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24 tháng 6 2015

1) 5x + 3 = 2(x + 7)

5x + 3 = 2x + 2.7

5x + 3 = 2x + 14

5x - 2x = 14 - 3

3x        = 11

x          = 11/3

Vậy x = 11/3

2) 5x - 25 = 2x - 3

5x - 2x  =  -3 + 25

3x         =  22

x           = 22/3

Vậy x = 22/3

16 tháng 10 2023

a, 117 - \(x\) = 28 - (-7)

   117 - \(x\) = 28 + 7

    117 - \(x\) = 35

            \(x\) =  117 - 35

             \(x\) = 82

16 tháng 10 2023

b, \(x\) - (-38 - 2\(x\)) = (-3) - 8 + 2\(x\) 

    \(x\) + 38 + 2\(x\) = - 11 + 2\(x\)

   3\(x\)  + 38       = - 11 + 2\(x\)

   3\(x\) - 2\(x\)        = - 11 - 38

   \(x\)                = - 49

   

9 tháng 1 2017

\(a,8x-75=5x+21\)

    \(8x-5x=21+75\)

               \(3x=96\)

                  \(x=32\)

\(b,9x+25=-\left(2x-58\right)\)

    \(9x+25=-2x+58\)

    \(9x+2x=58-25\)

            \(11x=33\)

                 \(x=3\)

\(c,\left(5-x\right).\left(x+2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}5-x=0\\x+2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-2\end{cases}}}\)

5 tháng 2 2018

a) \(8x-75=5x+21\)

\(8x-5x=21+75\)

\(3x=96\)

\(x=32\)

vậy \(x=32\)

b) \(9x+25=-\left(2x-58\right)\)

\(9x+25=-2x+58\)

\(9x+2x=58-25\)

\(11x=33\)

\(x=3\)

vậy \(x=3\)

5 tháng 7 2017

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9 tháng 10 2017

lkl;k

28 tháng 10 2021
Jdjsjsnnsndndndndndnnejejekekeodkndnfndndnnfnfnfnfnndkakwowoeijrhfbd historical đó có bột all of có lúc có là do sốc xó óc đó Úc được xây ff xóc đi h Hà đó ơi clan. Gì ơi có óc cm mà đi mà số of con là clair đó Úc áo
20 tháng 9 2015

nhấn vào đúng 0 sẽ có câu trả lời

olm-logo.png

29 tháng 1 2020

Cái này dễ mà, nên tự làm đi 😂😂😂

13 tháng 7 2016

a) <=> 2x - 1 = 0 hoặc 5x + 2 = 0

<=> 2x = 1 hoặc 5x = -2

<=> x = \(\frac{1}{2}\) hoặc x = \(-\frac{2}{5}\)

b) <=> 3/7 . (1 + 1/x) = 1/4

=> 1 + 1/x = 7/12      <=> 1/x = -5/12 

<=> -5/-5x = -5/12     <=> -5x = 12 

<=> x = \(-\frac{12}{5}\)

c) Dễ thấy 3x + 5 > 2x - 3

Để (3x + 5)( 2x - 3) < 0 thì 3x + 5 > 0 và 2x - 3 < 0

<=> x > -5/3 và x < 3/2

Vậy \(-\frac{5}{3}< x< \frac{3}{2}\)

13 tháng 7 2016

a) (2x-1).(5x+2) = 0

\(\Leftrightarrow\) 2x-1 = 0  hoặc  5x+2 = 0

\(\Leftrightarrow\) 2x    = 1  hoặc  5x     = -2

\(\Leftrightarrow\)   x    = \(\frac{1}{2}\) hoặc   x      = \(\frac{-2}{5}\)

b) \(\frac{3}{7}+\frac{3}{7}:x=\frac{-1}{2}-\left(\frac{-3}{4}\right)\)

     \(\frac{3}{7}+\frac{3}{7}:x=\frac{-1}{2}+\frac{3}{4}\)

     \(\frac{3}{7}+\frac{3}{7}:x=\frac{1}{4}\)

            \(\frac{3}{7}:x=\frac{1}{4}-\frac{3}{7}\)

            \(\frac{3}{7}:x=\frac{-5}{28}\)

                  \(x=\frac{3}{7}:\frac{-5}{28}\)

                  \(x=\frac{-12}{5}\)

2 tháng 4 2020

\((x-6)(3x-9)>0\)
TH1:
\(\orbr{\begin{cases}x-6< 0\\3x-9< 0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x< 6\\x< 3\end{cases}}\)\(\Rightarrow x< 3\)
TH2:
\(\orbr{\begin{cases}x-6>0\\3x-9>0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x>6\\x>3\end{cases}}\)\(\Rightarrow x>6\)
Vậy \(x< 3\) hoặc \(x>6\)thì \((x-6)(3x-9)>0\)
Học tốt!

2 tháng 4 2020

20.
\((2x-1)(6-x)>0\)
TH1:
\(\orbr{\begin{cases}2x-1>0\\6-x>0\end{cases}\Rightarrow\orbr{\begin{cases}x< \frac{1}{2}\\x< 6\end{cases}}\Rightarrow x< 6}\)
TH2
\(\orbr{\begin{cases}2x-1< 0\\6-x< 0\end{cases}\Rightarrow\orbr{\begin{cases}x>\frac{1}{2}\\x>6\end{cases}}\Rightarrow x>\frac{1}{2}}\)
Vậy \(x< 6\)hoặc \(x>\frac{1}{2}\)thì \((2x-1)(6-x)>0\)