Question

[OoO Kún Chảnh OoO]

tim cac so x,y,z thoa man dang thuc :

\(\sqrt{\left(x-\sqrt{2}\right)^2}+\sqrt{\left(y+\sqrt{2}\right)^2}+Ix+y+zI=0\)

Answer 1

[Minh Hiền]

Ta có: \(\sqrt{\left(x-\sqrt{2}\right)^2}\ge0;\sqrt{\left(y+\sqrt{2}\right)^2}\ge0;\left|x+y+z\right|\ge0\)

Mà theo đề: \(\sqrt{\left(x-\sqrt{2}\right)^2}+\sqrt{\left(y+\sqrt{2}\right)^2}+\left|x+y+z\right|=0\)

=> \(\sqrt{\left(x-\sqrt{2}\right)^2}=\sqrt{\left(y+\sqrt{2}\right)^2}=\left|x+y+z\right|=0\)

=> \(x-\sqrt{2}=y+\sqrt{2}=x+y+z=0\)

=> \(x=\sqrt{2};y=-\sqrt{2};z=0\).