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-15(21-3x)=-63
21-3x=(-63)-(-15)
21-3x= -48
3x=(-48)-21
3x=-27
x=-27:3
x=-9
$\Rightarrow 3^x(1+3+3^2+3^3)=1080$
$\Rightarrow 3^x.40=1080$
$\Rightarrow 3^x=27=3^3$
$\Rightarrow x=3$
\(5x\left(4+2\right)+3x=240\) \(\left(8x+x+63\right):11=9\)
\(20x+10x+3x=240\) \(8x+x+63=99\)
\(33x=240\) \(9x=36\)
\(x=\frac{240}{33}\) \(x=4\)
5.(4x + 2) + 3x = 240
20x + 10 + 3x = 240
23x + 10 = 240
23x = 240 - 10
23x = 230
x = 230 : 23 = 10
31.57.x - 57.14.x = 85.57
(1767 - 798 ).x = 4845
969 . x = 4845
x = 4845 : 969
x = 5
a)x+(x+1)+(x+2)+(x+3)+...+(x+99)+(x+100)=5555
=> 101x +5050 = 5555
=> 101x = 505
=> x = 505 : 101 = 5
Vậy, x = 5
b)1+2+3+4+...+x=820
=> ( x+1) x :2 = 820
=> (x+1)x = 1640
Mà 1640 = 40 . 41
=> x = 40 ( vì {x+1} - x = 1)
Vậy, x = 40
c) 3x+1 = 9.27=243
=> 3x+1 = 35
=>x + 1 = 5
=> x = 4
Vậy, x=4
d) x+2x+3x+...+99x+100x=15150
=> [( 100 + 1) x 100 :2 ] x = 15150
=> 5050x = 15150
=> x = 15150:5050 = 3
Vậy, x =3
e)(x+1)+(x+2)+(x+3)+...+(x+100)=205550
=> 100x + 5050 = 205550
=> 100x = 205550 - 5050= 200500
=> x = 200500 : 100 = 2005
Vậy, x = 2005
f)3x+3x+1+3x+2=351
=> 3x + 3x . 3 + 3x x 9 = 351
=> 3x ( 1+3+9) = 351
=> 3x . 13 = 351
=> 3x = 351 :13=27 mà 27 = 33
=> x=3
Vậy, x=3
a) 3x – 15 = 25 – 5x
=> 3x + 5x = 25 + 15
=> 8x = 40
=> x = 5
b) 3x - 17 = 2x – 7
=> 3x - 2x = -7 + 17
=> x = 10
c) 2x – 17 = – (3x – 18)
=> 2x - 17 = -3x + 18
=> 2x + 3x = 18 + 17
=> 5x = 35
=> x = 7
d) 3x – 14 = 2(x – 9) + 1
=> 3x - 14 = 2x - 18 + 1
=> 3x - 2x = -18 + 1 + 14
=> x = -3
f) (x – 5)2 = 9
\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
a) Ta có: \(3x-15=25-5x\)
\(\Leftrightarrow3x-15-25+5x=0\)
\(\Leftrightarrow8x-40=0\)
\(\Leftrightarrow8x=40\)
hay x=5
Vậy: x=5
b) Ta có: \(3x-17=2x-7\)
\(\Leftrightarrow3x-17-2x+7=0\)
\(\Leftrightarrow x-10=0\)
hay x=10
Vậy: x=10
c) Ta có: \(2x-17=-\left(3x-18\right)\)
\(\Leftrightarrow2x-17=-3x+18\)
\(\Leftrightarrow2x-17+3x-18=0\)
\(\Leftrightarrow5x-35=0\)
\(\Leftrightarrow5x=35\)
hay x=7
Vậy: x=7
d) Ta có: \(3x-14=2\left(x-9\right)+1\)
\(\Leftrightarrow3x-14=2x-18+1\)
\(\Leftrightarrow3x-14-2x+18-1=0\)
\(\Leftrightarrow x+3=0\)
\(\Leftrightarrow x=-3\)
Vậy: x=-3
f) Ta có: \(\left(x-5\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{2;8\right\}\)
a: =>4/3x=1/2
hay x=1/2:4/3=3/8
b: =>-3(2-3x)=4(x+1)
=>-6+9x=4x+4
=>5x=10
hay x=2
a: =>4/3x=1/2
hay x=1/2:4/3=3/8
b: =>-3(2-3x)=4(x+1)
=>-6+9x=4x+4
=>5x=10
hay x=2
3x + 2 - 3x + 1 + 3x = 63
<=> 7 . 3x = 63
<=> 3x = 63 : 7
<=> 3x = 9
<=> 3x = 32
=> x = 2
\(3^{x+2}-3^{x+1}+3^x=63\)
\(\Rightarrow3^x\left(3^2-3+1\right)=63\)
\(\Rightarrow3^x.7=63\)
\(\Rightarrow3^x=63:7=9\)
\(\Rightarrow3^x=9=3^2\)
\(\Rightarrow x=2\)