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a) \(6-2x-8=-4\Leftrightarrow2x=2\Leftrightarrow x=1\)
b) \(6⋮x\Rightarrow x=\left\{-6;-3;-2;-1;1;2;3;6\right\}\)
c) \(2x-3=-7\Leftrightarrow2x=-4\Leftrightarrow x=-2\)
d) \(231-x+6=103\Leftrightarrow x=124\)
e) hình như sai đề
f) \(x^3=27\Leftrightarrow x=3\)
g) \(x+2=3\Leftrightarrow x=1\)
h) \(\left(x+5\right)^2=25\Leftrightarrow x+5=5\Leftrightarrow x=0\)
i) \(x^2=9\Leftrightarrow\orbr{\begin{cases}x=-3\\x=3\end{cases}}\)
j) \(14⋮\left(x+3\right)\Rightarrow x=\left\{-17;-10;-5;-4;-2;4;11\right\}\)
1: =>5(2x+6)=40
=>2x+6=8
=>2x=2
=>x=1
2: =>12-(x+3)=256:64=4
=>(x+3)=8
=>x=5
3: =>2x-1=3 hoặc 2x-1=-3
=>x=2 hoặc x=-1
4: \(\Leftrightarrow3^{x+2017}=3^{2015}\)
=>x+2017=2015
=>x=-2
1) 2x . 4 = 128
2x = 128 : 4
2x = 32
2x = 25
=> x = 5
2) (2x + 1)3 = 125
(2x + 1)3 = 53
=> 2x + 1 = 5
2x = 5 - 1
2x = 4
x = 2
các bài khác bạn tự làm nha
nhiều quá :((
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(-x=45\)
\(x=45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36==12\)
\(3x=48\)
\(x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(3x-12-8+x=0\)
\(4x-20=0\)
\(4x=20\)
\(x=5\)
Cố nốt nha bn !
cảm ơn, bn nha:)))
mà hình như bạn TOP 3 trả lời câu hỏi pải ko nhỉ???
\(7^6+7^5-7^4\)
\(=7^4\left(7^2+7-1\right)\)
\(=7^4\cdot55⋮55\)
\(16^5+2^5\)
\(=\left(2^4\right)^5+2^5\)
\(=2^{20}+2^5\)
\(=2^5\left(2^{15}+1\right)\)
\(=2^5\cdot32769⋮33\)
Với tất cả các câu, mk chỉ làm ngắn gọn. Nếu bn muốn đầy đủ, thì bn tự lập bảng rồi xét.
1. \(13⋮\left(x-3\right)\)
\(\Leftrightarrow\left(x-3\right)\inƯ\left(13\right)=\left\{\pm1;\pm13\right\}\)
\(\Rightarrow x\in\left\{2;4;-10;16\right\}\)
Vậy x = ......................
2. \(\left(x+13\right)⋮\left(x-4\right)\)
\(\Leftrightarrow\left(x-4\right)+17⋮\left(x-4\right)\)
\(\Leftrightarrow17⋮x-4\)
\(\Leftrightarrow\left(x-4\right)\inƯ\left(17\right)=\left\{\pm1;\pm17\right\}\)
\(\Rightarrow x\in\left\{3;5;-13;21\right\}\)
Vậy x = ...................
3. \(\left(2x+108\right)⋮\left(2x+3\right)\)
\(\Leftrightarrow\left(2x+3\right)+105⋮\left(2x+3\right)\)
\(\Leftrightarrow105⋮\left(2x+3\right)\)
\(\Leftrightarrow\left(2x+3\right)\inƯ\left(105\right)\)\(=\left\{\pm1;\pm3;\pm5;\pm7;\pm15;\pm21;\pm35;\pm105\right\}\)
\(\Rightarrow x=-2;-1;-3;0;-4;1;-5;2;...............\)
4. \(17x⋮15\)
\(\Leftrightarrow x⋮15\) ( vì \(\left(15,17\right)=1\) )
Do đó : Với mọi x thuộc Z thì \(17x⋮15\)
6. \(\left(x+16\right)⋮\left(x+1\right)\)
\(\Leftrightarrow\left(x+1\right)+15⋮\left(x+1\right)\)
\(\Leftrightarrow15⋮\left(x+1\right)\)
\(\Leftrightarrow\left(x+1\right)\inƯ\left(15\right)=\left\{\pm1;\pm3;\pm5;\pm15\right\}\)
\(\Rightarrow x\in\left\{-2;0;-4;2;-6;4;-16;14\right\}\)
Vậy x = .....................
7. \(x⋮\left(2x-1\right)\)
Mà \(\left(2x-1\right)\) lẻ
Nên : Với mọi x thuộc Z là số lẻ thì \(x⋮\left(2x-1\right)\)
8. \(\left(2x+3\right)⋮\left(x+5\right)\)
\(\Leftrightarrow\left(2x+10\right)-7⋮\left(x+5\right)\)
\(\Leftrightarrow2.\left(x+5\right)-7⋮\left(x+5\right)\)
\(\Leftrightarrow7⋮\left(x+5\right)\)
\(\Leftrightarrow\left(x+5\right)\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
\(\Rightarrow x\in\left\{-6;-4;-12;2\right\}\)
Vậy x = .........................
a)13-2(x+1)=7
2.(x+1)=13-7
2.(x+1)=6
x+1=6/2
x+1=3
x=3-1
x=2
a, 13 - 2 ( x + 1 ) = 7
2 .( x + 1 ) = 13 - 7
2 .( x + 1 ) = 6
x + 1 = 6 : 2
x + 1 = 3
x = 3 - 1
x = 4
a) \(6-2\left(x+4\right)=-4\)
\(\Leftrightarrow6-2x-8=-4\)
\(\Leftrightarrow-2-2x=-4\)
\(\Leftrightarrow-2x=-4+2\)
\(\Leftrightarrow-2x=-2\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
b) tự làm.
c) \(2x-15:5=-7\)
\(\Leftrightarrow2x-7,5=-7\)
\(\Leftrightarrow2x=-7+7,5\)
\(\Leftrightarrow2x=0,5\)
\(\Leftrightarrow x=0,25\)
\(\Leftrightarrow x=\dfrac{1}{4}\)
Vậy \(x=\dfrac{1}{4}\)
d) \(231-\left(x-6\right)=1339:13\)
\(\Leftrightarrow231-x+6=103\)
\(\Leftrightarrow237-x=103\)
\(\Leftrightarrow237-x+6=103\)
\(\Leftrightarrow-x=103-237\)
\(\Leftrightarrow-x=-134\)
\(\Leftrightarrow x=134\)
e) đề j mà có 2 dấu bằng >> sai :v
f) \(28-x^3=1\)
\(\Leftrightarrow-x^3=1-28\)
\(\Leftrightarrow-x^3=-27\)
\(\Leftrightarrow x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
Vậy \(x=3\)
g) \(\left(x+2\right)^3=27\)
\(\Leftrightarrow\left(x+2\right)^3=3^3\)
\(\Leftrightarrow x+2=3\)
\(\Leftrightarrow x=3-2\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
h) \(81-\left(x-5\right)^2=56\)
\(\Leftrightarrow-\left(x-5\right)^2=56-81\)
\(\Leftrightarrow-\left(x-5\right)^2=-25\)
\(\Leftrightarrow\left(x-5\right)^2=25\)
\(\Leftrightarrow x-5=\pm5\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=5\\x-5=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5+5\\x=-5+5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=0\end{matrix}\right.\)
Vậy \(x_1=0;x_2=10\)
j) \(x^2=9\)
\(\Leftrightarrow x=\pm3\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy \(x_1=-3;x_2=3\)
l) tự làm.
(x-12):6=3
x^2-1=3
mình nhâm