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Ta phân tích :13=2+3+4
=> 1/2+1/3+1/4=13/12.
=> Ta có : 1/2016-x=1/2
=> Ta có 2016-x=2 =>x=2014
Hãy tích cho tui đi
vì câu này dễ mặc dù tui ko biết làm
Yên tâm khi bạn tích cho tui
Tui sẽ ko tích lại bạn đâu
THANKS
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1-x}{2015}+\frac{2-x}{1007}+\frac{3-x}{671}=\frac{1992-x}{4}\)
\(\left(\frac{1-x}{2015}+1\right)+\left(\frac{2-x}{1007}+2\right)+\left(\frac{3-x}{671}+3\right)=\frac{1992-x}{4}+6\)
\(\left(\frac{2016-x}{2015}+\frac{2016-x}{1007}+\frac{2016-x}{671}\right)=\frac{2016-x}{4}\)
\(\Leftrightarrow\left(2016×x\right)×\left(\frac{1}{2015}+\frac{1}{1007}+\frac{1}{671}-\frac{1}{4}\right)=0\)
Vì\(\frac{1}{2015}+\frac{1}{1007}+\frac{1}{671}-\frac{1}{4}\ne0\)
\(\Rightarrow2016-x=0\)
\(\Rightarrow x=2016\)
Chúc bạn học tốt!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1\frac{1}{5}\cdot1\frac{1}{6}\cdot...\cdot1\frac{1}{2014}=x\)
\(\frac{6}{5}\cdot\frac{7}{6}\cdot...\cdot\frac{2015}{2014}=x\)
\(\frac{6\cdot7\cdot...\cdot2015}{5\cdot6\cdot...\cdot2014}=x\)
\(\frac{2015}{5}=x\)
\(2015:5=x\)
\(403=x\)
Vậy : \(x=403\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{6}.\frac{1}{3}+\frac{17}{6}.\frac{1}{3}+\frac{2015}{2016}-1\)
\(=\frac{1}{3}\left(\frac{1}{6}+\frac{17}{6}\right)+\frac{2015}{2016}-1\)
\(=\frac{1}{3}.3+\frac{2015}{2016}-1\)
\(=1-1+\frac{2015}{2016}=\frac{2015}{2016}\)
\(\frac{1}{6}\times\frac{1}{3}+\frac{17}{6}\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=\left(\frac{1}{6}+\frac{17}{6}\right)\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=3\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=1+\frac{2015}{2016}-1\)
\(=0+\frac{2015}{2016}=\frac{2015}{2016}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)....\left(1-\frac{1}{2015}\right)\)
\(=\left(\frac{2-1}{2}\right)\left(\frac{3-1}{3}\right)\left(\frac{4-1}{4}\right)....\left(\frac{2015-1}{2015}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{2013}{2014}.\frac{2014}{2015}\)
\(=\frac{1}{2015}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\frac{6}{5}.\frac{7}{6}.\frac{8}{7}............\frac{2015}{2014}=\frac{2015}{5}=403\)
=> \(\frac{6}{5}.\frac{7}{6}.\frac{8}{7}...\frac{2014}{2013}.\frac{2015}{2014}=x\)
=> \(\frac{6.7.8.9...2014.2015}{5.6.7.8...2013.2014}=x\)
=> \(x=\frac{2015}{5}=403\)