\right):3=\dfrac{5}{6}:\dfrac{1}{8}\\ \left(\dfrac{1}{4}x\right):3=\dfrac{20}{3}\\ \dfrac{1}{4}x=\dfrac{20.3}{3}\\ \dfrac{1}{4}x=20\\ x=80\)
a: Ta có: \(\dfrac{0.25x}{3}=\dfrac{5.6}{0.125}\)
\(\Leftrightarrow x\cdot\dfrac{1}{4}=134.4\)
hay x=537,6
b: Ta có: \(\dfrac{2.5}{7.5}=x:\dfrac{3}{5}\)
\(\Leftrightarrow x:\dfrac{3}{5}=\dfrac{1}{3}\)
hay \(x=\dfrac{1}{5}\)
Bài 2:
a:
1: \(\dfrac{a}{b}=\dfrac{c}{d}\)
\(\Leftrightarrow\dfrac{a+b}{a}=\dfrac{c+d}{c}\)
hay \(\dfrac{a}{a+b}=\dfrac{c}{c+d}\)
Lời giải:
a.
$x:27=-2:3,6=\frac{-5}{9}$
$x=27.\frac{-5}{9}=-15$
b.
$\frac{2x+1}{-27}=\frac{-3}{2x+1}$
$\Rightarrow (2x+1)^2=(-27)(-3)=81=9^2=(-9)^2$
$\Rightarrow 2x+1=9$ hoặc $2x+1=-9$
$\Rightarrow x=4$ hoặc $x=-5$
a) \(2,5:7,5=x:\dfrac{3}{5}\)
\(\Rightarrow\dfrac{2,5}{7,5}=\dfrac{x}{\dfrac{3}{5}}\)
\(\Rightarrow x=\dfrac{\dfrac{3}{5}\cdot2.5}{7,5}\)
\(\Rightarrow x=\dfrac{1}{5}\)
b) \(\dfrac{5}{6}:x=20:3\)
\(\Rightarrow\dfrac{\dfrac{5}{6}}{x}=\dfrac{20}{3}\)
\(\Rightarrow x=\dfrac{3\cdot\dfrac{5}{6}}{20}\)
\(\Rightarrow x=\dfrac{1}{8}\)
c) \(2\dfrac{2}{3}:x=1\dfrac{7}{9}\)
\(\Rightarrow\dfrac{8}{3}:x=\dfrac{16}{9}\)
\(\Rightarrow\dfrac{\dfrac{8}{3}}{x}=\dfrac{16}{9}\)
\(\Rightarrow x=\dfrac{\dfrac{8}{3}\cdot9}{16}\)
\(\Rightarrow x=\dfrac{3}{2}\)
a, Ta có: x = 2,5 . 3/5 : 7,5 = 1/5
b, Ta có: x = 3 . 5 : 7 = 15/7
c, Ta có: x = -2 . 37 : 3,6 = -185/9
a) \(2.5\div7.5=x\div\frac{3}{5}\)
\(x\div\frac{3}{5}=\frac{1}{3}\)
\(x=\frac{1}{3}×\frac{3}{5}\)
\(x=\frac{3}{15}=\frac{1}{5}\)
Vậy, \(x=\frac{1}{5}\)
b) \(x\div5=3\div7\)
\(x\div5=\frac{3}{7}\)
\(x=\frac{3}{7}×5\)
\(x=\frac{15}{7}\)
Vậy, \(x=\frac{15}{7}\)
c) \(x\div37=\frac{-2}{3×6}\)
\(x\div37=\frac{-5}{9}\)
\(x=\frac{-5}{9}×37\)
\(x=\frac{-185}{9}\)
Vậy, \(x=\frac{-185}{9}\)
Cbht