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Ta có: \(\frac{1}{2}.x+\frac{3}{5}.\left(x-2\right)=3\)
\(\Rightarrow\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)
\(\Rightarrow\frac{11}{10}x-\frac{6}{5}=3\)
\(\Rightarrow\frac{11}{10}x=3+\frac{6}{5}=\frac{21}{5}\)
\(\Rightarrow x=\frac{21}{5}:\frac{11}{10}=\frac{42}{11}\)
Vậy \(x=\frac{42}{11}\)
Ủng hộ tớ nha?
\(3\times x-x\times2=7\frac{3}{8}+\frac{5}{8}\)
\(x\left(3-2\right)=8\)
\(x=8\)
3 nhân x - x nhân 2 = 7 3/8 + 5/8
x nhân (3-2) = 7 3/8 + 5/8
x = 7 3/8 + 5/8
Ta có:
1/3 x X + 2/5 x ( X-1) = 4
1/3 x X + 2/5 x X - 2/5 = 4
X x ( 1/3 + 2/5 ) - 2/5 = 4
X x 11/15 = 4 + 2/5
X x 11/15 = 22/5
X = 22/5 : 11/5
X = 2
k mình nha :)
1) \(2^x-15=17\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
2) \(\left(7x-11\right)^3=25\cdot5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=825\)
\(\Leftrightarrow7x-11=\sqrt[3]{825}\)
\(\Leftrightarrow7x=11+\sqrt[3]{825}\)
\(\Rightarrow x=\frac{11+\sqrt[3]{825}}{7}\)
3) \(\left(x+1\right)^{100}-3\left(x+1\right)^{99}=0\)
\(\Leftrightarrow\left(x+1\right)^{99}\left(x-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)^{99}=0\\x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=2\end{cases}}\)
4) \(4x+5\left(x+3\right)=105\)
\(\Leftrightarrow9x+15=105\)
\(\Leftrightarrow9x=90\)
\(\Rightarrow x=10\)
5) \(5\cdot\left(x-2\right)+10\left(x+3\right)=170\)
\(\Leftrightarrow5\left[x-2+2\left(x+3\right)\right]=170\)
\(\Leftrightarrow3x+4=34\)
\(\Leftrightarrow3x=30\)
\(\Rightarrow x=10\)
Bài làm
\(\frac{1}{2}.\frac{x+3}{5}.\left(x-2\right)=3\)
Bài làm
xl, vừa r bấm nhầm.
\(\frac{1}{2}.\frac{x+3}{5}.\left(x-2\right)=3\)
\(\frac{x+3}{10}.\left(x-2\right)=3\)
\(\frac{x^2-2x+3x-6}{10}=3\)
\(x^2-2x+3x-6=3.10\)
\(x^2+x-6=30\)
\(x^2+x-36=0\)