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a, \(\frac{2}{3}-\frac{5}{3}\)
\(=\frac{2-5}{3}\)
\(=\frac{-3}{3}=-1\)
b, \(\left(4:\frac{4}{3}-\frac{1}{2}\right)x\)\(\frac{6}{5}\)\(-17\)
-> Tự làm,dễ mà?
\(6.\left(-\frac{1}{3}\right)^2-\frac{5}{4}:0,5+3\frac{1}{2}\)
\(=6.\frac{1}{9}-\frac{5}{4}.2+\frac{7}{2}\)
\(=\frac{2}{3}-\frac{5}{2}+\frac{7}{2}\)
\(=-\frac{11}{6}+\frac{7}{2}\)
\(=\frac{5}{3}\)
\(\frac{2017}{2018}.\frac{15}{17}-\frac{32}{17}.\frac{2017}{2018}=\frac{2017}{2018}.\left(\frac{15}{17}-\frac{32}{17}\right)\)
\(=\frac{2017}{2108}.\left(-1\right)=-\frac{2017}{2018}\)
A) \(A=\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}+\left(-\frac{1}{4}+\frac{1}{3}\right):\frac{5}{11}\)
\(A=-11.\frac{1}{12}:5+\frac{1}{3}-\frac{1}{4}:\frac{5}{11}\)
\(A=-\frac{11.\frac{1}{12}}{5}+\frac{11.\frac{1}{12}}{5}\)
\(\Rightarrow A=0\)
b) \(B=\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(3\frac{1}{2}-1\frac{1}{2}\right)\)
\(B=\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(\frac{7}{2}-\frac{4}{2}\right)\)
\(B=\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-2\)
\(B=3^2.\left(\frac{3}{4}-0,25\right)-2\)
\(B=4,5-2\)
\(\Rightarrow B=2\)
Lộn nha :v ở phần b) ấy, bạn sửa 4,5 - 2 = 2 thành 4,5 - 2 = 2,5 hộ mình nha
a/ \(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-\frac{32}{17}+\frac{14}{21}=\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{7}{21}+\frac{14}{21}\right)-\frac{32}{17}=1+1-\frac{32}{17}=\frac{2}{17}\)
Biến đổi :
\(\frac{125\cdot8^2}{30^6\cdot\left(-15\right)^2}=\frac{5^3\cdot\left(2^3\right)^2}{2^6\cdot3^6\cdot5^6\cdot3^2\cdot5^2}\)
\(=\frac{5^3\cdot2^6}{2^6\cdot3^8\cdot5^8}=\frac{1}{3^8\cdot5^5}\)
\(\Rightarrow\left(\frac{-2}{5}\right)^5:\left(\frac{125\cdot8^2}{30^6\cdot\left(-15\right)^2}\right)^2\)
\(=\frac{\left(-2\right)^5}{5^5}:\frac{1^2}{\left(3^8\cdot5^5\right)^2}\)
\(=\frac{\left(-2\right)^5\cdot3^{16}\cdot5^{10}}{5^5}\)
\(=\left(-2\right)^5\cdot3^{16}\cdot5^5\)
\(\left(-\frac{1}{2}+\frac{2}{3}\right)^2.\frac{6}{5}+\frac{3}{5}\)
\(=\frac{1}{36}.\frac{6}{5}+\frac{3}{5}\Rightarrow\frac{1}{30}+\frac{18}{30}=\frac{19}{30}\)