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720 : [41-(2x-5)] =2^3 . 5
<=> 41-(2x-5)=720:40=18
<=> 2x-5=41-18=23
<=>2x=23+5=28
<=> x=28:2=14
2^x-15=17
<=> 2^x=17+15=32
<=> 2^x=2^5
<=> x=5
(7x-11)^3= 2^5.5^2+200
<=> (7x-11)^3=1000
<=> (7x-11)^3=10^3
<=> 7x-11=10
<=> 7x=10+11=21
<=> x=21:7=3
a: Ta có: \(7x+25=144\)
\(\Leftrightarrow7x=119\)
hay x=17
b: Ta có: \(33-12x=9\)
\(\Leftrightarrow12x=24\)
hay x=2
c: Ta có: \(128-3\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=105\)
\(\Leftrightarrow x+4=35\)
hay x=31
d: Ta có: \(71+\left(726-3x\right)\cdot5=2246\)
\(\Leftrightarrow5\left(726-3x\right)=2175\)
\(\Leftrightarrow726-3x=435\)
\(\Leftrightarrow3x=291\)
hay x=97
e: Ta có: \(720:\left[41-\left(2x+5\right)\right]=40\)
\(\Leftrightarrow41-\left(2x+5\right)=18\)
\(\Leftrightarrow2x+5=23\)
\(\Leftrightarrow2x=18\)
hay x=9
720:[41-(2x - 5)]=23.5
720:[41-(2x - 5)]=8.5
720:[41-(2x - 5)]=40
41-(2x - 5)=720:40
41-(2x - 5)=18
2x - 5=41-18
2x - 5=23
2.x=23+5
2.x=28
x=28:2
x=14
a)
<=> 720 : [ 41 - ( 7x^2 - 5 ) ] = 40
<=> 41 - ( 7x^2 - 5 ) = 720 : 40
<=> 41 - ( 7x^2 - 5 ) = 18
<=> 7x^2 - 5 = 41 - 18
<=> 7x^2 - 5 = 23
<=> 7x^2 = 23 + 5
<=> 7x^2 = 28
<=> x^2 = 28 : 7
<=> x^2 = 4
<=> x^2 = 2^2
<=> x = 2
b) 10: 1/10
40: 1/40
88: 1/88
154: 1/154
238: 1/238
Rồi b tách mẫu số ra như sau:
\(\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+\frac{1}{154}+\frac{1}{238}\)
=> \(\frac{1}{2\times5}+\frac{1}{5\times8}+\frac{1}{8\times11}+\frac{1}{11\times14}+\frac{1}{14\times17}\)
Đó rồi tính tiếp nha
a, 41-(7x^2-5)=720:40=18
7x^2-5=41-18=23
7x^2=23+5=28
x^2=28:7=4
x= 2 và -2
b, luôn bằng 0 có tính chất
a) 720:[41-(2x-5)]=8*5
720:[41-(2x-5)]=40
41-(2x-5) = 720:40
41-(2x-5) = 18
2x-5 =41-18
2x-5 =23
2x =23+5
2x =28
x =28:2
x=14
b) x+(x+1)+(x+2)+......+(x+30)=1240
x+x+1+x+2+...+x+30=1240
(x+x+x+....+x) + (1+2+3+....30)=1240
31*x + \(\frac{\left(30+1\right)\cdot30}{2}\)=1240
31*x + 465 =1240
31*x=1240-465
31*x =775
x = 775:31
x=25
tick mình nhé
720 : [ 41- ( 7\(x^2\) - 5)].22 = 62
720:[ 41 - (7\(x^2\) - 5)] = 62:22
720:[ 41 - (7\(x^2\) - 5)] = 9
41 - (7\(x^2\) - 5) = 720 : 9
41 - (7\(x^2\) - 5) = 80
7\(x^2\) - 5 = 41 - 80
7\(x^2\) - 5 = - 39
7\(x^2\) = - 39 + 5
7\(x^2\) = -34
7\(x^2\) ≥ 0 ∀ \(x\)
vậy 7\(x^2\) = - 34 ( vô nghiệm)
kl : \(x\in\) \(\varnothing\)
THAM KHẢO NHÉ
720÷[41−(2x−5)]=23.5720÷[41−(2�−5)]=23.5
⇒720÷[41−(2x−5)]=40⇒720÷[41−(2�−5)]=40
⇒41−(2x−5)=720÷40⇒41−(2�−5)=720÷40
⇒41−(2x−5)=18⇒41−(2�−5)=18
⇒2x−5=41−18⇒2�−5=41−18
⇒2x−5=23⇒2�−5=23
⇒2x=23+5⇒2�=23+5
⇒2x=28⇒2�=28
⇒x=28÷2⇒�=28÷2
⇒x=14