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\(a,2\frac{x}{7}=\frac{75}{35}\)
\(\frac{75}{35}=2\frac{5}{35}=2\frac{1}{7}\)
\(\Rightarrow x=1\)
\(b,47:4=...\left(+3\right)\)
\(\Rightarrow\left(47-3\right):4=11\)
\(\Rightarrow x=11\)
\(c,\frac{112}{5}=\frac{336}{15}=22\left(+6\right)\)
\(\Rightarrow x=22\frac{x=6}{15}\)
\(d,7,5x=\frac{75x}{100}:\left(9-6\frac{13}{21}\right)=2\frac{13}{25}\)
\(\frac{75x}{100}:\left(9-\frac{139}{21}\right)=\frac{63}{25}\)
\(\frac{75x}{100}:\frac{50}{21}=\frac{63}{25}\)
\(\Rightarrow\frac{63^3}{25^{\left(1\right)}}\cdot\frac{50^{\left(2\right)}}{21^1}=6=\frac{6}{1}\)
\(\Rightarrow\frac{6}{1}=\frac{600}{100}\)
Con d sai đề
\(a,4\frac{3}{x}=\frac{47}{x}\)
\(\frac{4x+3}{x}=\frac{47}{x}\)
\(\Rightarrow4x^2+3x=47x\)
\(4x^2=47x-3x=44x\)
\(4x^2:4x=44x:4x\)
\(x=11\)
\(b,x\frac{x}{15}=\frac{112}{5}\)
\(\frac{15x+x}{15}=\frac{112}{5}\)
\(75x+5x=112.15\)
\(80x=1680\)
\(x=21\)
a, \(4\frac{3}{x}=\frac{47}{x}\)
\(\Leftrightarrow\frac{4x+3}{x}=\frac{47}{x}\)
\(\Leftrightarrow4x+3=47\)
\(4x=47-3\)
\(4x=44\)
\(x=44:4\)
\(x=11\)
b, \(x\frac{x}{15}=\frac{112}{5}\)
\(\Leftrightarrow\frac{15x+x}{15}=\frac{112}{5}\)
\(\Leftrightarrow\frac{16x}{15}=\frac{336}{15}\)
\(\Leftrightarrow16x=336\)
\(x=336:16\)
\(x=21\)
a) \(\frac{9}{20}\) c) \(\frac{-55}{4}\)
b) \(\frac{116}{75}\) d) \(\frac{-76}{45}\)
đúng hết đấy nhé mình tính kĩ lắm ko sai đâu
chúc may mắn
\(a.-1,52+\frac{2}{47}-x=3.\)
\(\Leftrightarrow\frac{2}{47}-x=4,52\)
\(\Leftrightarrow x=\frac{2}{47}-4,52\)
\(\Leftrightarrow x=-\frac{5261}{1175}\)
\(b.x+3,5-\frac{4}{7}=\frac{3}{2}-1\frac{3}{5}\)
\(\Leftrightarrow x=\frac{3}{2}-\frac{8}{5}-\frac{7}{2}+\frac{4}{7}\)
\(\Leftrightarrow x=-\frac{106}{35}\)
\(c.\left(x:2\frac{1}{8}\right).\frac{1}{6}=-\frac{3}{8}.\left(\frac{1}{2}-1\frac{3}{5}\right)\)
\(\Leftrightarrow\left(x:\frac{17}{8}\right).\frac{1}{6}=-\frac{3}{16}+\frac{3}{5}\)
\(\Leftrightarrow\left(x:\frac{17}{8}\right).\frac{1}{6}=\frac{33}{80}\)
\(\Leftrightarrow x:\frac{17}{8}=\frac{99}{40}\)
\(\Leftrightarrow x=\frac{99}{40}.\frac{17}{8}\)
\(\Leftrightarrow x=\frac{1683}{320}\)
\(2\frac{x}{7}=\frac{75}{35}\)
\(\frac{2.7+x}{7}=\frac{75}{35}\)
\(\frac{14+x}{7}=\frac{75}{35}\)
\(\frac{5\left(14+x\right)}{35}=\frac{75}{35}\)
=>5 ( 14 + x ) = 75
14 + x = 75 : 5
14 + x = 15
x = 15 - 14
x = 1
Vậy x =1