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a, 6^2 : 4 . 3 + 2 . 5^2
= 36 : 12 + 2 . 25
= 4 + 50
= 54
b, 5 . 4^2 - 18 : 3^2
= 5 . 16 - 18 : 9
= 80 - 2
= 78
a) \(6^2:4\cdot3+2\cdot5^2\)
\(=36:4\cdot3+2\cdot25\)
\(=9\cdot3+2\cdot25\)
\(=27+50\)
\(=77\)
\(77=7\cdot11\)
b) \(5\cdot4^2-18:3^2\)
\(=5\cdot16-18:9\)
\(=80-2\)
\(=78\)
\(78=2\cdot3\cdot13\)
toàn hỏi lung tung. lớp 6 mà còn ko biết làm mấy bài toán vớ vẩn kia
Thực hiện phép tính
a ) \(\frac{2}{5}+\frac{-1}{6}-\frac{3}{4}-\frac{-2}{3}\)
= \(\frac{2}{5}+\frac{-1}{6}+\frac{-3}{4}+\frac{2}{3}\)
= \(\left(\frac{2}{5}+\frac{-3}{4}\right)+\left(\frac{-1}{6}+\frac{2}{3}\right)\)
= \(\left(\frac{8}{20}+\frac{-15}{20}\right)+\left(\frac{-1}{6}+\frac{4}{6}\right)\)
= \(\left(\frac{8+\left(-15\right)}{20}\right)+\left(\frac{\left(-1\right)+4}{6}\right)\)
= \(\frac{-7}{20}+\frac{1}{2}\)
= \(\frac{-7}{20}+\frac{10}{20}=\frac{\left(7\right)+10}{20}=\frac{3}{20}\)
tk mk nha
đang âm rất nhiều rồi , giúp nha !!!!!
B1a)\(11\frac34-\left(6\frac56-4\frac12\right)+1\frac23\)
=\(11\frac34-6\frac56+4\frac12+1\frac23\)
=\(\left(11-6+4+1\right)+\left(\frac34-\frac56+\frac12+\frac23\right)\)
=\(10+\left(\frac{9}{12}-\frac{10}{12}+\frac{6}{12}+\frac{8}{12}\right)\)
=\(10+\left(-\frac{1}{12}+\frac{6}{12}+\frac{8}{12}\right)\)
=10+\(\frac{13}{12}\)
=\(\frac{120}{12}+\frac{13}{12}\)
=\(\frac{133}{12}\)
b)\(2\frac{17}{20}-1\frac{11}{5}+6\frac{9}{20}:3\)
= \(\frac{57}{20}-\frac{16}{5}+\frac{129}{20}\times\frac13\)
=\(\frac{57}{20}-\frac{16}{5}+\frac{129}{60}\)
=\(\frac{171}{60}-\frac{192}{60}+\frac{129}{60}\)
=\(\frac{108}{60}\)
=\(\frac95\)
a) 2011 + 5[300 - (17 - 7)2 ]
= 2011 + 5[300 - 100]
= 2011 + 5.200
= 2011 + 1000
= 3011
b) 695 - [200 + (11 - 1)2 ]
= 695 - [200 + 100]
= 695 - 300
= 395
c) 129 - 5[29 - (6-1)2 ]
= 129 - 5[29 - 25]
= 129 - 5 . 4
= 129 - 20
= 109
d) 2345 - 1000 : [19 - 2(21-18)2 ]
= 2345 - 1000 : [19 - 2 . 9]
= 2345 - 1000 : 1
= 2345 - 1000
= 1345
a, 2011+5 [300-(17-7)2 ] =2011+5[300-102]
=2011+5[300-100]=2011+5.200
=2011+1000=3011
b, 695-[200+(11-1)2]=695-[200+102]
=695-[200+100]=695-300=395
\(\frac37+\frac{5}{13}+\frac{4}{13}\)
=\(\frac37+\left(\frac{5}{13}+\frac{4}{13}\right)\)
=\(\frac37+\frac{9}{13}\)
=\(\frac{39}{91}+\frac{63}{91}\)
=\(\frac{102}{91}\)
\(\left(\frac38+\frac{-3}{4}+\frac{7}{12}\right):\frac56+\frac12\)
=\(\left(\frac{9}{24}+\frac{-18}{24}+\frac{7}{24}\right)\times\frac65+\frac12\)
=\(\frac{5}{24}\times\frac65+\frac12\)
=\(\frac14+\frac12\)
=\(\frac14+\frac24\)
=\(\frac34\)
a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)
=1
b)=(1.2.3....8).(9-1-8)
=(1.2.3....8).0
=0
mik chỉ giải được zậy thôi.
t mik nha.
(1000+1):11=1001:11=91=7.13
142+52+22=196+25+4=225=32.52
29.31+144:122=899+144:144=899+1=900=22.32.52
333:3+225:152=111+225:225=111+1=112=24.7
ĐÚNG THÌ
KHÔNG ĐÚNG THÌ KHÔNG SAO
a)(1000+1):11
=1001:11
=91
=7x13
b)=\(14^2+5^2+2^2\)
=196+25+4
=196+4+25
=200+25
=225
=\(3^2\times5^2\)
c)29.31+144:\(12^2\)
=899+144:144
=899+1
=900
=\(2^2\times3^2\times5^2\)
d)333:3+225:\(15^2\)
=111+225:225
=111+1
=112
=\(2^4\times7\)
a) (1000 + 1) :11 = 91 = 7 . 13,
b) 142 + 52 + 22 = 225 = 32 .52
c) 29.31 + 144 : 122 = 900 = 22. 32 . 52
d) 333: 3 + 225 : 152 = 112 =24 . 7