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Bài làm
a) \(\frac{x}{7}-\frac{3}{7}+\frac{1}{2}=\frac{31}{140}\)
\(\frac{x}{7}=\frac{31}{140}-\frac{1}{2}+\frac{3}{7}\)
\(\frac{x}{7}=\frac{31}{140}-\frac{70}{140}+\frac{60}{140}\)
\(\frac{x}{7}=\frac{21}{140}\)
\(\frac{x}{7}=\frac{3}{20}\)
=> \(x.20=3.7\)
=> \(x=\frac{3.7}{20}\)
=> \(x=\frac{21}{20}\)
Vậy \(x=\frac{21}{20}\)
b) \(\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{2}\)
\(\frac{5}{x}=\frac{1}{2}+\frac{1}{8}-\frac{5}{12}\)
\(\frac{5}{x}=\frac{12}{24}+\frac{3}{24}-\frac{10}{24}\)
\(\frac{5}{x}=\frac{5}{24}\)
=> \(5.24=5.x\)
=> \(x=\frac{5.24}{5}\)
=> \(x=24\)
Vậy \(x=24\)
# Học tốt #
\(x=\dfrac{7}{25}+\dfrac{-1}{5}=\dfrac{7}{25}-\dfrac{1}{5}=\dfrac{2}{25}.\\ x=\dfrac{5}{11}+\dfrac{4}{-9}=\dfrac{5}{11}-\dfrac{4}{9}=\dfrac{1}{99}.\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\Leftrightarrow\dfrac{5}{9}+x=-\dfrac{1}{3}.\Leftrightarrow x=-\dfrac{8}{9}.\)
\(x=\dfrac{7}{25}+-\dfrac{1}{5}=>\dfrac{7}{25}+-\dfrac{5}{25}=>x=\dfrac{2}{25}\)
\(x=\dfrac{5}{11}+\dfrac{4}{-9}=>\dfrac{-45}{-99}+\dfrac{44}{-99}=>x=\dfrac{-1}{-99}=\dfrac{1}{99}\)
\(\dfrac{5}{9}-\dfrac{x}{-1}=-\dfrac{1}{3}=>-\dfrac{1}{3}-\dfrac{5}{9}=>\dfrac{x}{-1}=-\dfrac{8}{9}=>x=-\dfrac{8}{9}\)
\(\frac{x}{4}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)
\(\frac{x}{4}=\frac{31}{140}-\frac{2}{5}+\frac{3}{7}\)
\(\frac{x}{4}=\frac{1}{4}\)
\(\Rightarrow x=1\)
\(\Leftrightarrow\left(x+2\right)^3=343\)
=>x+2=7
hay x=5
(X-140)^3:7^2=4^5-3^2.4^3.
=>(x - 140)3:72 = 45 - 32.43
(x - 140)3 : 49 = 448
(x - 140)3 = 21952 = 282
x - 140 = 28
x = 168
a: =>31-x=60
=>x=-29
b: =>(x-140):35=280-270=10
=>x-140=350
=>x=490
c: =>(1900-2x):35=48
=>1900-2x=1680
=>2x=220
=>x=110
d: =>\(2^{2x-1}=2^9\cdot2=2^{11}\)
=>2x-1=11
=>x=6
e: =>(x+2)^5=4^5
=>x+2=4
=>x=2
f: =>3x-4=0 hoặc x-1=0
=>x=4/3 hoặc x=1
g: =>(2x-1)^2=49
=>2x-1=7 hoặc 2x-1=-7
=>x=-3 hoặc x=4
h: =>x(x+1)/2=78
=>x(x+1)=156
=>x=12
\(a)\frac{x}{4}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)
\(\Leftrightarrow\frac{x}{4}-\frac{1}{35}=\frac{31}{140}\)
\(\Leftrightarrow\frac{x}{4}=\frac{1}{4}\Leftrightarrow x=1\)
\(b)\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{12}\)
\(\Leftrightarrow\frac{5}{x}+\frac{7}{24}=\frac{1}{12}\)
\(\Leftrightarrow\frac{5}{x}=-\frac{5}{24}\Leftrightarrow x=-24\)
Bài làm
\(\frac{x}{3}-\frac{3}{7}+\frac{2}{4}=\frac{31}{140}\)
\(\frac{x}{3}=\frac{31}{140}-\frac{2}{4}+\frac{3}{7}\)
\(\frac{x}{3}=\frac{31}{140}-\frac{70}{140}+\frac{60}{140}\)
\(\frac{x}{3}=\frac{21}{140}\)
\(\frac{x}{3}=\frac{3}{20}\)
=> \(x.20=3.3\)
=> \(x=\frac{3.3}{20}\)
=> \(x=\frac{9}{20}\)
Vậy \(x=\frac{9}{20}\)
# HỌc tốt #
\(\frac{x}{3}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)
\(\frac{x}{3}=\frac{1}{4}\)
x = \(\frac{3}{4}\)