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1)
\(\frac{3}{4}.x+\frac{x}{5}=\frac{1}{6}\)
\(x.\left(\frac{3}{4}+\frac{1}{5}\right)=\frac{1}{6}\)
\(x.\frac{19}{20}=\frac{1}{6}\)
\(x=\frac{1}{6}:\frac{19}{20}\)
\(x=\frac{10}{57}\)
2)
\(x+3\frac{1}{2}+x=24\frac{1}{4}\)
\(2x+3\frac{1}{2}=24\frac{1}{4}\)
\(2x=24\frac{1}{4}-3\frac{1}{2}\)
\(2x=\frac{83}{4}\)
\(x=\frac{83}{4}:2\)
\(x=\frac{83}{8}\)
a.
\(\frac{4}{7}x-\frac{2}{3}=\frac{1}{5}\)
\(\frac{4}{7}x=\frac{1}{5}+\frac{2}{3}\)
\(\frac{4}{7}x=\frac{3+10}{15}\)
\(\frac{4}{7}x=\frac{13}{15}\)
\(x=\frac{13}{15}\div\frac{4}{7}\)
\(x=\frac{13}{15}\times\frac{7}{4}\)
\(x=\frac{91}{60}\)
b.
\(\frac{2}{9}+\frac{7}{8}x=\frac{1}{3}\)
\(\frac{7}{8}x=\frac{1}{3}-\frac{2}{9}\)
\(\frac{7}{8}x=\frac{3-2}{9}\)
\(\frac{7}{8}x=\frac{1}{9}\)
\(x=\frac{1}{9}\div\frac{7}{8}\)
\(x=\frac{1}{9}\times\frac{8}{7}\)
\(x=\frac{8}{63}\)
Chúc bạn học tốt
b) \(\frac{2}{9}+\frac{7}{8}.x=\frac{1}{3}\)
\(\frac{1}{3}-\frac{2}{9}=\frac{7}{8}.x\)
\(\frac{7}{8}.x=\frac{1}{9}\)
\(x=\frac{1}{9}:\frac{7}{8}\)
\(x=\frac{8}{63}\)
c) \(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{3}\)
\(\frac{5}{7}:x=\frac{1}{3}-\frac{4}{5}\)
\(\frac{5}{7}:x=\frac{-7}{15}\)
\(x=\frac{5}{7}:\frac{-7}{15}\)
\(x=\frac{75}{-49}\)
b) \(\frac{2}{9}+\frac{7}{8}x=\frac{1}{3}\)
\(\frac{7}{8}x=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)
\(x=\frac{1}{9}:\frac{7}{8}=\frac{8}{63}\)
c) \(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{3}\)
\(\frac{5}{7}:x=\frac{1}{3}-\frac{4}{5}=-\frac{7}{15}\)
\(x=\frac{5}{7}:\left(-\frac{7}{15}\right)=-\frac{75}{49}\)
\(x.3\frac{1}{4}+\left(\frac{-7}{6}\right)x-1\frac{2}{3}=\frac{5}{12}\)
\(x.\frac{13}{4}+\left(\frac{-7}{6}\right)x-\frac{5}{3}=\frac{5}{12}\)
\(x\left[\frac{13}{4}+\left(\frac{-7}{6}\right)\right]-\frac{5}{3}=\frac{5}{12}\)
\(x\frac{25}{12}-\frac{5}{3}=\frac{5}{12}\)
\(x\frac{25}{12}=\frac{5}{12}+\frac{5}{3}\)
\(x\frac{25}{12}=\frac{25}{12}\)
\(x=\frac{25}{12}:\frac{25}{12}\)
\(x=1\)
a) 2 - ( \(5\frac{3}{8}\)x X - \(\frac{5}{24}\)) = \(\frac{5}{12}\)
\(5\frac{3}{8}\)x X - \(\frac{5}{24}\)= \(\frac{19}{12}\)
\(5\frac{3}{8}\)x X = \(\frac{43}{24}\)
X = \(\frac{1}{3}\)
b) \(1\frac{2}{9}\): ( \(3\frac{1}{3}\)x X + \(\frac{1}{6}\)) = \(\frac{22}{23}\)
\(3\frac{1}{3}\)x X + \(\frac{1}{6}\) = \(\frac{23}{18}\)
\(3\frac{1}{3}\)x X = \(\frac{10}{9}\)
X =\(\frac{1}{3}\)
C) \(\frac{4}{5}\)x X - \(\frac{1}{2}\)x X + \(\frac{3}{4}\)x X = \(\frac{7}{40}\)
( \(\frac{4}{5}-\frac{1}{2}+\frac{3}{4}\)) x X = \(\frac{7}{40}\)
\(\frac{21}{20}\) x X = \(\frac{7}{40}\)
X =\(\frac{1}{6}\)
Ta có: \(\frac{1}{2}.x+\frac{3}{5}.\left(x-2\right)=3\)
\(\Rightarrow\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)
\(\Rightarrow\frac{11}{10}x-\frac{6}{5}=3\)
\(\Rightarrow\frac{11}{10}x=3+\frac{6}{5}=\frac{21}{5}\)
\(\Rightarrow x=\frac{21}{5}:\frac{11}{10}=\frac{42}{11}\)
Vậy \(x=\frac{42}{11}\)
Ủng hộ tớ nha?
đúng k zậy bạn?^^