![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-y}{x+2y}=\frac{3}{4}\)
4(x - y) = 3(x + 2y)
4x - 4y = 3x + 6y
4x - 3x = 6y + 4y
x = 10y
\(\frac{x}{y}=\frac{10}{1}\)
\(\frac{x-y}{x+2y}=\frac{3}{4}\)
\(\Leftrightarrow4\left(x-y\right)=3\left(x+2y\right)\)
\(\Leftrightarrow4x-4y=3x+6y\)
\(\Leftrightarrow x=10y\)
\(\Leftrightarrow\frac{x}{y}=10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(\frac{x+2y}{22}=\frac{x-2y}{14}\Rightarrow\frac{x+2y}{x-2y}=\frac{22}{14}=\frac{11}{7}\)
\(\Rightarrow7\left(x+2y\right)=11\left(x-2y\right)\)
\(\Rightarrow7x+14y=11x-22y\)
\(\Rightarrow14y+22y=11x-7x\)
\(\Rightarrow36y=4x\Rightarrow\frac{x}{y}=\frac{36}{4}=9\)
b) Ta có: \(\frac{x}{y}=9\Rightarrow\frac{x}{9}=\frac{y}{1}\Rightarrow\frac{x^2}{81}=\frac{y^2}{1}\)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\frac{x^2}{81}=\frac{y^2}{1}=\frac{x^2+y^2}{81+1}=\frac{82}{82}=1\)
\(\Rightarrow\frac{x^2}{81}=1\Rightarrow x^2=81\Rightarrow\orbr{\begin{cases}x=81\\x=-81\end{cases}}\)
\(\frac{y^2}{1}=1\Rightarrow y^2=1\Rightarrow\orbr{\begin{cases}y=1\\y=-1\end{cases}}\)
Vậy .................
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-y}{x+2y}=\frac{3}{4}\)
=> 4x - 4y = 3x + 6y
=> x = 10y
=> \(\frac{x}{y}=\frac{1}{10}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\frac{x}{3}=\frac{y}{4}\Rightarrow\frac{5x}{15}=\frac{2y}{8}=\frac{5x-2y}{15-8}=\frac{28}{7}=4\)
=> x = 4.3 = 12
y = 4.4 = 16
b, \(x:2=y:\left(-5\right)\Rightarrow\frac{x}{2}=\frac{y}{-5}=\frac{x-y}{2-\left(-5\right)}=\frac{-7}{7}=-1\)
=> x = (-1).2 = -2
y = (-1)(-5) = 5
c, \(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{8}=\frac{y}{12}\)
\(\frac{y}{4}=\frac{z}{5}\Rightarrow\frac{y}{12}=\frac{z}{15}\)
\(\Rightarrow\frac{x}{8}=\frac{y}{12}=\frac{z}{15}=\frac{x+y-z}{8+12-10}=\frac{10}{10}=1\)
=> x = 8
y =12
z = 15
![](https://rs.olm.vn/images/avt/0.png?1311)
Đề sai nha pn phải là x^2+y^2=82
a) Ta có: \(\frac{X+2Y}{22}\)=\(\frac{X-2Y}{14}\)
=> 14(x+2y)=22(x-2y)
=>14x+28y=22x-44y
=>72y-8x=0
=>72x=8x
=>9y=x
=>\(\frac{X}{Y}\)=9
Vậy tỉ số \(\frac{X}{Y}\)=9
b) Mk ko bít làm nhé.
Nhớ K nha
ai giải tiếp giúp mình với
Theo đề ta có : \(\frac{2y-x}{x+y}=\frac{2}{3}\)
\(\Rightarrow\left(2y-x\right)3=\left(x+y\right)2\)
\(\Rightarrow6y-3x=2x+2y\)
\(\Rightarrow6y-2y=2x+3x\)
\(\Rightarrow4y=5x\)
\(\Rightarrow\frac{x}{y}=\frac{4}{5}\)
Can you k for me,Shiro Suu!