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\(3^{x+4}-3^{x+1}=2106\)
=> \(3^{x+1+3}-3^{x +1}=2106\)
=> \(3^{x+1}.\left(3^3-1\right)=2106\)
=> \(3^{x+1}.26=2106\)
=> \(3^{x+1}=2106:26\)
=> \(3^{x+1}=81\)
=> \(3^{x+1}=3^4\)
=> x + 1 = 4
=> x = 4 - 1
=> x = 3.
Ta có: \(-\frac{8}{15}< \frac{x}{40}\le-\frac{7}{15}\)
\(\Leftrightarrow-\frac{8.8}{15.8}< \frac{3x}{40.3}\le\frac{-7.8}{15.8}\)
\(\Leftrightarrow-\frac{64}{120}< \frac{3x}{120}\le-\frac{56}{120}\)
=> 3x từ -56 đến -63
=> 3x = -57 ; -60 ; -63
=> x = -19 ; -20 ; -21
3200 = 32.100= ( 32)100
2300 = 23.100 = (23)100
Vì 32 > 23 nên (32)100 > ( 23)100 hay 3200> 2300
1) \(3^{200}=\left(3^2\right)^{100}=9^{100}\)
\(2^{300}=\left(2^3\right)^{100}=8^{100}\)
Do 9^100 > 8^100 => 3^200 > 2^300
2) 4x+3 - 3.4x+1= 13.411
4x+1.42 - 3.4x+1= 13.411
4x+1 ( 42 - 3) = 13.411
4x+1 . 13 = 13. 411
4x+1 = 411
=> x + 1 = 11
=> x= 10
ta có : \(\frac{y}{-78}=\frac{-y}{78};\frac{7}{-6}=\frac{-7}{6}\)
\(\frac{-y}{78}=\frac{-7}{6}\)
=> ( -y ) . 6 = ( -7 ) . 78
=> -y = \(\frac{\left(-7\right).78}{6}=-91\)
=> y = 91
\(\frac{x}{102}=\frac{-91}{78}\)
=> x . 78 = ( -91 ) . 102
=> x = \(\frac{\left(-91\right).102}{78}=-119\)
vậy x = -119 ; y = 91
Theo đề ta có: \(x=\frac{102.7}{-6}=\frac{714}{-6}=-119\)
\(y=\frac{-78.7}{-6}=\frac{-546}{-6}=91\)
Vậy \(x=-119;y=91\)
\(\frac{x}{2}-\frac{2}{y}=\frac{1}{2}\)
\(\frac{2}{y}=\frac{x}{2}-\frac{1}{2}=\frac{x-1}{2}\)
=>y(x-1)=2*2=4
| y | 1 | -1 | 2 | -2 | 4 | -4 |
| x-1 | 4 | -4 | 2 | -2 | 1 | -1 |
| x | 5 | -3 | 3 | -1 | 0 | -2 |
\(\frac{x}{2}-\frac{2}{y}=\frac{xy}{2y}-\frac{4}{2y}=\frac{xy-4}{2y}=\frac{1}{2}\)
=> (xy-4).2=2y
=>2xy-8=2y
=>2xy-2y=8
=>2y.(x-1)=8
Ta thấy: 8=1.8=-1.(-8)=2.4=-2.(-4)
Vì x,y ngưyên.
=>2y,x-1 nguyên.
Ta có bảng sau:
2y | -1 | -8 | 1 | 8 | -2 | -4 | 2 | 4 |
y | -1/2 | -4 | 1/2 | 4 | -1 | -2 | 1 | 2 |
x-1 | -8 | -1 | 8 | 1 | -4 | -2 | 4 | 2 |
x | -7 | 0 | 9 | 2 | -3 | -1 | 5 | 3 |
Vậy (x,y)=(-4,0),(4,2),(-1,-3),(-2,-1),(1,5),(2,3)
l-i-k-e cho mình nha bạn.
\(4^{x+3}-3.4^{x+1}=13.4^{11}\)
\(\Rightarrow4^{x+1}.\left(4^2-3\right)=13.4^{11}\)
\(\Rightarrow4^{x+1}.\left(16-3\right)=13.4^{11}\)
\(\Rightarrow4^{x+1}.13=13.4^{11}\)
\(\Rightarrow x+1=11\)
\(\Rightarrow x=11-1\)
\(\Rightarrow x=10\)
\(\Rightarrow4^x\left(4^3-3.4\right)=13.4^{11}\)
\(\Rightarrow4^x.52=13.4^{11}\)
\(\Rightarrow4^x=4^{\left(-1\right)}.4^{11}\)
\(\Rightarrow4^x=4^{10}\)
=> x=10