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a: \(\dfrac{-8}{15}=\dfrac{-2}{15}+\dfrac{-6}{15}\)
\(\dfrac{-8}{15}=\dfrac{-1}{15}+\dfrac{-7}{15}\)
\(\dfrac{-8}{15}=\dfrac{-4}{15}+\dfrac{-4}{15}\)
b: \(-\dfrac{8}{15}=\dfrac{17}{15}-\dfrac{25}{15}\)
\(\dfrac{-8}{15}=\dfrac{9}{15}-\dfrac{17}{15}\)
\(\dfrac{-8}{15}=\dfrac{10}{15}-\dfrac{18}{15}\)
Câu 1.
$\frac{1}{15}-\frac{9}{15}=\frac{-8}{15}$
$\frac{2}{15}-\frac{10}{15}=\frac{-8}{15}$
$\frac{3}{15}-\frac{11}{15}=\frac{-8}{15}$
Câu 2:
$\frac{-9}{15}+\frac{1}{15}=\frac{-8}{15}$
$\frac{-10}{15}+\frac{2}{15}=\frac{-8}{15}$
$\frac{-11}{15}+\frac{3}{15}=\frac{-8}{15}$
a) \(\dfrac{-7}{20}=\dfrac{1}{5}.\dfrac{-7}{4}\) b) \(\dfrac{-7}{20}=\dfrac{-7}{40}:\dfrac{1}{2}\) c) \(\dfrac{-7}{20}=\dfrac{2}{5}+\dfrac{-3}{4}\) d) \(\dfrac{-7}{20}=\dfrac{-1}{5}+\dfrac{-3}{20}\)
a)\(\dfrac{-7}{20}=\dfrac{-7}{10}\times\dfrac{1}{2}\)
b)\(\dfrac{-7}{20}=\dfrac{-7}{40}\times\dfrac{1}{2}\)
c)\(\dfrac{-7}{20}=\dfrac{7}{20}+\dfrac{-7}{10}\)
d)\(\dfrac{-7}{20}=\dfrac{-1}{5}+\dfrac{-3}{20}\)
a) \(\frac{7}{2}.\frac{-1}{10}\)
b)\(7:\left(-20\right)\)
c)\(\frac{7}{20}+\frac{-7}{10}\)
d)\(\frac{-1}{5}+\frac{-3}{20}\)
a, - \(\dfrac{11}{25}\) = \(\dfrac{-6}{25}\) + \(\dfrac{-5}{25}\) +
- \(\dfrac{11}{25}\) = \(\dfrac{-1}{25}\) + \(\dfrac{-10}{25}\) +
- \(\dfrac{11}{25}\) = \(\dfrac{-3}{25}\) + \(\dfrac{-8}{25}\) +
b, - \(\dfrac{11}{25}\) = \(\dfrac{6}{25}\) - \(\dfrac{17}{25}\)
- \(\dfrac{11}{25}\) = \(\dfrac{7}{25}\) - \(\dfrac{18}{25}\)
- \(\dfrac{11}{25}\) = \(\dfrac{8}{25}\) - \(\dfrac{19}{25}\)
− 11 25 = − 1 25 + − 6 25 ; − 11 25 = − 3 25 + − 8 25 ; − 11 25 = − 2 25 + − 9 25
a)\(\dfrac{-3}{15}+\dfrac{-5}{15}\)
b)\(\dfrac{4}{3}-\dfrac{4}{5}\)
c)\(-1+\dfrac{7}{15}\)
d)\(\dfrac{-1}{15}-\dfrac{7}{15}\)
a: \(\dfrac{-8}{15}=\dfrac{-6}{15}+\dfrac{-2}{15}\)
\(\dfrac{-8}{15}=\dfrac{-3}{15}+\dfrac{-5}{15}\)
\(\dfrac{-8}{15}=\dfrac{-1}{15}+\dfrac{-7}{15}\)
b: \(\dfrac{-8}{15}=\dfrac{16}{15}-\dfrac{24}{15}\)
\(\dfrac{-8}{15}=\dfrac{22}{15}-\dfrac{30}{15}\)
\(\dfrac{-8}{15}=\dfrac{9}{15}-\dfrac{17}{15}\)