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Bài 1 :
\(\frac{x-1}{x-5}=\frac{6}{7}\Leftrightarrow7x-7=6x-30\)
\(\Leftrightarrow x=-23\)
\(\frac{x-2}{x-1}=\frac{x+4}{x+7}\)ĐK : \(x\ne1;-7\)
\(\Leftrightarrow\left(x-2\right)\left(x+7\right)=\left(x+4\right)\left(x-1\right)\)
\(\Leftrightarrow x^2+5x-14=x^2+3x-4\)
\(\Leftrightarrow2x-10=0\Leftrightarrow x=5\)
\(\frac{x-2}{5}+\frac{x-3}{4}=\frac{x-4}{3}+\frac{x-5}{2}\)
=> \(\frac{x-2}{5}-1+\frac{x-3}{4}-1=\frac{x-4}{3}-1+\frac{x-5}{2}-1\)
=> \(\frac{x-7}{5}+\frac{x-7}{4}=\frac{x-7}{3}+\frac{x-7}{2}\)
=> \(\frac{x-7}{5}+\frac{x-7}{4}-\frac{x-7}{3}-\frac{x-7}{2}=0\)
=> \(\left(x-7\right).\left(\frac{1}{5}+\frac{1}{4}-\frac{1}{3}-\frac{1}{2}\right)=0\)
=> x-7 = 0
=> x= 7
a, \(\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}5x-1=0\\2x-\frac{1}{3}=0\end{cases}\Rightarrow}\orbr{\begin{cases}5x=1\\2x=\frac{1}{3}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{1}{6}\end{cases}}\)
b. \(\left(x^2+1\right)\left(x-4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x^2+1=0\\x-4=0\end{cases}\Rightarrow}\orbr{\begin{cases}x^2=-1\left(Voly\right)\\x=4\end{cases}\Rightarrow x=4}\)
c, \(2x^2-\frac{1}{3}x=0\)
\(\Leftrightarrow x\left(2x-\frac{1}{3}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\2x-\frac{1}{3}=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{6}\end{cases}}\)
d, \(\left(\frac{4}{5}\right)^{5x}=\left(\frac{4}{5}\right)^7\)
\(\Rightarrow5x=7\)
\(\Rightarrow x=\frac{7}{5}\)
e, Ta có: \(A=\frac{x+5}{x-2}=\frac{\left(x-2\right)+7}{x-2}=1+\frac{7}{x-2}\)
Để A ∈ Z <=> (x - 2) ∈ Ư(7) = { ±1; ±7 }
x - 2 | 1 | -1 | 7 | -7 |
x | 3 | 1 | 9 | -5 |
Vậy....
a) \(\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}5x-1=0\\2x-\frac{1}{3}=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}5x=1\\2x=\frac{1}{3}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{1}{6}\end{cases}}\)
Vậy : ....
b) \(\left(x^2+1\right)\left(x-4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2+1=0\\x-4=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x^2=-1\left(loại\right)\\x=4\end{cases}}\)
c) \(2x^2-\frac{1}{3}x=0\)
\(\Leftrightarrow x\left(2x-\frac{1}{3}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\2x-\frac{1}{3}=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{6}\end{cases}}\)
Vậy :...
4 ( x- 1 0 ) - 3 ( 5 +x ) + 2 ( 4x- 3 ) = 5. ( x- 2 )
4x - 40 - 15 - 3x + 8x - 6 = 5x - 10
4x - 3x + 8x - 5x = -10 + 40 + 15 + 6
4x = 51
x = 51/4
tick đúng cho mình nha
bài 1 : a,ta có 3/x-1 =4/y-2=5/z-3 => x-1/3=y-2/4=z-3/5
áp dụng .... => x-1+y-2+z-3 / 3+4+5 = x+y+z-1-2-3/3+4+5 = 12/12=1
do x-1/3 = 1 => x-1 = 3 => x= 4 ( tìm y,z tương tự
Bài 1:
a) Ta có: 3/x - 1 = 4/y - 2 = 5/z - 3 => x - 1/3 = y - 2/4 = z - 3/5 áp dụng ... =>x - 1 + y - 2 + z - 3/3 + 4 + 5 = x + y + z - 1 - 2 - 3/3 + 4 + 5 = 12/12 = 1 do x - 1/3 = 1 => x - 1 = 3 => x = 4 ( tìm y, z tương tự )
a; (\(x\) - 2)2.(\(x+1\)).(\(x\) - 4) < 0
(\(x-2\))2 ≥ 0 ∀\(x\); \(x+1\) = 0 ⇒ \(x=-1\); \(x-4\) = 0 ⇒ \(x=4\)
Lập bảng ta có:
\(x\) | - 1 4 |
\(x+1\) | - 0 + | + |
\(x-4\) | - | - 0 + |
(\(x-2\))2 | + | + | + |
(\(x-2\))2.(\(x+1\)).(\(x+4\)) | + 0 - 0 + |
Theo bảng trên ta có: -1 < \(x\) < 4
Vậy \(-1< x< 4\)
b; [\(x^2\).(\(x-3\)):(\(x-9\))] < 0
\(x-3=0\)⇒ \(x=3\); \(x-9\) = 0 ⇒ \(x=9\)
Lập bảng ta có:
\(x\) | 3 9 |
\(x-3\) | - 0 + | + |
\(x-9\) | - | - 0 + |
\(x^2\) | + | + | + |
\(x^2\)(\(x-3\)):(\(x-9\)) | + 0 - 0 + |
Theo bảng trên ta có: 3 < \(x\) < 9
Vậy 3 < \(x\) < 9
a) \(5+\frac{x}{4-x}=\frac{1}{2}\)
\(\frac{x}{4-x}=5-\frac{1}{2}=\frac{9}{2}\)
\(\Rightarrow2x=9\left(4-x\right)\)
\(\Rightarrow2x=36-9x\)
\(\Rightarrow11x=36\)
\(\Rightarrow x=\frac{36}{11}=3,\left(27\right)\)
b) \(\frac{3x-5}{x+4}=\frac{5}{2}\)
\(\Rightarrow2\left(3x-5\right)=5\left(x+4\right)\)
\(\Rightarrow6x-10=5x+20\)
\(\Rightarrow x=30\)
a ) x + 5/12 = -2/3
=> x = -2/3 - 5/12
=> x = -8/12 - 5/12
=> x = -13/12
b ) 4/5 + 3/4 : x = 1/2
=> 3/4 : x = 1/2 - 4/5
=> 3/4 : x = 5/10 - 8/10
=> 3/4 : x = -3/10
=> x = 3/4 : -3/10
=> x = -5/2
c ) x/2 + x/3 = 1/4
=> 3x/6 + 2x/6 = 1/4
=> ( 3x + 2x )/6 = 1/4
=> 5x/6 = 1/4
=> 20x/24 = 6/24
=> 20x = 6
=> x = 6 : 20
=> x = 0 , 3
Chúc bạn học giỏi !!!