Question

[yen tran]

Tìm x biết 

4\(\frac{1}{3}\)( \(\frac{1}{6}\)-\(\frac{1}{2}\)) \(\le\)x\(\le\)\(\frac{2}{3}\)( \(\frac{1}{2}\)-\(\frac{1}{3}\)-\(\frac{1}{4}\)) với x \(\in\)\(ℤ\)

Answer 1

[I don't need you]

\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\le x\le\frac{2}{3}.\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{4}\right)\)

\(\frac{13}{3}.\frac{-1}{3}\le x\le\frac{2}{3}.\frac{-1}{12}\)

\(\frac{-13}{9}\le x\le\frac{-1}{18}\)

\(\Rightarrow\frac{-26}{18}\le x\le\frac{-1}{18}\)

\(\Rightarrow x\in\left(\frac{-26}{18};...;\frac{-18}{18};...\frac{-1}{18}\right)\)

mà x phải thuộc Z

\(\Rightarrow x=\frac{-18}{18}=-1\)

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