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1)
<=> 15 - x + 7 = -21
<=> -x = -21 - 15 - 7
<=> -x = -43
<=> x = 43
Các câu sau phá ngoặc đổi dấu, chuyển vế đổi dấu thôi kh có gì đâu
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Câu cuối:
<=> -13 - 6 + x + 1 = 24
<=> x = 24 + 13 + 6 - 1
<=> x = 42
a) \(x\cdot25=5^3\)
\(x\cdot25=125\)
\(x=\frac{125}{25}\)
\(x=5\)
b) \(6^x:6^2=6^4\)
\(6^x=6^4\cdot6^2\)
\(6^x=6^6\)
\(x=6\)
c) \(3x=27\)
\(x=27:3\)
\(x=9\)
d) \(5^x+1=125\)
\(5^x=124\)
...
e) \(x\cdot36=6^8\)
\(x=6^8:6^2\)
\(x=6^6\)
\(x=46656\)
g) \(7^x+1:7^2=7^9\)
\(7^x=7^9-\frac{1}{7^2}\)
......
a, x = 125: 25 =5
b , 6 ^x =6^4 . 6^2
6^x =6^6
=> x =6
c, 3x = 27
=> 3x = 3 .9
=> x = 9 ( vì 3 =3 )
d, 5^x +1 =125
5 ^ x+1 =5^3
=>x +1 =3
=>x=2
e, x. 36 =6 ^8
x . 6^2 = 6^8
x = 6^8 : 6^2
x= 6^6
g , 7^x+1 : 7^2 = 7^9
7^x+1 = 7^2+9
7^x +1=7^ 11
=>x +1 =11
=> x =10
Bui Bao Ngoc oi! phan a,la (x+1)/10 hay x+(1/10)?
cac phan khac nua!
b) \(\left(-x+7\right)^3=-27\)
\(\left(-x+7\right)^3=\left(-3\right)^3\)
\(\Rightarrow-x+7=-3\)
\(\Rightarrow-x=-3-7=-10\)
\(\Rightarrow x=10\)
b) \(\left|x+3\right|\left(x-7\right)< 0\)
Ta có: \(\left|x+3\right|\ge0\)
Mà theo đề bài\(\left|x+3\right|\left(x-7\right)< 0\)
Nên \(x-7< 0\)
\(\Rightarrow x< 7\)
1) 9-25=(7-x)-(25+7)
(7-x)-(25+7)=9-25
(7-x)-(25+7)=-16
(7-x)-32=-16
7-x=-16+32
7-x=16
x=7-16
x=-9
2) (27-514) -(486-73)+x=7
(27-514) -(486-73)+x=7
-487-413+x=7
-1011+x=7
x=7-(-1011)
x=7+1011
x=1018
3) 25+5+37-25+6-29-x=37
25+5+37-25+6-29-x=37
67-25+6-29-x=37
42+6-29-x=37
48-29-x=37
19-x=37
x=19-37
x=-18
4) 14+(-12)+x =10-/-15/+ /-3/
14+(-12)+x =10-15+3
14+(-12)+x =-5+3
14+(-12)+x =-2
2+x=-2
x=-2-2
x=-4
1) \(A=\frac{7}{10\times11}+\frac{7}{11\times12}+\frac{7}{12\times13}+...+\frac{7}{69\times70}\)
\(A=7\times\left(\frac{1}{10\times11}+\frac{1}{11\times12}+\frac{1}{12\times13}+...+\frac{1}{69\times70}\right)\)
\(A=7\times\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)
\(A=7\times\left(\frac{1}{10}-\frac{1}{70}\right)\)
\(A=7\times\frac{3}{35}\)
\(A=\frac{3}{5}\)
2) \(B=\frac{1}{25\times27}+\frac{1}{27\times29}+\frac{1}{29\times31}+...+\frac{1}{73\times75}\)
\(B=\frac{1}{2}\times\left(\frac{2}{25\times27}+\frac{2}{27\times29}+\frac{2}{29\times31}+...+\frac{2}{73\times75}\right)\).
\(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\times\frac{2}{75}\)
\(B=\frac{1}{75}\)
3) \(C=\frac{4}{2\times4}+\frac{4}{4\times6}+\frac{4}{6\times8}+...+\frac{4}{2008\times2010}\)
\(C=\frac{4}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{2008\times2010}\right)\)
\(C=2\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2008}-\frac{1}{2010}\right)\)
\(C=2\times\left(\frac{1}{2}-\frac{1}{2010}\right)\)
\(C=2\times\frac{502}{1005}\)
\(C=\frac{1004}{1005}\)
_Chúc bạn học tốt_
1/4+1/3:(2x-1)=-5
-->1/3:(2x-1)=-5-1/4
-->1/3:(2x-1)=-21/4
-->2x-1 =1/3:-21/4
-->2x-1 =-4/63
-->2x =-4/63+1
-->2x =59/63
--x =59/126
b7/9:(2+3/4x)+5/9=23/27
-->7/9:(2+3/4x) =23/27-5/9
-->7/9:(2+3/4x) =8/27
-->2+3/4x =7/9:8/27
-->2+3/4x =21/8
-->3/4x =21/8-2
-->3/4x =5/8
-->x =5/8:3/4
-->x =5/6
c|2x-1/3|+5/6=1
-->|2x-1/3| =1-5/6
-->|2x-1/3| =1/6
-->\(\orbr{\begin{cases}2x-\frac{1}{3}=\frac{1}{6}\\2x-\frac{1}{3}=-\frac{1}{6}\end{cases}}\)
-->\(\orbr{\begin{cases}2x=\frac{1}{6}+\frac{1}{3}\\2x=-\frac{1}{6}+\frac{1}{3}\end{cases}}\)
-->\(\orbr{\begin{cases}2x=\frac{1}{2}\\2x=\frac{1}{6}\end{cases}}\)
-->\(\orbr{\begin{cases}x=\frac{1}{2}:2\\x=\frac{1}{6}:2\end{cases}}\)
-->\(\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{1}{12}\end{cases}}\)
\(\frac{6}{x+27}=-\frac{7}{x+1}\)
\(\Rightarrow6\left(x+1\right)=-7\left(x+27\right)\)
\(6x+6=-7x+\left(-189\right)\)
\(6x+7x=-189-6\)
\(13x=195\)
\(x=195:13\)
\(x=15\)
Vậy \(x=15\)
Ta có: \(\frac{6}{x+27}=\frac{-7}{x+1}\)
\(\Leftrightarrow6\cdot\left(x+1\right)=-7\cdot\left(x+27\right)\)
\(\Leftrightarrow6x+6=-7x-189\)
\(\Leftrightarrow6x+7x=-189-6\)
\(\Leftrightarrow13x=-195\)
\(\Leftrightarrow x=-15\)
Vậy \(x=-15\)
\(\approx GOOD\)\(LUCK\approx\)
Bạn ghi lại đề ... bằng cách gõ cthưc giùm mk