Question

[lê thị thu hoài]

tìm x thuộc Z biết

a. 2x+6 chia hết cho x+2

b. 5x=10 chia hết cho x +5

c. 4x+10 chia hết cho 2x+3

mình đang cần gấp, ai nhanh mình tick cho

trình bày cả lời giải nhé!!!!!

Answer 1

[BW_P&A]

Ta có: \(4x+10⋮2x+3\)

\(\Rightarrow4x+6+4⋮2x+3\)

\(\Rightarrow4x+6⋮2x+3\)

\(\Rightarrow4⋮2x+3\)

\(\Rightarrow2x+3\inƯ_{\left(4\right)}=-4;-2;-1;1;2;4\)

* Nếu: \(2x+3=-4\Rightarrow2x=-7\Rightarrow x=\frac{-7}{2}\)

* Nếu: \(2x+3=-2\Rightarrow2x=-5\Rightarrow x=\frac{-5}{2}\)

* Nếu: \(2x+3=-1\Rightarrow2x=-4\Rightarrow x=-2\)

* Nếu: \(2x+3=1\Rightarrow2x=-2\Rightarrow x=-1\)

* Nếu: \(2x+3=2\Rightarrow2x=-1\Rightarrow x=-\frac{1}{2}\)

* Nếu: \(2x+3=4\Rightarrow2x=1\Rightarrow x=\frac{1}{2}\)

Vậy: \(x=-\frac{7}{2};-\frac{5}{2};-2;-1;-\frac{1}{2};\frac{1}{2}\)

Answer 2

[BW_P&A]

Ta có: \(2x+6⋮x+2\)

\(\Rightarrow2x+4+2⋮x+2\)

\(\Rightarrow2x+4⋮x+2\)

\(\Rightarrow2⋮x+2\)

\(\Rightarrow x+2\inƯ_{\left(2\right)}=-2;-1;1;2\)

\(\Rightarrow\left[\begin{matrix}x+2=-2\\x+2=-1\\x+2=1\\x+2=2\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-4\\x=-3\\x=-1\\x=0\end{matrix}\right.\)

Vậy: \(x=-4;-3;-1;0\)